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Member Avatar for edensigauke

I want to know what method to use to view Images from my MYSQL database using PHP. i know that for basic data it is getString(). what about for images?

Member Avatar for edensigauke
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Member Avatar for gilgil2

Hi I have two Mysql tables, one with the information in and another with payment information in. I want to echo the results that have paid first and then the rest of the results. If information has no payment associated with it it does not appear in the payment table. …

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Member Avatar for adishardis

Hi, I'm sorry if this is answered already but I'm such a newbie at programming that I apperantly can't formulate my problem to find an answer! :-/ Here goes: I have a table filled with data. I want a user to be able to select via a dropdown list what …

Member Avatar for adishardis
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218
Member Avatar for BadManSam

I want to create a grey login bar at the top of my page but I don't know how to make one please could someone help. The code that I want in the login bar is <table> <tr><td> <?php if($session->logged_in){ echo "Welcome <b>$session->username</b>, you are logged in. <br><br>" ."[<a href=\"userinfo.php?user=$session->username\">My …

Member Avatar for code739
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Member Avatar for intelgy

[B]Hello everyone, I'm new to PHP and creating an advertising website for massage therapists. On the profile page I'm creating a button so anyone can click on to send the advertiser an email. I created a page called profile_sendemail.php which contains the form to send the email and here is …

Member Avatar for the_traveller
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Member Avatar for bangla

[CODE]<?php $con = mysql_connect("bangla123.db.8390659.hostedresource.com","bangla123","Algnab123%"); if (!$con) { die('Could not connect: ' . mysql_error()); } if (mysql_query("CREATE DATABASE tryDB",$con)) { echo "Database created"; } else { echo "Error creating database: " . mysql_error(); } mysql_close($con); ?> [/CODE] ------------ When I run the code, i get error -"Error creating database:.... Pls advise. …

Member Avatar for divyakrishnan
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Member Avatar for asif49

This code seems to work on a simpler level but not on the one I'm trying to use. It's for a website's search engine. First the result is gotten from the database like so: [CODE] $query = "select * from $tbl_name where name like \"%$var%\" OR text like \"%$var%\""; $numresults=mysql_query($query); …

Member Avatar for the_traveller
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