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Need help figuring out C++ Pointers
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I am supposed to figure out what the output produced would be from this equation..can anyone help me and explain it to me
char var1='s';
char var2='x';
char *ptr1, *ptr2;
ptr1=&var2;
*ptr2=*ptr1;
cout << *ptr1 << " " < var2 << endl;
char var1='s';
char var2='x';
char *ptr1, *ptr2;
ptr1=&var2;
*ptr2=*ptr1;
cout << *ptr1 << " " < var2 << endl;
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Join Date: Apr 2004
Posts: 4,342
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Behavior is undefined since ptr2 does not point anywhere.
"One of the methods used by statists to destroy capitalism consists in establishing controls that tie a given industry hand and foot, making it unable to solve its problems, then declaring that freedom has failed and stronger controls are necessary." --Ayn Rand
Sorry i missed a line when i typed it in..could you take another look now..
char var1='s';
char var2='x';
char *ptr1, *ptr2;
ptr1=&var1;
ptr2=&var2;
*ptr2=*ptr1;
cout << *ptr1 << " " << var2 << endl;
char var1='s';
char var2='x';
char *ptr1, *ptr2;
ptr1=&var1;
ptr2=&var2;
*ptr2=*ptr1;
cout << *ptr1 << " " << var2 << endl;
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Join Date: Apr 2004
Posts: 4,342
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Solved Threads: 237
Did you try compiling it and running it?
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s s
"One of the methods used by statists to destroy capitalism consists in establishing controls that tie a given industry hand and foot, making it unable to solve its problems, then declaring that freedom has failed and stronger controls are necessary." --Ayn Rand
The code you given has some error, are you sure you are giving the right code?
Anyway, the output should be:
x x
cause ptr1 has been assigned to the address of var2. When you output the value of *ptr1, it will refer to the value of that address.
Anyway, the output should be:
x x
cause ptr1 has been assigned to the address of var2. When you output the value of *ptr1, it will refer to the value of that address.
i need to know the data types of variables such as:
double var1, *ptr1, *ptr2;
float *ptr3;
int var2, *var4....do you know anything about data types?
double var1, *ptr1, *ptr2;
float *ptr3;
int var2, *var4....do you know anything about data types?
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Join Date: Apr 2004
Posts: 4,342
Reputation:
Solved Threads: 237
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Originally Posted by hail2dthief
The code you given has some error, are you sure you are giving the right code?
Anyway, the output should be:
x x
cause ptr1 has been assigned to the address of var2. When you output the value of *ptr1, it will refer to the value of that address.
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Originally Posted by hfick
i need to know the data types of variables such as:
double var1, *ptr1, *ptr2;
float *ptr3;
int var2, *var4....do you know anything about data types?
"One of the methods used by statists to destroy capitalism consists in establishing controls that tie a given industry hand and foot, making it unable to solve its problems, then declaring that freedom has failed and stronger controls are necessary." --Ayn Rand
the next question asks says i am supposed to state the data type of each variable...
double var1, *ptr1, *ptr2;
float *ptr3;
int var2, *var4
double var1, *ptr1, *ptr2;
float *ptr3;
int var2, *var4
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Join Date: Apr 2004
Posts: 4,342
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var1 is a double
ptr1 is a pointer to double
...you should be able to handle it from here.
ptr1 is a pointer to double
...you should be able to handle it from here.
"One of the methods used by statists to destroy capitalism consists in establishing controls that tie a given industry hand and foot, making it unable to solve its problems, then declaring that freedom has failed and stronger controls are necessary." --Ayn Rand
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