DaniWeb IT Discussion Community - PHP

Deleting from an array

dhani09 — Fri, 24 May 2013 18:09:17 +0000

I have an array that looks like this:
Array ( [0] => Array ( [id] => 2 [name] => test product1 [description] => test [quantity] => 1 [price] => 188 [status] => Brand New [category] => Computer Software [subcategory] => Music Software [postdate] => 2013-05-19 [prodimage] => [user] => admin ) [1] => Array ( [id] => 2 [name] => test product1 [description] => test [quantity] => 1 [price] => 188 [status] => Brand New [category] => Computer Software [subcategory] => Music Software [postdate] => 2013-05-19 [prodimage] => [user] => admin )
I want to be able to delete an entire row e.g Array[0] which would mean deleting this;
Array ( [0] => Array ( [id] => 2 [name] => test product1 [description] => test [quantity] => 1 [price] => 188 [status] => Brand New [category] => Computer Software [subcategory] => Music Software [postdate] => 2013-05-19 [prodimage] => [user] => admin ).
I tried the following:

$delid = $_GET['delid']//the product id of the element on which DELETE link was clicked.
if($delid){
    $contents = count($_SESSION['cartItems']);//$_SESSION['cartItems'] is the array shown above.
    for($i=0; $i < $contents $i++){
        foreach($_SESSION['cartItems'] as $products){
        if($products['id'] == $delid){
            unset($products[$i]);
           }
        }
    }
}

But it doesn't delete the specified item form the array. Never implemented such a thing before so i'm a bit confused. How do i go about this? thanks

Get Values to var in Jquery

PF2G — Fri, 24 May 2013 15:29:36 +0000

Hi,

I'm creating a mentionInput, a textarea where i can identify people writing "@NAME" (like facebook)

I have a this js file where i tell the info of the names i can identify:

$(function () {

  $('textarea.mention').mentionsInput({
    onDataRequest:function (mode, query, callback) {
      var data = [
        { id:1, name:'Kenneth Auchenberg', 'avatar':'http://cdn0.4dots.com/i/customavatars/avatar7112_1.gif', 'type':'contact' },
        { id:2, name:'Jon Froda', 'avatar':'http://cdn0.4dots.com/i/customavatars/avatar7112_1.gif', 'type':'contact' },
        { id:3, name:'Anders Pollas', 'avatar':'http://cdn0.4dots.com/i/customavatars/avatar7112_1.gif', 'type':'contact' },
        { id:4, name:'Kasper Hulthin', 'avatar':'http://cdn0.4dots.com/i/customavatars/avatar7112_1.gif', 'type':'contact' },
        { id:5, name:'Andreas Haugstrup', 'avatar':'http://cdn0.4dots.com/i/customavatars/avatar7112_1.gif', 'type':'contact' },
        { id:6, name:'Pete Lacey', 'avatar':'http://cdn0.4dots.com/i/customavatars/avatar7112_1.gif', 'type':'contact' },
        { id:7, name:'kenneth@auchenberg.dk', 'avatar':'http://cdn0.4dots.com/i/customavatars/avatar7112_1.gif', 'type':'contact' },
        { id:8, name:'Pete Awesome Lacey', 'avatar':'http://cdn0.4dots.com/i/customavatars/avatar7112_1.gif', 'type':'contact' },
        { id:9, name:'Kenneth Hulthin', 'avatar':'http://cdn0.4dots.com/i/customavatars/avatar7112_1.gif', 'type':'contact' }
      ];

      data = _.filter(data, function(item) { return item.name.toLowerCase().indexOf(query.toLowerCase()) > -1 });

      callback.call(this, data);
    }
  });

  $('.get-syntax-text').click(function() {
    $('textarea.mention').mentionsInput('val', function(text) {
      alert(text);
    });
  });

  $('.get-mentions').click(function() {
    $('textarea.mention').mentionsInput('getMentions', function(data) {
      alert(JSON.stringify(data));
    });
  }) ;

});

But i want to get those values to my MySQL Table "Artists", how do i do that?

And than i want to insert some of those values in another table!

Can you help me?

Here's the index.php:




  jquery.mentionsInput

Thank you.

delete and upload images

dourvas — Fri, 24 May 2013 15:07:32 +0000

Hallo,

i ve made a script that uploads an image in a web site and then show that image (admin site). when i upload the file i rename it with a specific name. The user may delete the image he uploaded. Everything works fine. If he tries to upload another image (the rename takes place like mentioned) the pictured that shown is the first one!! the one he deleted a few minutes ago.

I used me ftp client to see if the first image deleted and it did. When i upload the second image (the same name as the first) the image appears but it is not the one i just uploaded but the one i ve just deleted.

Obviously is something the server does and i was wondering if i could stop it...

upon loading , form autosubmits empty fields to database

amkaos — Fri, 24 May 2013 13:40:05 +0000

this is link to code http://jsbin.com/ixupuk/4/edit
when my form is loaded into browser OR refreshed, all fields are auto-submitted to mysql database..
i included at the bottom, an if(isset) statement that i couldnt get to work.
thanx

embedding video on webpage

showman13 — Fri, 24 May 2013 12:54:18 +0000

Good Morning,

I'v been combing through the net including many links on this site, trying to get the necessary information to make a video play on my webpage. No Luck

I've tried multiple pieces of code to embed the video, but in each case I am faced with either a black screen or a note saying that a plugin is needed or No video with supported mime types found... But never a functioning playback of the video.

When I click on the link to install the necessary plug in, I get a message that it is an unknown plugin...

What I have is a .wmv

this is the webpage http://www.hctubs.com/syllent_vid.php

Here is the code that I currently have in place








http://www.microsoft.com/Windows/MediaPlayer/">

Any suggestions on making this work or on other alternatives that may be better would be greatly appreciated.

Do I need a different format video?

thanks in advance
Douglas

Ensuring that a daily cron keeps executing within a given range of dates

Webville312 — Fri, 24 May 2013 12:05:53 +0000

Hi,

I am working on a code that dispatches airtime depending on a schedule that is specified. Now all works just fine. The only problem is that the code executes only once.
To throw more light, here is how it is meant to work;
1. An administrator creates a schedule, specifying how frequently they want the airtime to be dispatched [working ok]
2. The cron runs on a daily basis to find which airtime to send

Currently, I have a field called airtime status, whose default value is 0. But after sending the airtime, then the statusis updated to 1.

Now the real challenge is that; if this status is set to 1, it means that the script will not send that airtime again; yet it is supposed to be sent daily.

Any suggestions as to how I can go about this?

PDF edit

davy_yg — Fri, 24 May 2013 10:45:36 +0000

Hello all,

this might not be related to php (I don't know which forum I should post this topic) so I thought may be someone could help me out.

How to edit pdf file ? Is there any specific software to edit adobe pdf file ?

I have tried adobe acrobat x yet I do not know how to do it nor how to use the software.

Anyone could help me give any further recommendation?

Thanks.

Login to direct user type to a different page

mdemetri2 — Fri, 24 May 2013 10:00:58 +0000

I have some script that I have used for sometime so understand it is out of date code, but it works. I want to amend it so that it also checks a field user_type and on successful login directs each to a differnt page. The code at the moment takes username and password from a login page, checks it (code below) and either takes user to a main page if correct or tells them username or password is wrong.

Any help would be very much appreciated!

for loop in php

shilu2 — Fri, 24 May 2013 08:56:27 +0000

If I have dropdownlist as below

I want to display discription of item selectd so I have below code

  
      
      
    This is popupbox of Audi

now in content can I give If else as below

      
          
         
             
            This is popupbox of Volvo
            
            This is popupbox of Saab 
            
            This is popupbox of VW 
            
            This is popupbox of Audi
            } ?>

The error is occurs
Notice: Undefined variable: id
please help me :(

compare $_GET with array existence

mjsmitten — Thu, 23 May 2013 23:49:27 +0000

If I have a array: $myarray = array("10"=>"apple", "20"=>"banana", etc..) up to 15 values. and I use $_GET['category'] to get my value from url for instance "10" How do I echo $myarray to be "apple"?

how to delete a token when cancel is clicked

php.coder — Thu, 23 May 2013 23:13:38 +0000

how can i get a token that a user has requested if he/she clicks cancel NOTE the user doesnt have to input anything if cancel is clicked that particular token is deleted from the d.b and the user is redirected to index.php i really dont know where and how to start so bear with me thanks anyway below is the token.php

Click here to go back to the HOME PAGE");}

$pass=$_POST['password'];
$email=$_SESSION['email'];

if(isset($_POST['password'])&&isset($_SESSION['email']))
{
$q="update registration set password='".md5($pass)."' where email='".$email."'";
$r=mysql_query($q);
if($r)mysql_query("update tokens set used=1 where token='".$token."'");echo "Your password is changed successfully  Click here to go back to the HOME PAGE";
if(!$r)echo "An error occurred";
    }

and below is the formreset.php

Forgot Password
      
        
          
            
               
              Password
              
              
              

            
                

                Your PASSWORD is need

              

            
               
              
Confirm Password
              
              
              
              
              

              
              

              Please re-confirm your PASSWORDThe PASSWORDS don't match.



    
       
      
        
          
          Cancel
          
        
      

    
    
      
         
         
      
    thanks in advance

so how do i go about this

if certain words are in url

mjsmitten — Thu, 23 May 2013 22:38:05 +0000

My url's are similar like this:

website/search/category,Room/region,Oregon/
website/search/category,Room/
website/search/category,Room/city,Palm Bay/
website/search/city,Palm Bay/
website/search/region,Florida/

It always contains single or combination of CATEGORY CITY REGION

I want to echo in an if statement, for example:
if url contains "category,xxx" then echo "category is xxx".
(xxx can be anything)

I found this code:

But this method is large when I have 12 or more category words, 50 region names, and hundreds of city words to compare. How to make this more easy?

form validation: php validates for email, but not database submissions

amkaos — Thu, 23 May 2013 16:26:05 +0000

Hi:
i have contact form that i thought the validation (.js + php) worked fine because i received emails
that were only submitted w/ all fields correctly filled in. i added submission to mysql database, then
found out that empty fields were being submitted to database -- but not email..
this is how validation behaves::

fill in name only == js blocks

fill in valid email only == js blocks

fill in bad email format == js doesnt block

fill in name + email wrong format == js blocks

fill in name + email correct format == js blocks

this link has both .js and php validation files..
http://jsbin.com/ixupuk/1/edit

i dont understand how validation would work for email but not database...
thanx for any help

confusing myself with arrays

bradly.spicer — Thu, 23 May 2013 13:52:30 +0000

hey guys,

I've been working on that moodle database link and I have it somewhat working!

