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here if i click the Generate Employee Id button it should generate the random number in input textfield and then that button should hide after generate the id. how to do that? but, i can automatically generate the random number in input textfiled without the button. that code is below …

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i want to upload the employee profile picture into mysql database using php. i tried this coding. image uploaded successful but when i fetch that image on browser it shows me text character like this (ÿØÿàJFIF


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1r). one more problem is below 20kb size images only uploaded into mysql. how to …

Here, i'm trying to fetch the image from database. In my database i can see a image file size ([BLOB - 62.3 KiB]). But, it didn't work. i didn't get any error here. i'm confused where i made a mistake here? <?php include('config.php'); ini_set('display_errors', '1'); error_reporting(E_ALL); try { $stmt = …

Recently i've rewritten my code to PDO from mysql query. Insert, fetch, update, delete everything working fine. But, pagination not displaying in my page. Before i've used mysql query. In that time pagination worked perfectly. Now, i've changed my codes into prepared statements. pagination not dispalying i don't know what …

 look at this image. when i send this page via email it shows the php code. it does not fetch the details from mysql and then i'm fetching the mysql records based on the particular voucher id. how to send mysql fetch records page via email?

<form action="searchdetail.php" method="post"> SEARCH BY: <select name="searchby"> <option value="gname">Guest Name</option> <option value="city">Guest City</option> </select> <input name="query" type="text" /> <input name="subval" type="submit" value="Search" /> </form> and searchdetail.php include("config.php"); if(isset($_POST['subval'])) { $query = mysql_real_escape_string(trim($_POST['query'])); $sql = mysql_query ("SELECT * FROM voucher WHERE gname = '$query'"); echo "<table border=1 width=860 align=center cellsapcing=5 cellpadding=5>"; …

here i am store the dynamic row values into mysql. i am using jquery and javascript for dynamic rows and auto calculation and then stored to mysql using php coding. that works perfectly. i already added dynamic row value into mysql perfectly. But, now i want to edit the table …

edit.php coding... <?php $uid = (int)$_GET['id']; ?> <form action="update.php" name="myform" method="post" onsubmit="return(validateform());"> <input type="hidden" name="edited" value="<?=$uid;?>"> <?php $tariff_query = mysql_query("SELECT * FROM ebvouchertariffs WHERE VoucherID_Fk = $uid"); if(mysql_num_rows($tariff_query)>=1) { echo "<table width=960 align=center cellspacing=0 cellpadding=0> <tr> <td width=68 height=50 class=tabtext>SL.NO</td> <td width=106 class=tabtext>DATE</td> <td width=204 class=tabtext>PARTICULARS</td> <td width=117 class=tabtext>NO OF …

how to send an email from localhost xampp?? anyone give me a proper procedure... i'm confused.

<?php include("config.php"); if (isset($_POST['submit_val'])) { $cmeal = mysql_real_escape_string($_POST['meal']); $meal = "INSERT INTO ebmealplans( MealPlanName, CreatedOn ) VALUES ( '{$cmeal}', NOW() )"; if(!mysql_query($meal, $link)) { die("Error : " .mysql_error()); } $croom = mysql_real_escape_string($_POST['room']); $ref_key = mysql_insert_id(); $room = "INSERT INTO ebroomtypes( RoomTypeName, CreatedOn ) VALUES ( '{$croom}', NOW() )"; if(!mysql_query($room, $link)) …

index.php coding <td><input type="text" name="slno[]" value="" size="2"></td> <td><input type="text" size="10" name="date[]" id="SelectedDate" onClick="GetDate(this);" readonly="readonly"/></td> <td><input size="24" type="text" name="particulars[]" value="" placeholder="Description"></td> <td><select name="noofnights[]" value="0"> <option value="empty"></option> <option value="1">1</option> <option value="2">2</option> <option value="3">3</option> <option value="4">4</option> <option value="5">5</option> <option value="6">6</option> <option value="7">7</option> <option value="8">8</option> <option value="9">9</option> <option value="10">10</option> <option value="11">11</option> <option value="12">12</option> <option …

here i am trying to do calculation for javascript dynamic rows. i have done auto multiplication in few rows using this function . but i want to calculate the tax percentage. how can i do that? help.. <script src="http://code.jquery.com/jquery-1.6.4.min.js"></script> <script> var $k = jQuery.noConflict(); $k.fn.sum = function() { var sum …

