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Hi, Please I have a problem inserting record to mysql database, it always shows this error " Warning: mysqli_query() expects parameter 1 to be mysqli, null given in C:\wamp\www" here is my code <?php if(isset($_POST['submit'])){ $member_dat1=$_POST['member_first']; $member_dat2=$_POST['member_lastname']; $member_dat3=$_POST['sex']; $member_dat4=$_POST['member_type']; $member_dat5=$_POST['m_email1']; $member_dat6=$_POST['m_phone1']; $member_dat7=$_POST['m_address1']; $member_dat8=$_POST['m_address2']; $member_dat9=$_POST['city']; $member_dat10=$_POST['state']; $member_dat11=$_POST['added_by']; $member_insert= "INSERT INTO members(member_first,member_lastname,sex,member_type,m_address1,m_address2,city,state,m_phone1,m_email1,added_by)" … 
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Hello, Please as at this morning everything was fine, but all of a sudden all data record wiped off from 3tables in my database, now my client can't find records. Am using MYSQL, Visual Basic. Thanks. 
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Please I have a project that looks like this http://www.businessdictionary.com/ , whereby i can create a search field which search for every topic/word in my database and displays it on a page like you have it on the url above. I would appreciate if anyone can help with this. Thanks. 
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How do I fetch data from table into dropdown menu in mysql and post back to another table? What I want is to create a registration form for customers and attach an agent to each customer, the agent names are stored in a table and i need to post agent …
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