I have it logging in and echoing the username. This is the login section:

  $query = "SELECT * FROM moodle_user WHERE username = '{$_POST['username']}' AND password = '$password'";
    $result = mysqli_query($con,$query) or die(mysqli_error($con));

    //setup row
    if ($_POST['submit']) {
        $Row = mysqli_fetch_assoc($result);
        $username = $_POST['username'];
        $firstname = $_Row['firstname'];
        $lastname = $_Row['lastname'];
        $name = print_r($_Row['firstname']);

    }





  ';
     echo 'Your name: ' . $firstname;
    } else {
     echo 'Not logged in';
     }
   ?>

The problem I am having is that the echo 'Your name: ' . $firstname;

isn't echoing anything. However I was able to echo the array earlier.

Get value of text box store in php array variable

giao.can — Thu, 23 May 2013 13:11:44 +0000

I have a table like code html belows
I want to store value of check box and corresponding text value into 2 array in PHP
For example
if i check box ID_1, ID_2
the values of these check box are stored in $array_box ( 74, 75)
and values of corresponding text box are stored in $array_text ("iOS","Android")
Do you have any idea? thank you very much

php not updating password nor token in the d.b

php.coder — Thu, 23 May 2013 11:39:44 +0000

My forgot password is not updating the token table nor is it updating the password when changes it keeps echoing the error message below is the form code:

Forgot Password
      
        
          
            
               
                Password
              

                
                
                Your password is required

            
               
                Confenter code hereirm Password
              
                
                
                A value is required.The values don't match.

and the reset.php is:

Click here to go back to the HOME PAGE");}

$pass=$_POST['password'];
$email=$_SESSION['email'];

if(isset($_POST['password'])&&isset($_SESSION['email']))
{
$q="update registration set password='".md5($pass)."' where email='".$email."'";
$r=mysql_query($q);
if($r)mysql_query("update tokens set used=1 where token='".$token."'");echo "Your password is changed successfully  Click here to go back to the HOME PAGE";
if(!$r)echo "An error occurred";
    }

so the issue is the following error message is echoed all the time: Invalid link or Password already changed.

also if i add the following to the php code:

if(!isset($pass)){
echo '
enter your new password:


';}

then it works but opens it in new blank page which is un professional thats y am trying to add it to the html. any suggestions thanks.

include() error :(

Shalomd — Thu, 23 May 2013 07:21:30 +0000

when include file to dreamweaver i cant edit anything in design view.

What should i do?

Undefined offset? Why?

xianamersu — Wed, 22 May 2013 20:57:22 +0000

Why does this code snippet keep getting Undefined offset: 2, Undefined offset: 7, Undefined offset: 11, respectively? I'm not sure where I'm going wrong,

for($i = 0; $i < $user_length; $i++) // CHECKS IF THE USERNAME, FIRST NAME, IC NUMBER AND CONTACT NUMBER IS ALREADY BEEN REGISTERED AS A MEMBER
                    {
                        $userdetail = explode(":", $user[$i]);
                        if ($_POST['ic'] == $userdetail[2])
                        {
                            echo "Sorry!
The ic no is already in use!";
                            $error = 1;
                            $i = $user_length;
                        }
                        else if ($_POST['phone'] == $userdetail[7])
                        {
                            echo "Sorry!
phone no is already in use!";
                            $error = 1;
                            $i = $user_length;
                        }
                        else if ($_POST['facename'] == $userdetail[10])
                        {   
                            echo "Sorry!
The Username you provided is already in use!";
                            $error = 1;
                            $i = $user_length;
                        }

                    }

Here's the text file format the explode is reading from:

u0003:omied:123456-12-1234:male:married:privatesector:dfsfsdf:603-32323242:6016-2343432:omied@gmail.com:omeid123:dingo1234

as you can see, ic, phone, and facename are defined as 2, 7 and 10 following the format of the loop and array.

Passing variable through URL

weeraa — Wed, 22 May 2013 19:12:12 +0000

I want to pass a combo box value from url in php. I have no idea how to do it. I just try like this.
This my combo box html code.

 

//What i want is pass selected value through URL

     > Click here

I'm bit new to php and what is wrong with this code?
im sure that 'MyCity.php' coding is correct, because i pass, hard coded value throgh above URL and could get that value from MyCity.php

How to call 2 tables with matching fields

mark2326l — Wed, 22 May 2013 15:52:00 +0000

I have a MySQL DB with 2 Tables in particular, "Properties" and "Tenants". Each Table has a unique address Field "propAddress" & "TenAddress".
I have a PHP page with a repeating reigon that lists all properties in the DB.
What I'm trying to do is list all the tenants info to the matching property based on the addresses.
I have it in my mind I should be using the "Where Clause".
Any advise will be greatly appreciated.

mysql_select_db($database_rent, $rent);
$query_RsProp = "SELECT * FROM Properties ORDER BY PropId ASC";
$query_limit_RsProp = sprintf("%s LIMIT %d, %d", $query_RsProp, $startRow_RsProp, $maxRows_RsProp);
$RsProp = mysql_query($query_limit_RsProp, $rent) or die(mysql_error());
$row_RsProp = mysql_fetch_assoc($RsProp);

if (isset($_GET['totalRows_RsProp'])) {
  $totalRows_RsProp = $_GET['totalRows_RsProp'];
} else {
  $all_RsProp = mysql_query($query_RsProp);
  $totalRows_RsProp = mysql_num_rows($all_RsProp);
}
$totalPages_RsProp = ceil($totalRows_RsProp/$maxRows_RsProp)-1;

$colname_Recordset1 = "-1";
if (isset($_GET['TenantId'])) {
  $colname_Recordset1 = $_GET['TenantId'];
}
mysql_select_db($database_rent, $rent);
$query_Recordset1 = sprintf("SELECT Properties.Address, Properties.PropId, Tenants.TenantId, Tenants.FirstName1, Tenants.LastName1, Tenants.FirstName2, Tenants.LastName2, Tenants.Phone1, Tenants.Phone2, Tenants.ContractStart, Tenants.ContractEnd, Tenants.RentDueDate, Tenants.Email, Tenants.ContractLink, Tenants.ApartmentNo, Tenants.TenantAdress FROM Properties, Tenants WHERE Properties.PropId AND Properties.Address=Tenants.TenantAdress AND %s", GetSQLValueString($colname_Recordset1, "int"));
$Recordset1 = mysql_query($query_Recordset1, $rent) or die(mysql_error());
$row_Recordset1 = mysql_fetch_assoc($Recordset1);
$totalRows_Recordset1 = mysql_num_rows($Recordset1);
?>
http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
http://www.w3.org/1999/xhtml">


Untitled Document





  
    



      
        " width="150"/>
         
,

Warning: session_start() Cannot send session cache limiter

lloyd.farrell.7 — Wed, 22 May 2013 15:16:16 +0000

Hi everyone, got really strange issue with a template I have started to build.

I am continually getting the follwing error message
Warning: session_start() [function.session-start]: Cannot send session cache limiter - headers already sent

Even though the only code I have on my page is

it's driving me crazy... Any help would be appreciated, thanks

array merge

aithabuddy — Wed, 22 May 2013 13:31:32 +0000

I have an array of format

Array
(
    [1] => Array
        (
            [1] => Array
                (
                    [27] => C1
                    [28] => Y1
                )

            [2] => Array
                (
                    [31] => C2
                    [32] => Y2
                )

            [3] => Array
                (
                    [34] => C3
                    [35] => Y3
                )

        )

    [2] => Array
        (
            [4] => Array
                (
                    [37] => X1
                )

            [5] => Array
                (
                    [38] => X2
                )

        )

    [3] => Array
        (
            [7] => Array
                (
                    [40] => D1
                )

            [9] => Array
                (
                    [42] => D2
                )

        )

)

with this array I need to form another array like

Array
(
    [0] => Array
        (
          [27] => C1
          [28] => Y1
          [37] => X1
          [40] => D1
        )
    [1] => Array
        (
          [27] => C1
          [28] => Y1
          [37] => X1
          [40] => D2
        )
    [2] => Array
        (
          [27] => C1
          [28] => Y1
          [37] => X2
          [40] => D1
        )
    [3] => Array
        (
          [27] => C1
          [28] => Y1
          [37] => X2
          [40] => D2
        )

    [4] => Array
        (
          [31] => C2
          [32] => Y2
          [37] => X1
          [40] => D1
        )
    [5] => Array
        (
          [31] => C2
          [32] => Y2
          [37] => X1
          [40] => D2
        )
    [6] => Array
        (
          [31] => C2
          [32] => Y2
          [37] => X2
          [40] => D1
        )
    [7] => Array
        (
          [31] => C2
          [32] => Y2
          [37] => X2
          [40] => D2
        )
    [8] => Array
        (
          [34] => C3
          [35] => Y3
          [37] => X1
          [40] => D1
        )
    [9] => Array
        (
          [34] => C3
          [35] => Y3
          [37] => X1
          [40] => D2
        )
    [10] => Array
        (
         [34] => C3
          [35] => Y3
          [37] => X2
          [40] => D1
        )
    [11] => Array
        (
          [34] => C3
          [35] => Y3
          [37] => X2
          [40] => D2
        )
)

and it should work for 'n' dimensional array not only for 3-dimensional array.

Please help me with this.....

Thanks in advance.