I am using datepicker in my form for booking date field. when i pick a date it shown like this 11/13/2013 (MM/DD/YYYY). In mysql database i am using datetime Type. in mysql db always shows 0000-00-00 00:00:00. i want to change the date format. for example if i am choose …

 here i attached one image. look at this.if i selected the Guest Currency then automatically Guest Currency Value should shown in the next text box. how to do that? is there any javascript, jquery plugin? Guest Currency : <select name="gcurrency" tabindex="21"> <option value=""></option> <option> INR India Rupees </option> …

this is my html and javascript coding. how to do contenteditable div onkeyup calculation. i tried it but i doesn't work... <td><div class="inputclass" id="quantity1" contenteditable> </div></td> <td><div class="inputclass" id="unitprice1" onkeyup="maths();" contenteditable> </div></td> <td><div class="inputclass" id="total1" contenteditable> </div></td> function maths() { var qt = document.getElementById("quantity1").value; var up = document.getElementById("unitprice1").value; qtup = …

This is my php & html code for show numbers in words. this works correctly `<input type="text" value="<?php include("number_words.php"); echo convert_number_to_words(123); ?>" size="70" readonly="readonly" />` this is my final total amount html code `<input type="text" name="totalamount" id="totalamount" size="8" readonly="readonly" />`. here i am doing convert numbers into words. but i …

please I want to know how to program

This is my javascript code. here i am trying to multiple two values in each row (totally 7 rows) and then doing addition operation at end of the table. its worked but problem is NaN. when i entered all fields then only it shows the final value. if user entered …

1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'NOT NULL, CreatedOn DATETIME NOT NULL, ModifiedOn DATETIME NOT NULL, `StartD' at line 1 CREATE TABLE `billing`.`ebUsers` ( `UserID` INT NOT NULL AUTO_INCREMENT …

here if user logged information is correct it should show the main page. in that mainpage right top corner i need to show the username, employee id, employee name. here i can get username correctly. but, i did not get employee id and employee name. for example : Name - …

this is my login page coding. my login form html coding and php coding is in same page. now if login successful it will redirect to mainpage.php and then if login failure it will show the error message on same page (login.php). how to do that? i tried something but …

in my project i'm using user input form. that form contains serial no, reference no, name, email, phone, address, etc.., in that user input form serial number textfield is readonly option. user can't able edit the serial number. in that textfield i want to show the next auto_increment id from …

this is my sendmsg coding page. Am i right? its not working. First i got fatal error: call undefined function curl_init(). i cleared that error. now it takes time to load 10 to 15 seconds and show error in that page. coding is below... $name = $_POST['name']; $connum = $_POST['connum']; …

i want if user select one value in combo box that value should store in db and then display what they are selected. for example if user select CONFIRM option that value stored in db after that it display CONFIRM instead of that combo box form and button. Here i …

Fatal error: Call to undefined function curl_init(). in my php.ini() file i removed the semi colon for extension=php_curl.dll and then restarted my xampp server. but its not worked. any idea?

in my db have 20+ columns. i added 19 columns throught input form and stored in db succesfully. i fetch few details from db in my main page. in my main page 1 more column is there. that is status column, it is a combo box. if i click status …

i stored few values through input form. (for example tax and rate field) if i entered tax = 777.77 and rate = 10000 it stored the details to db successfully. retrieve function also done successfully. but i want to show add these two values(tax+rate = total) from db when i …

i have the db with serial no and reference no. serial no is auto_increment value. it is worked perfectly. but i want ref no column also as auto_increment value start with 0000001,0000002,0000003...., how to do that? i cannot able to add two auto_increment values in mysql.

i created main.php page. this page includes these following php codes, <?php $user = ""; $pass = ""; $db = ""; $connect = mysql_connect("", $user, $pass); if(!$connect) { die ("Could not connect to MySQL"); } mysql_select_db($db, $connect) or die ("Could not open $db: " .mysql_error()); $sql = mysql_query ( "SELECT …