Posts by phani1092 which have been Voted Down

Try compiling the above code in

www.codepad.org

#include <stdio.h>

int main(void)
{
    int arr[2][2][2]={1,2,3,4,5,6,7,8};
    int *p = arr;

    printf("%d", *p);

    return 0;
}

Try compiling this you will get what i am talking about. 

you all are making things complex. Here's the simplest way of doing

int num;
printf("enter any five digit num \n");
scanf("%d",&num);
len=findoutlength(num);
while(len>0)
{
  d=num%10;
  if(d==0)
  {
  printf("digit %d is 0",d);
  }
  else if(d%2==0)
  {
  printf("digit %d is even",d);
  }
  else
  {
  printf("digit %d is odd",d);
  }
  len--;
}  

I guess this will give you the desired output.

Now deceptikon, nitin1 asked about the first element of the array and for first element there is no need to type cast,if it would have been necessary the compiler would have thrown definite error.

In array pointers, when you are not specifying any index of the array it takes the first position as default. Unless untill you give specific index to the array,it returns the value of first index pointer. You would get the same output if you typecast or not.

In array pointers, when you are not specifying any index of the array it takes the first position as default. Unless untill you give specific index to the array,it returns the value of first index p

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