How to stop automatical download

rolanduk — Wed, 22 May 2013 12:46:11 +0000

Hy All I have another problem. When somebody going to my download link Click Here a window pop up to download the file called get.php. I dont want that to appear. Because its not the file which is under the "regulr downlod button" . The get.php its the file which controll the progress of the download in the site. I paste here the code from the donwload.php because i think there is the problem.

or may have been removed by the owner.";
        }
        else
        {
            $ip = $_SERVER['REMOTE_ADDR'];
            $country = $users->countryFromIP($ip);
            $now = date("y-m-d h:i:s");
            while($info = mysql_fetch_array($fileid)) 
            {
                $fileid2 = trim(mysql_real_escape_string($info['id']));
                $userid = trim(mysql_real_escape_string($info['uploaded_by']));
                $filename = trim(mysql_real_escape_string($info['file_title']));
                $filesize = trim(mysql_real_escape_string($info['file_size']));
                $filepath = trim(mysql_real_escape_string($info['file_path']));
                $filedate = trim(mysql_real_escape_string($info['created_date']));
            }
   mysql_query("INSERT INTO `file_visits` SET `file_id` = '$id', `country_iso` = '$country', `ip_address` = '$ip', `user_id` = '$userid', `date` = '$now'");
   $rand = substr(md5($now),1,8);
   mysql_query("insert into conversions set ip = '$_SERVER[REMOTE_ADDR]', user_id='$userid', date='$now', file_id='$fileid2', rand='$rand'");


        }
        if(isset($_POST['submit'])){
        $ret_val = $users->is_loginValid(mysql_real_escape_string($_POST['user_name']),mysql_real_escape_string($_POST['password']));
    if($ret_val == -1){     
        header( 'Location: login.php?alert=invalid' ) ; 
        exit();
    } elseif($ret_val == 0){
                header( 'Location: login.php?alert=banned' ) ;  
        exit();
        } else {                
        $_SESSION['userid'] = $ret_val['id'];
        $_SESSION['username'] = $ret_val['username'];
        $_SESSION['email'] = $ret_val['email'];
        $_SESSION['pass'] = $_POST['password'];
        $_SESSION['email'] = $users->getEmailAddress();
        $_SESSION['status'] = $users->getUserStatus();
        $_SESSION['timestamp'] = time();
                $ip = $_SERVER['REMOTE_ADDR'];
                $now = date('Y-m-d H:i:s');
                $ado->exec("INSERT INTO `ip_logs` SET `user_id` = '$ret_val[id]', `ip` = '$ip', `date` = '$now'");          
        header( 'Location: download.php?id=$id' ) ; 
        exit(); 
    }               
        }
        if($_GET['type'] == 'premium') {
        if($users->validCredits($_SESSION['userid'])) {
        if($files->FileExists($id)) { 
        $result1 = $ado->exec("SELECT * FROM `uploads` WHERE `id` = '$id'");
        $row1 = $ado->fetch($result1);
        $filename1 = $row1['hash'];
        $filepath1 = $settings->getUploadPath();
        $fileid1 = $row1['id'];
        $now = date('y-m-d');
        $ado->exec("INSERT INTO `credit_downloads` SET `file_id` = '$fileid1', `user_id` = '$_SESSION[userid]', `date` = '$now'");
        $ado->exec("UPDATE `users` SET `credits` = credits - 1 WHERE `id` = '$_SESSION[userid]'");       
        $files->download($filepath1.$filename1);
        } else {
        echo "";
        }
        } else {
        echo "";
        }
        }
?>
                
isUserLoggedIn()){ ?>
                


  
    
      
        
          
          
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Download images from URLS

mpc123 — Wed, 22 May 2013 10:56:48 +0000

I am trying to get to download images into a file from database field urls onto my server as there is lots of them. I think im on the right track.

I currently have an error

Parse error: syntax error, unexpected T_STRING in getimages.php on line 11

Hope someone can help with this please.

php MSQL Date

davidjennings — Wed, 22 May 2013 10:54:04 +0000

Hi All I am trying to format the sql ouput reg_date into a date format current details echoed out 2013 - 03 - 08 12:12:11 I just require the date only

echo stripslashes($row['reg_date'])

$result = $mysqli->query($query) or die ($mysqli->error.__LINE__);

 if($result->num_rows > 0)
    {
      while($row = $result->fetch_assoc())
     {
  echo stripslashes($row['reg_date']) . "  " . stripslashes($row['centre_name'])."
";
     }
   else
   {
   echo "No results found";
   }
 mysqli_close($mysqli);

Thanks in advance
D

Having trouble with rename()

Borzoi — Wed, 22 May 2013 07:30:49 +0000

Hi everyone. It's been a while since I've needed help with a PHP problem. Hopefully someone here knows what I'm doing wrong because I can't see it.

I am trying to use rename() to rename an image file which is in a subdirectory of a subdirectory the script is running in. The script is running in "/folder" and the images are held in "/folder/images/general"

The script I currently have is:

$old = "./images/general/item2.jpg";
$new = "./images/general/item44.jpg";

if(file_exists($old))
{
    rename($old, $new);
    echo "yes";
}
else
{
    echo "no";
}

The if statement is finding the file as my browser is outputting "yes" however the file is not being renamed. The permissions of the image file are 644 which as far as I am aware, is all it needs to be but I have tried with the permissions set to 666 and even 777. Have I missed something increadibly obvious?

I need the script to be able to rename the image as it's uploaded (was going to have it uploaded, then renamed unless there's a more efficient way?) and to rename files which already exist.

Unfortunately, error logging is disabled on the server this is hosted on and I don't have the necessary access to enable it. Is there maybe something I can put in die() to output the PHP error to the browser just like die(mysql_error()); would output the MySQL error?

Google calender issue

Priti_P — Wed, 22 May 2013 06:25:04 +0000

Hello there,
Does anyone know about following google calender issue:
I had code for google calender invitation.
But due to some reson I add patch over there which fetches some extra information and merge in the body of that mail.
But what I found is : when I add patch there, It takes only some starting part of information.
Final conclusion is it takes particular length of data in calender.
(If you say how I came to this decission, then here is my answer: I tried to remove previous part of my message then it added next few lines of added patch. I again removed some part of body message, it again take some part of message!!! )

Is this known issue or am wrong somewhere?
Help me out please. This issue is wasting my time.
Please let me know if am not clear in this question.

how to I check for existing username without using mysql in php?

xianamersu — Wed, 22 May 2013 05:19:25 +0000

How to I check for existing username without using mysql in php?
I tried something like this but it isnt working. Please help. Thanks. Strictly no SQL...

     $name=$nme;
        $name = file("datatext/users.txt");
        $ic=file("datatext/users.txt");
        if (this.$nme== $name)
        {
        echo "this user exits, please log in";
        }

Redirecting problem in the PHP code, Can you help

rolanduk — Tue, 21 May 2013 20:26:03 +0000

Hy All

Im here again to ask for you help. I still in the begining to launch the site, and i found a major error. The theory is the following. I planning to start a Pay per download site, which mean the members upload a file and when somebody want to download it, they have to fill a short survey. After survey done, both me and them get money. The problem is i test the script, and when i open the donwload link http://www.filemonster.org/download.php?id=11 the page load, then immediately redirect and i get a following error "Stop trying to download without completing a survey." which is an anti cheat message. Its 100% wrong because its appears all the time. i paste here the code, do you know why its appear straight after the page load? Its just appear for me on the Firefox.

alert("Invalid access.");';
    die();
}
$path = $settings->getUploadPath();
$rand = mysql_real_escape_string($_GET['rand']);
$sql = "SELECT * FROM `conversions` WHERE `rand` = '$rand' and `converted` = '1'";
$result = mysql_query($sql);
$row = mysql_fetch_assoc($result);
$file = $row['file_id'];
if($row['converted'] == '1') {
if($row['downloaded'] == '0') {
$path = $settings->getUploadPath(); 
$sql5 = "select * from `uploads` where `id` = '$file'";
$row5 = $ado->fetch($ado->exec($sql5));
$sql6 = "UPDATE `conversions` SET `downloaded` = '1' WHERE `rand` = '$rand'";
$ado->exec($sql6);
set_time_limit(0);  

header("Pragma: public");
header("Expires: 0");
header("Cache-Control: must-revalidate, post-check=0, pre-check=0");
header("Cache-Control: public");
header("Content-Description: File Transfer");
header("Content-Type: application/force-download"); 
header("Content-Type: application/octet-stream"); 
header("Content-Type: application/download"); 
header("Content-Disposition: attachment; filename=\"".$row5['hash']."\"");
header("Content-Transfer-Encoding: binary");
header("Content-Length: ".filesize($path.$row5['hash']));
ob_end_flush(); 
@readfile($path.$row5['hash']);
exit(0); 

} else {
echo '';
}
} else {
echo ''; 
}
?>

Please if any of you have an idea, share with me

ImagickException memory allocation failed

wplay — Tue, 21 May 2013 17:05:50 +0000

Hi all,

I have been getting ImagickException with imagick on my server but cannot reproduce it on my computer(localhost).

This is when I try to call thumbnailImage(with, height, true) for a JPG

exception 'ImagickException' with message 'Memory allocation failed /tmp/funYYmdPl[0]' @ cache.c/AcquireCacheNexusPixels/416' This is when I call writeImages(path, true) for a GIF exception 'ImagickException' with message 'Memory allocation failed/home/funsub/public_html/uploads/gif/45/45544.gif' @ gif.c/WriteGIFImage/1605'

These are my specs:
ImageMagick 6.5.4-7 2012-05-07 Q16
imagick module version 3.0.1
PHP 5.3.24

I'm on VPS and have set disk usage and bandwidth for that cpanel to unlimited.

I've also tried increasing the php ram usage as well, the problem still occurs.

[root@server ~]# df -h
Filesystem Size Used Avail Use% Mounted on
/dev/vda3 72G 16G 54G 23% /
tmpfs 427M 0 427M 0% /dev/shm
/dev/vda1 195M 76M 110M 41% /boot
/usr/tmpDSK 622M 50M 541M 9% /tmp

Any ideas why?

i cant create the code to login

aqualove — Tue, 21 May 2013 15:00:01 +0000

http://www.wapforum.org/DTD/xhtml-mobile10.dtd"> 
http://www.w3.org/1999/xhtml">  
    
        
    
     
    Universiti Malaysia Sabah 
      
    
    
    
    
 
 

    

        
        Sistem Kompaun Pelajar
            Home
    


    

        
            Login
            
            
              Katanama

              :
            
            Katalaluan:
            
            
            

        

    
   
   













//example for table student. the rest almost the same
` varchar(50) NOT NULL,
  `pwd` varchar(50) NOT NULL,
  `nama` varchar(50) NOT NULL,
  `std_id` varchar(50) NOT NULL,
  `std_ic` varchar(50) NOT NULL,
  `sekolah` varchar(50) NOT NULL,
  `kos` varchar(50) NOT NULL,
  `tahun` int(2) NOT NULL,
  PRIMARY KEY (`ID`)
) ENGINE=InnoDB  DEFAULT CHARSET=armscii8 COMMENT='student xda s d ujung k' AUTO_INCREMENT=2 ;





//config.php

Best GIF resizing software

wplay — Tue, 21 May 2013 14:40:01 +0000

Hi all,

I'm currently using imagemagick to resize gifs for my site. But the compression doesn't seem really good.

