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Hi

I have some script that I have used for sometime so understand it is out of date code, but it works. I want to amend it so that it also checks a field user_type and on successful login directs each to a differnt page. The code at the moment takes username and password from a login page, checks it (code below) and either takes user to a main page if correct or tells them username or password is wrong.

<?php require_once('Connections/Connection1.php'); ?>

<?php
$tbl_name="users"; // Table name 



// Connect to server and select databse.
//mysql_connect("$host", "$username", "$password")or die("cannot connect"); 
//mysql_select_db("$db_name")or die("cannot select DB");
mysql_select_db($database_Connection1, $Connection1);

// username and password sent from form 
$myusername=$_POST['myusername']; 
$mypassword=md5($_POST['mypassword']); 




// To protect MySQL injection (more detail about MySQL injection)
$myusername = stripslashes($myusername);
$mypassword = stripslashes($mypassword);
$myusername = mysql_real_escape_string($myusername);
$mypassword = mysql_real_escape_string($mypassword);

$sql="SELECT * FROM $tbl_name WHERE userid='$myusername' and 

password='$mypassword'";
$result=mysql_query($sql);


// Mysql_num_row is counting table row
$count=mysql_num_rows($result);

// If result matched $myusername and $mypassword, table row must be 1 row

if($count==1){

// Register $myusername, $mypassword and redirect to file "login_success.php"
session_register("myusername");
session_register("mypassword"); 
header("location:main.php?myusername=".$myusername);
}
else {
header("location:login_failed.php");
//echo "Wrong Username or Password";
}
?>

Any help would be very much appreciated!

If I have dropdownlist as below

<select onChange="this.value;">  
  <option value="Volvo" id="volvo">Volvo</option>    
  <option value="Saab" id="saab">Saab</option>    
  <option value="VW" id="vw">VW</option>    
  <option id="audi" value="Audi" selected>Audi</option>                  
</select> 

I want to display discription of item selectd so I have below code

<div id="boxpopup" class="box">  
    <a onClick="closeOffersDialog('boxpopup');" class="boxclose"></a>  
    <div id="content">  
    This is popupbox of Audi   
    </div><!--end of content --> 
</div><!--end of popupbox -->     

now in content can I give If else as below

    <div id="boxpopup3" class="box">  
        <a onClick="closeOffersDialog('boxpopup');" class="boxclose"></a>  
        <div id="content"> 
            <?php if($id=="volvo"){ ?> 
            This is popupbox of Volvo
            <?php } elseif($id=="saab"){ ?>
            This is popupbox of Saab 
            <?php } elseif($id=="vw"){ ?>
            This is popupbox of VW 
            <?php } else { ?>
            This is popupbox of Audi
            } ?>
        </div><!--end of content --> 
    </div><!--end of popupbox -->

The error is occurs
Notice: Undefined variable: id
please help me :(

Hi all,
I have taken from net drop down menu script
my web page is medistyle.az. It works perfectly
but when i look up code i cannot understand one thing there
below is code (js. file)

var menu=function(){
    var t=15,z=50,s=6,a;
    function dd(n){this.n=n; this.h=[]; this.c=[]}
    dd.prototype.init=function(p,c){
        a=c; var w=document.getElementById(p), s=w.getElementsByTagName('ul'), l=s.length, i=0;
        for(i;i<l;i++){
            var h=s[i].parentNode; this.h[i]=h; this.c[i]=s[i];
            h.onmouseover=new Function(this.n+'.st('+i+',true)');
            h.onmouseout=new Function(this.n+'.st('+i+')');
        }
    }
    dd.prototype.st=function(x,f){
        var c=this.c[x], h=this.h[x], p=h.getElementsByTagName('a')[0];
        clearInterval(c.t); c.style.overflow='hidden';
        if(f){
            p.className+=' '+a;
            if(!c.mh){c.style.display='block'; c.style.height=''; c.mh=c.offsetHeight; c.style.height=0}
            if(c.mh==c.offsetHeight){c.style.overflow='visible'}
            else{c.style.zIndex=z; z++; c.t=setInterval(function(){sl(c,1)},t)}
        }else{p.className=p.className.replace(a,''); c.t=setInterval(function(){sl(c,-1)},t)}
    }
    function sl(c,f){
        var h=c.offsetHeight;
        if((h<=0&&f!=1)||(h>=c.mh&&f==1)){
            if(f==1){c.style.filter=''; c.style.opacity=1; c.style.overflow='visible'}
            clearInterval(c.t); return
        }
        var d=(f==1)?Math.ceil((c.mh-h)/s):Math.ceil(h/s), o=h/c.mh;
        c.style.opacity=o; c.style.filter='alpha(opacity='+(o*100)+')';
        c.style.height=h+(d*f)+'px'
    }
    return{dd:dd}
}();

Here i dont understand what does return{dd:dd} mean. I understand dd is name of function(class) but i couldnt understand what does syntax mean (return{dd:dd})
Thanks in advance for attention !!!

Hi thanks for reply. This isn't jQuery it's a class I wrote myself. It's becuase I didn't define the ID in the <input > tags.

I really ought to read up on jQuery - looks like it might prove useful!