How to translate debugging?

[bd338]

Hello everyone!
When I go into the command prompt and type:

debug main.com

I get this in the console, when I type 'r':

AX=0000  BX=0000  CX=0041  DX=0000  SP=FFFE  BP=0000  SI=0000  DI=0000
DS=1549  ES=1549  SS=1549  CS=1549  IP=0100   NV UP EI PL NZ NA PO NC
1549:0100 E91000        JMP     0113

And this when I type 'd':

1549:0100  E9 10 00 41 58 20 3D 20-37 0D 0A 24 42 58 20 3D   ...AX = 7..$BX =
1549:0110  20 35 24 B8 05 00 BB 07-00 50 53 58 5B 3D 07 00    5$......PSX[=..
1549:0120  74 00 B4 09 BA 03 01 CD-21 83 FB 05 74 00 B4 09   t.......!...t...
1549:0130  BA 0C 01 CD 21 B4 08 CD-21 E9 00 00 B8 00 4C CD   ....!...!.....L.
1549:0140  21 3A 75 01 46 E8 36 00-8A 46 00 84 C0 79 DD F6   !:u.F.6..F...y..
1549:0150  46 05 04 75 D7 3C FE 88-E0 88 46 00 72 D1 E8 A1   F..u.<....F.r...
1549:0160  C4 EB CC 3D 01 90 3E 01-A0 3F 01 B0 40 01 C0 41   ...=..>..?..@..A
1549:0170  01 D0 42 01 BD 45 01 8D-3C 01 8D 09 01 8D E8 69   ..B..E..<......i

How can I translate the two above outputs, from this source code:

jmp executor

axSeven db "AX = 7", 0dh, 0ah, "$"
bxFive db "BX = 5", "$"

executor:
    mov ax, 0005h
    mov bx, 0007h
    push ax
    push bx
    pop ax
    pop bx
    cmp ax, 0007h
    jz axIsSeven
axIsSeven:
    mov ah, 0009h
    lea dx, axSeven
    int 0021h
    cmp bx, 0005h
    jz bxIsFive
bxIsFive:
    mov ah, 0009h
    lea dx, bxFive
    int 0021h
    mov ah, 0008h
    int 0021h
    jmp exit
exit:
    mov ax, 4c00h
    int 0021h
end executor

Problem: I don't understand the outputs, so I need to learn how to "read" them :).

Best regards,
Benjamin.