I've already tried optimizing it the best way I could, but it isn't satisfactory. Does anyone have recommendations for a better option?

Tumblr's gif compression seems to be the best I've seen, was hoping if I could achieve similar results.

Thanks!

Login with other DB

bradly.spicer — Tue, 21 May 2013 13:42:52 +0000

Hey all,

Been trying to work this out. But I'm stumped!

Got a database running on Moodle. Want to create an external script which uses the usernames and passwords from the table moodle_user and the db Profiled_Moodle.

Here is my page so far:



        ' . $username ;

        while ($row = mysql_fetch_assoc($result)) {
            print_r($row);
            echo 'logged in as:' . $username;
        } 
    } else {
        echo "Not logged in";
    }
    ?>

The reason I have that salt is because in moodle config.php I have that set.

$CFG->passwordsaltmain = '7(}AouN0sysQF#{]s@[F]Y~b]5E';

When I login to the form. Nothing is happening? I'm not getting an echo or print

Thanks guys

Help, My DB do not insert more then three record.

adeeb.keyaam — Tue, 21 May 2013 10:09:07 +0000

Here is my code below:

 $value) {
        $_POST[$key] = mysql_real_escape_string(strip_tags($value));
    }

    // data container
    $name = $_POST['name'];
    $name = strtolower($name);
    $password = $_POST['password'];
    $password = md5($password);
    $type = $_POST['type'];
    $account = $_POST['account'];
    date_default_timezone_set('Asia/Dhaka');
    $time = date("h:i:s A");
    $date = date("D d M y");
    $create = ($date." @ ".$time);
    $ip = $_SERVER['REMOTE_ADDR'];
    $login = ($date." @ ".$time);
    $logout = ($date." @ ".$time);


    // error message
    $error = "";
    $success = "";          

    // check duplicate data
    $u_check = mysql_query('SELECT name FROM users WHERE name = "'. $name .'"');

    if(mysql_num_rows($u_check)>0){             
     $error = "User name is already taken, try different one !!!";               
     mysql_close($conn);        
    }
    else{               

     // insert data into table
     mysql_query
     ("
        INSERT INTO users (id, name, password, type, account, create, ip, login, logout) 
        VALUES ('', '$name', '$password', '$type', '$account', '$create', '$ip', '$login', '$logout') 
     ");

     $id = mysql_insert_id();
     $get_id = mysql_query('SELECT * FROM users WHERE id = "'. $id .'"');
     $data = mysql_fetch_array($get_id);
     $success = ''.$data['name'].''.' is created successfully.';
     mysql_close($conn);

    }
}

?>
http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
http://www.w3.org/1999/xhtml">


Add User

















 

    

  

   



   

  

  

   

    Notice

    Please read the guidance notes below, before completing the form :

     • User Name must be unique.
     • User Name can contain alphabets & numbers only.
     • User Name characters length limit is from 4 to 20.
     • Password must be equal or more then 8 characters long.
     • Click on underlined user name to add account information.
     • Marked ( •) field can't be left empty.

    

   

   

    Add User Account

    
     

      
      
      

      
      
      

      
       •
       User Name
       :
       
      
      
       •
       Password
       :
            
      
      
       •
       Confirm Password
       :
            
      
      
       •
       User Type
       :
           
      
      
       •
       User Access
       :

Here is my db structure

CREATE TABLE IF NOT EXISTS users (
id int(11) NOT NULL AUTO_INCREMENT,
name varchar(30) NOT NULL,
password int(11) NOT NULL,
type varchar(30) NOT NULL,
account varchar(30) NOT NULL,
create varchar(30) NOT NULL,
ip varchar(30) NOT NULL,
login varchar(30) NOT NULL,
logout varchar(30) NOT NULL,
PRIMARY KEY (id)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;

Specific Keyword URL Redirecting

4fridi — Tue, 21 May 2013 09:40:10 +0000

I have script which has search engine to find mp3 songs, i need that if someone search the site with free mp3 songs or mp3 free songs both keywords has free keyword.
i have redirected with header(); function through my coding in php but what about previously indexed urls with these free kwyrod in google, if someone click on that url it will not redirecting to notfound.php page, i have to redirect those urls with .htacess file please help me
my url pattern is http://mydomain.com/search/songs/free+mp3+songs.html
please help me, my redirecting is working if someone type in text box and hit the search button but its not working if you just directly implement this free keyword in already generated url and hit the enter button it will show up with results i need this too redirect to notfound.php page thanks!

Search several tables at the same time

PF2G — Mon, 20 May 2013 22:36:01 +0000

Hello,

I did this search engine just for one table:

$search 

";



mysql_connect("localhost","root","");
mysql_select_db("rmworshipers");



$search_exploded = explode (" ", $search);
$x=1;

foreach($search_exploded as $search_each)
{
$x++;    
}

$constructs ="SELECT * FROM events WHERE event_name LIKE '%$search_each%'";
$run = mysql_query($constructs) or die(mysql_error());

$foundnum = mysql_num_rows($run);

if ($foundnum==0)
echo "Sorry, there are no matching result for $search.";
else
{ 

echo "$foundnum results found !";

$per_page = 10;
if(isset($_GET['start'])){
$start = $_GET['start'];
}
$max_pages = ceil($foundnum / $per_page);
if(!isset($_GET['start'])){
$start=0; 
}
$getquery = mysql_query("SELECT * FROM events WHERE event_name LIKE '%$search_each%' LIMIT $start, $per_page");
$runrows = mysql_fetch_assoc($getquery);

do{
    $id = $runrows ['event_id'];
    $nome = $runrows ['event_name'];
    echo "$id - $nome";
}while($runrows = mysql_fetch_assoc($getquery));

//Pagination Starts
$prev = $start - $per_page;
$next = $start + $per_page;

$adjacents = 3;
$last = $max_pages - 1;

if($max_pages > 1)
{   
//previous button
if (!($start<=0)) 
echo " Prev ";    

//pages 
if ($max_pages < 7 + ($adjacents * 2))   //not enough pages to bother breaking it up
{
$i = 0;   
for ($counter = 1; $counter <= $max_pages; $counter++)
{
if ($i == $start){
echo " $counter ";
}
else {
echo " $counter ";
}  
$i = $i + $per_page;                 
}
}
elseif($max_pages > 5 + ($adjacents * 2))    //enough pages to hide some
{
//close to beginning; only hide later pages
if(($start/$per_page) < 1 + ($adjacents * 2))        
{
$i = 0;
for ($counter = 1; $counter < 4 + ($adjacents * 2); $counter++)
{
if ($i == $start){
echo " $counter ";
}
else {
echo " $counter ";
} 
$i = $i + $per_page;                                       
}

}
//in middle; hide some front and some back
elseif($max_pages - ($adjacents * 2) > ($start / $per_page) && ($start / $per_page) > ($adjacents * 2))
{
echo " 1 ";
echo " 2 .... ";

$i = $start;                 
for ($counter = ($start/$per_page)+1; $counter < ($start / $per_page) + $adjacents + 2; $counter++)
{
if ($i == $start){
echo " $counter ";
}
else {
echo " $counter ";
}   
$i = $i + $per_page;                
}

}
//close to end; only hide early pages
else
{
echo " 1 ";
echo " 2 .... ";

$i = $start;                
for ($counter = ($start / $per_page) + 1; $counter <= $max_pages; $counter++)
{
if ($i == $start){
echo " $counter ";
}
else {
echo " $counter ";   
} 
$i = $i + $per_page;              
}
}
}

//next button
if (!($start >=$foundnum-$per_page))
echo " Next ";    
}   
} 
} 
?>

and now i want to Select the tables: Guests, News, Interviews. And also how do i do to if i search for a some guest or event it gives me the results of every news/interviews where the guest and/or event appears...

Thank you for your help

Problem with mysql connection

Ridji — Mon, 20 May 2013 22:27:31 +0000

Hi guys, I'm new here. I have a problem with connecting to my sql database. Everytime when I want to log in, I get this :

Warning: mysql_connect(): Access denied for user 'root'@'localhost' (using password: YES) in C:\xampp\htdocs\novi\funkcije.php on line 9

Warning: mysql_query() expects parameter 2 to be resource, boolean given in C:\xampp\htdocs\novi\funkcije.php on line 25
Access denied for user ''@'localhost' to database 'photosend'

Please help mee,
I would be very grateful.

The best way to create documentation.

NardCake — Mon, 20 May 2013 22:03:25 +0000

Hello! Currently I am working on a PHP project on my own that is slowly growing, before I really get it out there I want to begin working on some documentation. It's just that I'm unsure on how documentation is usually created, best practices on writing it, and how it should be organized. Wasn't sure where this should be posted, but thanks for any suggestions!

revisit How to Send Mail to Email Address on Mysql Database?

amkaos — Mon, 20 May 2013 20:46:59 +0000

Hi:
i search as to why my database wont send out emails and find this forum.
i find the exact code im using in this forum.. it originally is for xaamp.
i need to have it work from my server:

http://www.daniweb.com/web-development/php/threads/412468/how-to-send-mail-to-email-address-on-mysql-database.

i posted on https://gist.github.com/amkaos/5608094
but i can post code here if need be..

this is what is going on:
i have domain and web host.

i type in address to pull up a form that pulls all names and emails
from mysql database. at top of page "connected successfully"

there is message box for me to type text.
when i hit submit, i get all "connected successfully , emails processed"..
But no emails are sent ..
there are no errors..

my web host looked over my code and thinks it should be fine..
they are not restricting any outgoing emails..
they said i do not have to configure anything different.

i have a "Contact Form" on my domain and users fill out and submit to my email just fine.. i get the info sent to my gmail and it is added to Database..

i am desperate to fix this ..
any help is greatly appreciated

thanks

error in php code last insert id

Fiorentino01^ — Mon, 20 May 2013 16:46:09 +0000

Hi, I am working on an hotel booking system for a small hotel.I finally found a nice tutorial on HTML.it.It is in Italian but that's not a problem for me as Italian is my mother tongue.The site consists of the usual tables like clients, reservations, etc.I ran all the scripts from the command line and everything works fine. I still am not too sure of what I am doing but I figured that once I deliver the finished site to the hotel people, they are not going to want to fiddle with the command line, phpMyAdmin,MySQL etc.when they have to insert a reservation.So I started creating some user interface like a form to insert clients data as below.The problem is that last insert id business which is very important for the site to work.I searched the Internet but could not find a solution, I think the problem is that insert_id into @codeclient.Can you help me?this is the code involved.

INSERT INTO client SET
nominativo = 'Rossi Mario',
indirizzo = via Manzi 2 00153 Rome,
telefono ='06 86123920';
SELECT_LAST_INSERT_ID() INTO @codCliente;




Insert Data into MySQL Database
Nominativo
:


Indirizzo
:










";
 echo "Back to main page";
 }

 else {
 echo "ERROR";
 }
 ?> 

 

 And this is the error I get:Parse error: syntax error, unexpected 'LAST_INSERT_ID' (T_STRING) in C:\inetpub\wwwroot\Hotel Site\insert_ac.php on line 20

HOW do I add A PHP Link

sambulo.senda — Mon, 20 May 2013 16:03:26 +0000

 $options[] = array( 'title' => __('Donate to the theme developers', 'default'),
                    'desc'  => __('Note :Donate to the Developers of this theme, Donate any amount to keep the themes free '  , 'default'),
                    'id'    => '',
                    'std'   => '',
                    'type'  => 'sep' );

How do I add a link to the text I want the word "Donate" to have a link

How do I do that. If anyone could help me I would really be grateful

Time zone

varunsara — Mon, 20 May 2013 13:13:14 +0000

Guys,

please let me know is anybody aware of the below doubt.

php taking hosting server date and time but am in need to find the client time and date who accesing the site.

otherwise how to find the date & time in server time zone .

Assigment Problem-Hungarian Algorithm

Nero Basanta — Mon, 20 May 2013 12:51:30 +0000

I am working on an Assignment Problem, a part of Operation Research but the problem am facing is how to assign the task to the agents and then the anomaly where the algorithm has to repeat it self when it is not able to perform the assignment.

grouping data in php page

Maideen — Mon, 20 May 2013 10:18:38 +0000

hi
I have created the php report using below code. It works fine. But My problem is to group the data
example

# Date          Code   Name       Rate  Qty  Amount# 
 15.01.2011     0001   Milk       4.01  50    200.50
 15.01.2011     0125   Choklet   30.00  10    300.00
 15.01.2011     0241   Drink     12.50  12    150.00
 16.01.2011     5461   Meat      35.07  10    350.75
 16.01.2011     4587   Fish      17.80   5     89.00
                                    total    1090.25

if I take the date range from 15.01.2011 to 16.01.2011, it shows in php page look like above. But if i select
the date range as 15.01.2011 to 16.01.2011, i need look like below

Pls help me

 # Date          Code   Name       Rate  Qty  Amount# 
 15.01.2011     0001   Milk       4.01  50    200.50
 15.01.2011     0125   Choklet   30.00  10    300.00
 15.01.2011     0241   Drink     12.50  12    150.00
                             subtotal         650.50

 16.01.2011     5461   Meat      35.07  10    350.75
 16.01.2011     4587   Fish      17.80   5     89.00
                             subtotal         439.75 

                             grand total     1090.25

it is my code

    `
    

    

    fetch())
        {?>

      
        SO Date
        MV CODE
        MV NAME
        RATE
        SUPP.QTY
        AMT

'
Regards

Maideen

PHP Error

mohammed.ismail — Mon, 20 May 2013 09:46:00 +0000

What does the PHP error ‘Parse error in PHP – unexpected T_variable at line x’ means?

PHP Thread

mohammed.ismail — Mon, 20 May 2013 09:43:49 +0000

How to run the interactive PHP shell from the command line interface?

profile page

janicemurby — Sun, 19 May 2013 21:51:26 +0000

hya ive created a edit profile page for members to fill in and now i need that information to go to members profile page how do i do this ive tried several tutorials in youtube but get nowhere with them

i dont need the register or login got that already

any help would be much appreicated

ty jan xxx

show checked and unchecked checkboxes in 2 different column

rubai — Sun, 19 May 2013 19:54:22 +0000

Hi Friends,

I have 5 checkboxes. What I want is.....
I want to check 3 checkboxes so other 2 will be unchecked. After clicking the next button a table will appear and checked checkboxes will show in one column and unchecked will be another column.

Can you give any idea how to solve it. example of code will be helpful

Thanks in advance for your help. :)

php paging error

dhani09 — Sun, 19 May 2013 16:01:41 +0000

I'm using the following code for my paging on my script

 $lastPage) { // if it is greater than $lastpage
    $pn = $lastPage; // force it to be $lastpage's value
} 

// This creates the numbers to click in between the next and back buttons
$centerPages = ""; // Initialize this variable
$sub1 = $pn - 1;
$sub2 = $pn - 2;
$add1 = $pn + 1;
$add2 = $pn + 2;
if ($pn == 1) {
    $centerPages .= '  ' . $pn . '  ';
    $centerPages .= '  ' . $add1 . '  ';
} else if ($pn == $lastPage) {
    $centerPages .= '  ' . $sub1 . '  ';
    $centerPages .= '  ' . $pn . '  ';
} else if ($pn > 2 && $pn < ($lastPage - 1)) {
    $centerPages .= '  ' . $sub2 . '  ';
    $centerPages .= '  ' . $sub1 . '  ';
    $centerPages .= '  ' . $pn . '  ';
    $centerPages .= '  ' . $add1 . '  ';
    $centerPages .= '  ' . $add2 . '  ';
} else if ($pn > 1 && $pn < $lastPage) {
    $centerPages .= '  ' . $sub1 . '  ';
    $centerPages .= '  ' . $pn . '  ';
    $centerPages .= '  ' . $add1 . '  ';
}
// This line sets the "LIMIT" range... the 2 values we place to choose a range of rows from database in our query
$limit = 'LIMIT '.($pn - 1) * $itemsPerPage .','.$itemsPerPage; //returns negative range
// Now we are going to run the same query as above but this time add $limit onto the end of the SQL syntax
// $sql2 is what we will use to fuel our while loop statement below


$result2 = mysql_query("SELECT * FROM tbl_product WHERE category = '$cat' ORDER BY id ASC $limit");//query fails
if(!$result2)
echo  "ERROR".mysql_error();

//PAGINATION DISPLAY

$paginationDisplay = ""; // Initialize the pagination output variable
// This code runs only if the last page variable is not equal to 1, if it is only 1 page we require no paginated links to display
if ($lastPage != "1"){
    // This shows the user what page they are on, and the total number of pages
    $paginationDisplay .= 'Page ' . $pn . ' of ' . $lastPage. '';
    // If we are not on page 1 we can place the Back button
    if ($pn != 1) {
        $previous = $pn - 1;
        $paginationDisplay .=  '    Back ';
    } 
    // Lay in the clickable numbers display here between the Back and Next links
    $paginationDisplay .= '' . $centerPages . '';
    // If we are not on the very last page we can place the Next button
    if ($pn != $lastPage) {
        $nextPage = $pn + 1;
        $paginationDisplay .=  '    Next ';
    } 
}

?>

THEN I USE THIS LOOP TO RETRIEVE ITEMS IN THE HTML BODY

';
          echo '#'.$row[0].'('.$row[1].')'.'';
         echo ''.$row[2].'';
         echo ''.$row[4].'TL';
      echo '';
      }

      ?>

AND TO DISPLAY THE PAGINATION I DO THIS SOMEWHERE BELOW THIS LOOP

Showing

HOWEVER, when i run the code, i get this error: "You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '-5,5' at line 1".

It seems i get a negative page number when i click the "NEXT" link or try to move to a new page (by clicking that page number), so the query returns a negative range for LIMIT. But I don't know why because i have a conditon that makes sure there are no negative page numbers. I know it's a lot of code but any help figuring out the issue will be appreciated. Thanks

check (non) empty string from functions

mjsmitten — Sun, 19 May 2013 14:59:10 +0000

I have some functions that returns nothing or some value (obvious), and also having a little trouble with the if and closing, is there a good way to do this? I want to return the value after checking if any of the strings are not empty.
Actually it is a search results page. I can have result by links that follow this structure:

search_url(array("xxx" => "name");

and in the array for xxx's is either:

"sPattern"=> "name"
"sRegion"=> "name"
"sCity"=> "name"

so how to do this?

 '') { ?> 
echo  result
else
 '') { ?> 
echo result
else
 '') { ?> 
echo result
if nothing match do this

Pass data from one php script to another

fheppell — Sun, 19 May 2013 14:02:49 +0000

I've got an upload script that generates some stuff in relation to uploads eg

File foo.jpg uploaded succesfully

File bar.tiff failed to upload!
...

This is all part of a variable called $message. How could I pass this to another php script?
Thanks for any help

help me please..

dina85 — Sun, 19 May 2013 11:16:18 +0000

require("conn.php");
$sql = "select * from pemohon where kp_baru='$kp';";
$result = mysql_query($sql);
while($row = mysql_fetch_array($result))
{
    if($row == TRUE)
    {
     echo $row['kp_baru']; // can display
    }
    else
    {
        echo "No KP tiada didalam pangkalan data."; // can't display
    }
}

phpcode unable to connect to My SQL --- OOP project

kakalahori — Sun, 19 May 2013 08:04:25 +0000

ok here is the login function from my class user which parent class is a Db connection file

userName' and `Password` = '$this->password'";

        $result = @mysql_query($sqlSelect, $this->get_Conn());

//      $dataCount = mysql_num_rows($result);
        if(mysql_num_rows($result) == 0)
        {
            throw new Exception("Login Failed");
        }

        $userData = mysql_fetch_assoc($result);
        extract($userData); 

        $this->userId = $UserId;
        $this->firstName = $FirstName;
        $this->middleName = $MiddleName;
        $this->lastName = $LastName;
        $this->email = $Email;
        $this->userName = $UserName;
        $this->password = NULL;
        $this->loginStatus = true;

        $_SESSION['objUser'] = serialize($this);

        if($remember)
        {
            $struser = serialize($this);
            $expTime = time() + (60*60*24*7);
            setcookie("objUser", $struser, $expTime, "/");  
        }

    }

when from the login page i press login button it just checks for the values inside the box for error and chekcing the array error() its empty it stays on the same page

php session and echo checkbox

rubai — Sun, 19 May 2013 06:10:58 +0000

I have a problem want to be solved.
I have three pages. page1.php, page2.php
page1.php has a form with two text field. one text field is for name and another is for number. there is a submit button and a "next" button too. using session I want show given name into page2.php and create checkboxes that according to given number. (e.g if I write 4 in number text field in page1.php then 4 checkboxes will appear in page2.php, if 8 then 8 checkboxes.

I want solve this problem using session.

page1.php

page2.php

JavaScript Radio button selection and validates text field?

dina85 — Sun, 19 May 2013 03:10:03 +0000

I need to use javascript so that when the one radio button is selected nothing happens but if the other one is (for example, Cheque) it will then validate the field (Cheque Number)..

Resource ID 3 produced - cannot see what is wrong

maharrington — Sat, 18 May 2013 23:56:20 +0000

Hi,

I've had a look through the forum(s), however, can't seem to find a solution to my issue (and I don't understand the PHP Manual).

Basically, got a website linked to a database, trying to pull data from one table and display onto the website where appropriate.

I have the following code:



    $Query = "SELECT * FROM database.tablename WHERE eventDay=1";
    $Result = mysql_query ($Query, $Link) or die (mysql_error($Link));

    //ON Debugging - code stops here resulting in Resource ID #3 - suggesting there is a problem
    with the $Result. However, please check the following code to see if there are errors (if poss).

    $Rows=mysql_num_rows($Result) or die (mysql_error($Rows));
    $loop=0;
    while ($loop<$Rows){
            //Add all variables to the output loop.
            $eventVisible=mysql_result($Result,$loop,"eventVisible");
            $eventDay=mysql_result($Result,$loop,"eventDay");
            $eventImagePath=mysql_result($Result,$loop,"eventImagePath");
            $eventTitle=mysql_result($Result,$loop,"eventTitle");
            $eventInfo=mysql_result($Result,$loop,"eventInfo");
            $expiryYear=mysql_result($Result,$loop,"expiryYear");
            $expiryMonth=mysql_result($Result,$loop,"expiryMonth");
            $expiryDay=mysql_result($Result,$loop,"expiryDay");
        //Print out the values into a table
    }

    if($eventVisible==1){
        //EVENT VISIBLE
            date_default_timezone_set('Europe/London');
                if(mktime() < mktime(23,59,59,$expiryMonth,$expiryDay,$expiryYear)) {
                //Event is before expiry?>
                " width="160" height="160" style="float:left"/>

This code is for one tab - there are 6, so i simply copy the code, and change the query based on the tab that's selected.
As you can probably tell, I've tried to cut down and explain the code as much as possible - any questions though, feel free to ask.

code for converting csv file to excel

gvsamrat — Sat, 18 May 2013 21:11:15 +0000

hii can any give me a php code that converts a csv file to an excel file

my table wont update

dourvas — Sat, 18 May 2013 20:30:49 +0000

hallo there,

Its a very complicate problem and i wiil try to be as brief as i can. I hope you ll be able to understand my description.

i ve coded a script that works perfect in my localhost. When i uploaded the files to a server some things just did not work.

For the script i used 2 mysql tambles. The tables have the same exact structure and different names. They are 'big' tables. 46 fields each.

the fields from the tables fills by forms section by section (lets say that a section is 3-5 fields). (one insert and then with updates).

It seems that when most fields are already filled up the next fields just wont update. There are no errors. When i try to fill up those fields by hand using PHPMYADMIN and the same sql command i used in my code the fields updates just fine.

Is there something i am missing? Do u thing it is a coding mistake or there is a apache setting i did not think about? it is important to mention that if i reapet the procedure by starting filling the table from the section that wouldnt update it will, and soon another section wont update.

i know i may did not give a quite good description. If you dont understand what i am saynig i will try again including some code..

Mystery of Multiple Record Insertions

RoryGren — Sat, 18 May 2013 20:09:51 +0000

Hi All
I'm sure I'm missing something very small - and embarrassing!
I'm being lazy - I could have entered the data manually, but wanted to automate it.

I have a small csv file containing swimming meets, dates and locations along the following lines:

May-13;;;;
17;other;Level 1 Program 1;Arboretum;
24;other;All Levels Program 2;King's Park;
June-13;;;;
15;other;Level 2 3 Program3;Pmb;
.
. and so forth

I read this into an array, run through the array to correct the date format and then insert each line into a mySQL database table.
All easy, but my code is inserting multiple entries for each key in the array! Sometimes it inserts 6 records for each key and sometimes 19. It jsut seems to be quite random!

My code:

//===== Read csv into array =====
if (($handle = fopen("../uploads/KZNCal.csv", "r")) !== FALSE) {
    while (($data = fgetcsv($handle, 1000, ";")) !== FALSE) {
        $Cal[] = $data;
    }
  fclose($data);
}
$con  = new mysqli($HOST, $USER, $PASS, $NAME);
if (mysqli_connect_errno()) {
    printf("Connect failed: %s\n", mysqli_connect_error());
    exit();
}

$query = $con->prepare("INSERT INTO `kzn_upcoming` (`meet_name`, `location`, `start_date`) VALUES (?, ?, ?)");
foreach ($Cal as $Key => $Event) {
    //===== First 2 rows not needed =====
    if ($Key > 1) {
        if (!is_numeric(substr($Event[0], 0, 1))) {
            //===== Get month and year =====
            $Month = date('m', strtotime(substr($Event[0], 0, 3)));
            $Year  = '20' . substr($Event[0], 4);
        }
        else {
            $Day        = trim(substr($Event[0], 0, 2));
            if ($Day < 10) {$Day = '0' . $Day;}
            // === Discarded $Event[1] - of no consequence for this table. ===
            $Name       = $Event[2];
            $Location   = $Event[3];
            $Start      = "$Year-$Month-$Day";
            //===== Inserted into "clean" array to see if there was something wrong =====
            $Calendar[] = array($Name, $Location, $Start);
        }
    }
}
echo "
Count: " . count($Calendar) . "
"; //===== Produces expected result of 39 =====

$query = $con->prepare("INSERT INTO `kzn_upcoming` (`meet_name`, `location`, `start_date`) VALUES (?, ?, ?)");
foreach ($Calendar as $Key => $Meet) {
    echo "$Key: $Meet[0] - $Meet[1] - $Meet[2]
"; //===== All displayed correctly =====
    $query->bind_param("sss", $Meet[0], $Meet[1], $Meet[2]);
    $query->execute();
}

$query->close();
$con->close();

There are a whole 39 rows in the $Calendar array. The echo produces the expected result - 39 rows, as per the count(). I get random duplication of each record inserted into the table! One run, I had 91 records for each Meet, another "only" 6!
What have I missed?

Not display the alert if email does not exist in table

GlenRogers — Sat, 18 May 2013 12:50:14 +0000

Can someone have a look at some code for me?

Here the problem. This is meant to delet an email address form a mysql table then alert the user this has been done. If the address does not exist then it alerts the user to that too.

But even if the address ddoes not exist it alerts the user that the address has been deleted!

Heres the code

if (filter_var($email, FILTER_VALIDATE_EMAIL)) {
   if($r = mysql_query("DELETE FROM maillist WHERE email = '$mail'")){
      echo '';
   }
   else {
      echo '';
   }
   }
   else {
      echo '';
   }
   }

Thanks for looking...............

Php overwrite file with variable

martjojo1 — Sat, 18 May 2013 12:36:24 +0000

Hey all,

i'm working on some code and i've got a little problem.

$my_file = 'file.php';
$newline = "";
file_put_contents($my_file, $newline);

As you can see i want to post a line into a file.. The problem is, this file will output:

the $root is gone..
Please help me.
Thanks

Converting mysql class to sqlite class

JACOBKELL — Sat, 18 May 2013 11:36:02 +0000

I need to convert mysql class of one script to make a support for sqlite,but problem is sqlite dont have username/password thing nor database select as well,which means how some parts need to be removed.If i would convert to mssql one search and replace probaly would do the job.There is another file which contain queries but i belive that does'nt need to be touched.

So here is the code,what lines i need to remove and which just replace?

 "localhost",
            "serverport"=> "3306",
            "username"  => false,
            "password"  => false,
            "database"  => false,
            "persist"   => false,
            "dieonerror"=> false,
            "showerror" => false,
            "error_file"=> true
        );

    function __construct() {
        global $db_config;
        $this->settings = array_merge($this->settings, $db_config);
        if($this->settings["error_file"] === true) $this->settings["error_file"] = dirname(__FILE__)."/__mysql_errors.log";
    }

    function connect() {
        if (!$this->link) {
            $this->link = ($this->settings["persist"]) ? 
                mysql_pconnect(
                    $this->settings["servername"].":".$this->settings["serverport"], 
                    $this->settings["username"], 
                    $this->settings["password"]
                ) : 
                mysql_connect(
                    $this->settings["servername"].":".$this->settings["serverport"], 
                    $this->settings["username"], 
                    $this->settings["password"]
                ) or $this->error();
        }
        if (!mysql_select_db($this->settings["database"], $this->link)) $this->error();
        if($this->link) mysql_query("SET NAMES 'utf8'");
        return ($this->link) ? true : false;
    }

    function query($sql) {
        if (!$this->link && !$this->connect()) $this->error();
        if (!($this->result = mysql_query($sql, $this->link))) $this->error($sql);
        return ($this->result) ? true : false;
    }

    function nextr() {
        if(!$this->result) {
            $this->error("No query pending");
            return false;
        }
        unset($this->row);
        $this->row = mysql_fetch_array($this->result, MYSQL_BOTH);
        return ($this->row) ? true : false ;
    }

    function get_row($mode = "both") {
        if(!$this->row) return false;

        $return = array();
        switch($mode) {
            case "assoc":
                foreach($this->row as $k => $v) {
                    if(!is_int($k)) $return[$k] = $v;
                }
                break;
            case "num":
                foreach($this->row as $k => $v) {
                    if(is_int($k)) $return[$k] = $v;
                }
                break;
            default:
                $return = $this->row;
                break;
        }
        return array_map("stripslashes",$return);
    }

    function get_all($mode = "both", $key = false) {
        if(!$this->result) {
            $this->error("No query pending");
            return false;
        }
        $return = array();
        while($this->nextr()) {
            if($key !== false) $return[$this->f($key)] = $this->get_row($mode);
            else $return[] = $this->get_row($mode);
        }
        return $return;
    }

    function f($index) {
        return stripslashes($this->row[$index]);
    }

    function go_to($row) {
        if(!$this->result) {
            $this->error("No query pending");
            return false;
        }
        if(!mysql_data_seek($this->result, $row)) $this->error();
    }

    function nf() {
        if ($numb = mysql_num_rows($this->result) === false) $this->error();
        return mysql_num_rows($this->result);
    }
    function af() {
        return mysql_affected_rows();
    }
    function error($string="") {
        $error = mysql_error();
        if($this->settings["show_error"]) echo $error;
        if($this->settings["error_file"] !== false) {
            $handle = @fopen($this->settings["error_file"], "a+");
            if($handle) {
                @fwrite($handle, "[".date("Y-m-d H:i:s")."] ".$string." <".$error.">\n");
                @fclose($handle);
            }
        }
        if($this->settings["dieonerror"]) {
            if(isset($this->result)) mysql_free_result($this->result);
            mysql_close($this->link);
            die();
        }
    }
    function insert_id() {
        if(!$this->link) return false;
        return mysql_insert_id();
    }
    function escape($string){
        if(!$this->link) return addslashes($string);
        return mysql_real_escape_string($string);
    }

    function destroy(){
        if (isset($this->result)) mysql_free_result($this->result);
        if (isset($this->link)) mysql_close($this->link);
    }


}
?>

PHP wont make a file.

MasterHacker110 — Sat, 18 May 2013 09:55:21 +0000

I am trying to create a file that with some values the user entered in the webpage. But my code doesnt create a file. And I have other code that is more or less similar that creates the file:

Here is my code:

         In order to create an account we need certain information about you. We will not in anyway use this information 
 ";
            echo "  To identify you personaly. Read out privacy statement HERE";
            echo "";
            echo "  Required information ";
            echo "";

            echo "";
            echo "";
            echo "First name:
";
            echo "
";
            echo "Last name:
";
            echo "
";
            echo "Email: 
";
            echo " Is also your account name 
";
            echo "
";
            echo "Password: 
";
            echo "       Must contain atleas 1 number and 1 upper case character 
";
            echo "      
";
            echo "       Male
";
            echo "       Female
";
            echo "      Country:
";
            echo "      ";
            echo "      ";
            echo "      
";
            echo "      ";
            echo "      
";
            echo "       No 
";
            echo "       Yes 
";
            echo "  ";
            echo "";

            echo "";
            echo "  Additional infromation";
            echo "";
            echo "";
            echo "  ";
            echo "      Job position: 
";
            echo "      
";
            echo "      Company: 
 ";
            echo "      
";
            echo "      Cellphone: 
";
            echo "      
";
            echo "  ";
            echo "  ";
            echo "";

            if(isset($_REQUEST['submit'])){
            $email = $_REQUEST['email'];
            $pass = $_REQUEST['password'];

            $file = fopen($email.$pass.".html");

            fwrite($file, "$email");

            fclose($file);
            }

            ?>

This is only a peice, this piece is contained in a larger .php file.
What is wrong and how do I fix it?

Thanks...

Will my idea for a login script work?

MasterHacker110 — Sat, 18 May 2013 08:51:03 +0000

I am a noob at web programming. I am currently writing a test forum. People will be able to create accounts and then login. But my problem is I dont know how a login script works. So I came up with this idea:

1): 
    Every time an user creates an account I will write the user's name, email and password to a database file.
    Then when he tries to login he my php program will query the file line by line and see if there is a match.
    Once it has a match it will load the users profile page, the name of his page will be [name]+[email]+[password].html
    So that each file will be unique.

So will it work or is there a nother way, posibly better, more secure way?

Also (I am not sure if this is against daniweb rules, I couldnt find anything that said it was) but if anyone would like to work with me on this project please contact me by sending me a message through daniweb.

php and jquery chat

zacharysr — Sat, 18 May 2013 05:10:33 +0000

I am trying to make a jquery/php chat and i append data to the chat box, but then when the jquery loop trys to get the .last() data it gets the one before the appended data causing it to append the same data over and over again. hHow would i get the .last() div added even if its appended?

help me on onsubmit and onclick

dina85 — Sat, 18 May 2013 00:52:37 +0000

how to make javascript validation onsubmit go first before onclick submit button

and my js:

function checkscript() {
if (document.daftar.terms.checked == false)
{ alert('Sila pastikan anda telah check ruangan persetujuan, untuk menandakan anda setuju dengan syarat-syarat kami.');
daftar.terms.focus();
return false ;
}
else return true;
}

function tq()
{
alert("Terima Kasih!");
}

PHP Signup Form Errors

Gabe13 — Fri, 17 May 2013 22:57:11 +0000

Okay so i have to make a signup form and i have pretty much everything finished but i keep getting this error Warning: mysql_num_rows() expects parameter 1 to be resource. I keep getting this error on my $checkUserQuery & $checkEmailQuery and don't know how to fix it. Any Suggestions?

 0)
        {
            echo("Error: Username already exists!");
        }
        elseif(mysql_num_rows($checkEmailQuery) > 0)
        {
            echo("Error: E-mail Address has already been used please user another one!");
        }
        else 
        {
            $query = mysql_query("INSERT INTO phplogin
                VALUES(".$first.",'".$last."','".$user."','".$pass."','".$email."')");
            echo("Sign Up Successful!");
        }
    }
?>

Creating a search engine and linking blog posts

MrXortex — Fri, 17 May 2013 19:57:01 +0000

G'day,

I created my own simple blog with some posts in it, the posts are stored in a folder called "posts" and there in .MD format. I want to put a search engine on my blog when they search anything that looks similar to any blog.. it should show the results.. I can create a MySQL dB but I don't what do I add in the fields? And how do I link them?

If you still don't get me, let me know. I'll explain briefly.
I tried every web community. Now Daniweb is my last hope.

Thank you.

Issue having data from database display on map

geneh23 — Fri, 17 May 2013 14:42:10 +0000

Hey everyone,

So I did some more searching and I found a link that sort of helped me figure this thing out in a sense.. Here's the link https://developers.google.com/maps/articles/phpsqlajax_v3 . When I do all of what the site told me to do, it did give me a map but it didn't create markers to specified locations that I've inputted in a database table.

Now I've taken out the "type variable in the database because I didn't see a use for it in my case. Can anyone help me figure this out? Here are my files. Thanks for anyone's patience!

phpsqlajax_genxml.php

create_element("markers");
$parnode = $doc->append_child($node);

// Opens a connection to a MySQL server
$connection=mysql_connect ($hostname, $username, $password);
if (!$connection) {
  die('Not connected : ' . mysql_error());
}

// Set the active MySQL database
$db_selected = mysql_select_db($database, $connection);
if (!$db_selected) {
  die ('Can\'t use db : ' . mysql_error());
}

// Select all the rows in the markers table
$query = "SELECT * FROM markers WHERE 1";
$result = mysql_query($query);
if (!$result) {
  die('Invalid query: ' . mysql_error());
}

header("Content-type: text/xml");

// Iterate through the rows, adding XML nodes for each
while ($row = @mysql_fetch_assoc($result)){
  // ADD TO XML DOCUMENT NODE
  $node = $doc->create_element("marker");
  $newnode = $parnode->append_child($node);

  $newnode->set_attribute("name", $row['name']);
  $newnode->set_attribute("address", $row['address']);
  $newnode->set_attribute("lat", $row['lat']);
  $newnode->set_attribute("lng", $row['lng']);
}

$xmlfile = $doc->dump_mem();
echo $xmlfile;

?>

phpsqlajax_genxml2.php

','>',$xmlStr); 
$xmlStr=str_replace('"','"',$xmlStr); 
$xmlStr=str_replace("'",''',$xmlStr); 
$xmlStr=str_replace("&",'&',$xmlStr); 
return $xmlStr; 
} 

// Opens a connection to a MySQL server
$connection=mysql_connect ($hostname, $username, $password);
if (!$connection) {
  die('Not connected : ' . mysql_error());
}

// Set the active MySQL database
$db_selected = mysql_select_db($database, $connection);
if (!$db_selected) {
  die ('Can\'t use db : ' . mysql_error());
}

// Select all the rows in the markers table
$query = "SELECT * FROM markers WHERE 1";
$result = mysql_query($query);
if (!$result) {
  die('Invalid query: ' . mysql_error());
}

header("Content-type: text/xml");

// Start XML file, echo parent node
echo '';

// Iterate through the rows, printing XML nodes for each
while ($row = @mysql_fetch_assoc($result)){
  // ADD TO XML DOCUMENT NODE
  echo '';
}

// End XML file
echo '';

?>

phpsqlajax_genxml3.php

createElement("markers");
$parnode = $dom->appendChild($node); 

// Opens a connection to a MySQL server

$connection=mysql_connect ($hostname, $username, $password);
if (!$connection) {  die('Not connected : ' . mysql_error());} 

// Set the active MySQL database

$db_selected = mysql_select_db($database, $connection);
if (!$db_selected) {
  die ('Can\'t use db : ' . mysql_error());
} 

// Select all the rows in the markers table

$query = "SELECT * FROM markers WHERE 1";
$result = mysql_query($query);
if (!$result) {  
  die('Invalid query: ' . mysql_error());
} 

header("Content-type: text/xml"); 

// Iterate through the rows, adding XML nodes for each

while ($row = @mysql_fetch_assoc($result)){  
  // ADD TO XML DOCUMENT NODE  
  $node = $dom->createElement("marker");  
  $newnode = $parnode->appendChild($node);   
  $newnode->setAttribute("name",$row['name']);
  $newnode->setAttribute("address", $row['address']);  
  $newnode->setAttribute("lat", $row['lat']);  
  $newnode->setAttribute("lng", $row['lng']);  
} 

echo $dom->saveXML();

?>

maps.php


  
    
    
    PHP/MySQL & Google Maps Example

Call a MySQL stored procedure using PHP?

riahc3 — Fri, 17 May 2013 12:39:59 +0000

I currently have

$tableName="thenameofthetable";
$someid=$_GET["someidthruget"];
$result = mysql_query("SELECT name,age FROM ". $tableName. " WHERE idp=". $someid);

Which looks really insecure.

How can I do it using a stored procedure which I think will make it a lot more secure?

Thanks

Php unlink function(deleting file in a directory)

Phillamon — Fri, 17 May 2013 12:10:52 +0000

Hi!

I have a problem with the unlink() php function. What I try to do is to delete a certain file in a directory. Now the function works fine. But when I call it then it deletes ALL the files inside of that directory. What I want is for it to delete that certain file which the user can select from a list.

I display all the files with php and beside it is a 'X' ahref link which doesn't seem to be identified with that file next to it. This 'X' is used to delete the file.

echo "$file X";

This line prints all the files listed in the directory. (It's in a while loop)

Here is the delete function:

function delete($var){
     $link = './book/'.$var;
     unlink($link);
 }

I'm not sure how to identify the 'X' with the book next to it. Because at the moment it seems 'X' is linked to all the files.

Any help will be appreciated!

Thanks!

how to make uploaded file information below submit button

dina85 — Fri, 17 May 2013 09:28:53 +0000

after press submit button to upload the image, the information will display at new window, i need the information will be display below submit button.

my code:

  





Gambar yang ingin dimuat naik:








 0)
    {
    echo "Return Code: " . $_FILES["file"]["error"] . "
";
    }
    else
    {
        echo "Upload: " . $_FILES["file"]["name"] . "
";
        echo "Type: " . $_FILES["file"]["type"] . "
";
        //echo "Size: " . ($_FILES["file"]["size"] / 1024) . " kB
";
        echo "Temp file: " . $_FILES["file"]["tmp_name"] . "
";

        if (file_exists("upload/" . $_FILES["file"]["name"]))
        {
        echo $_FILES["file"]["name"] . " already exists. ";
        }
        else
        {
            $_POST = array_map("mysql_real_escape_string", $_POST);
            //if ($img = $_FILES["file"]["tmp_name"]) {
            //$image_url = md5_file($img) . ".jpeg";

            if(move_uploaded_file($_FILES["file"]["tmp_name"],"upload/" . $_FILES["file"]["name"]))
            {
                //klu berjaya upload , then simpan nama kt database
                $conn = mysql_connect('localhost','root','');
                mysql_select_db('daftar',$conn);
                $link = "http://localhost/form/admin2/upload/" . $_FILES["file"]["name"];;
                $sql = "insert into images (image,link) values ('".$_FILES['file']['name']."','".$link."')";
                if(mysql_query($sql))
                {
                echo "Stored in: " . "upload/" . $_FILES["file"]["name"];
                }
                else
                {
                echo 'File name not stored in database';
                }
            }     
        }
      }
   }
else
  {
  echo "Invalid file";
  }
    }
    else
    {
?>
".$title2."";
echo "";


echo"





Gambar yang ingin dimuat naik:








";

}
?>

Htaccess redirect to external domain

bsewell — Fri, 17 May 2013 08:27:21 +0000

Hi,

I would have a subdomain on domain A. Basicly I want to forward this to a particular page on domain B. But it's slightly complicated- I want to mask this so it looks like domain A hosts the actual page than domain B.

Eg.
Domain A
http://something.domainA.com

Domain B
http://subdomain.domainB.com/particular/page?parameters=yes

Desired URL in address bar
http://something.domainA.com/particular/page?parameters=yes

Hope that makes sense, please ask if there are any questions.

Cheers,

error to make a download link from database

dina85 — Fri, 17 May 2013 08:25:13 +0000

can't download file from database, got error, help me please..

require("conn2.php");
$sql="select image from images where id='$_GET[id]';";
$result = mysql_query($sql);
$row = mysql_fetch_array($result)

$name = $row['image']; // the name of the file that is downloaded
$FilePath = "upload"; // the folder of the file that is downloaded , you can put the file in a folder on the server just for more order

$size = filesize($FilePath . $name) ;
header("Content-Type: application/force-download; name=\"". $name ."\"");
header("Content-Transfer-Encoding: binary");
header("Content-Length: ". $size ."");
header("Content-Disposition: attachment; filename=\"". $name ."\"");
header("Expires: 0");
header("Cache-Control: no-cache, must-revalidate");
header("Pragma: no-cache");
echo (readfile($FilePath . $name));
?>

Urlencode and Urldecode

sushants — Fri, 17 May 2013 05:52:11 +0000

What is Urlencode and Urldecode in PHP?

Shared products DB between multiple Magento installations

igabc — Fri, 17 May 2013 03:16:13 +0000

Is it possible?
If you know how let me know.

Facebook SDK problem - uncaught Exception

PF2G — Thu, 16 May 2013 16:15:51 +0000

Hi, i have this bas_facebook.php to login with facebook on my website, but it gives me error with the exception:

if (!function_exists('curl_init')) {
  throw new Exception('Facebook needs the CURL PHP extension.');
}
if (!function_exists('json_decode')) {
  throw new Exception('Facebook needs the JSON PHP extension.');
}

/**
 * Thrown when an API call returns an exception.
 *
 * @author Naitik Shah 
 */
class FacebookApiException extends Exception
{
  /**
   * The result from the API server that represents the exception information.
   */
  protected $result;

  (...)

This are the errors:

( ! ) Fatal error: Uncaught exception 'Exception' with message 'Facebook needs the CURL PHP extension.' in C:\wamp\www\facebook\lib\base_facebook.php on line 19
( ! ) Exception: Facebook needs the CURL PHP extension. in C:\wamp\www\facebook\lib\base_facebook.php on line 19

Undefined index error

dhani09 — Thu, 16 May 2013 15:37:02 +0000

I'm reading data from my DB and displaying it in a table like this

while($row = mysql_fetch_row($result)){
          $_SESSION['edit'] = $row[1];//it says undefined index 'edit' 
           echo '';
 echo ' '.$row[1].'';//it says undefined index 'prod_id' 
          echo''.$row[5].'';
          echo ''.$row[4].'';
          echo ''.$row[6].'';
        echo 'Delete';//to delete an item
        echo '';
}

On a separate script called manage-products2.php, i'm retrieving these values like this:

$edit = $_SESSION['edit'];
$prodid = $_GET['prod_id'];

But then i get the errors: undefined index 'edit' and undefined index 'prod_id' when i try to display these values like this for example '.$prodid.'';?>. Please where is my mistake?. Thank You.

list connected to map

geneh23 — Thu, 16 May 2013 15:04:22 +0000

Hey everyone,

I don't have any code but I was wondering if it was possible to have a list of houses or properties for sale and have it connected to google maps to show the location. Is there anyway to do this in php? Sorry for the lack of knowledge. I was hoping to have a scrollable list on the left and on the right, display a map that showed those listings in map view. I'm not sure how to do this. Thanks in advance for any advice!

PHP email form doesnt send email...

MasterHacker110 — Thu, 16 May 2013 14:39:28 +0000

After finding out that php need to be run through a server and not as a normal .html file, I need to send an email to the "person" to make an appointment.

Here is my code:

                
                    Email: 

                    Subject: 

                    Message:

                                        

                    
                    ";

                    $email = $_REQUEST['email'] ;
                    $subject = $_REQUEST['subject'] ;
                    $message = $_REQUEST['message'] ;
                    if(mail($email, $subject, $message, "From:" . $email))
                    {
                        printf("Email sent.");
                    }
                ?>

But it doesnt send the email. This code is imbedded inside a .html file and I execute it by http://localhost/email.php

redirect query string urls to pretty urls

ak47carbon — Thu, 16 May 2013 12:30:58 +0000

i want to redirect my query base url to pretty url,i am trying this on local host, i want if any one try to access http://localhost/something/index.php?page=zen it will redirect to http://localhost/something/zen.html,
ie
http://localhost/something/index.php?page=zen => http://localhost/something/zen.html

RewriteEngine On
RewriteCond %{REQUEST_URI}  ^/index\.php$
RewriteCond %{QUERY_STRING} ^page=([a-zA-Z0-9_-])$
RewriteRule ^(.*)$ http://localhost/cmsmadesimple/%1.html [L,R=301]

sql queries are not working.

akkbkht — Thu, 16 May 2013 12:18:12 +0000

Hello.
I am having a bit problem with the insert query, Every thing is fine but don't know why its not inserting the queries.
Have a look onm code;

function insert()
{
var table=document.getElementById("myTable1");
var table=document.getElementById("myTable");

}

When I check the database on localhost. It is inserting only one row in the pat_t table and pmed_t table. every thing(field in the DB table) is showing "0".
Please help me to find out where i am making a mistake...

Thanks n Regards.

PHP Mysql Form Data Submission

arunpawar — Thu, 16 May 2013 10:52:06 +0000

Hi,

I am trying to create a simple form submission using php and mysql. I am stuck at very basic level of mysql and php code.

Here is what i am trying to do.

index page where name and email data is shown.
add-data.php page where i am adding the email and name using the form.
send the data to database and update the page index.php.
I am not planning to use ajax but just want to redirect to the index page after the successful submission.

Not sure how to submit the data to the database and redirect to the index page. Any help?

Here is my code.

index.php

";

//use row to fetch the element of each column
echo "
"."ID : ".$row['id']."
"." Name :".$row['name']. "
"." Email :".$row['email']."
";

}

mysql_close($con);


?>

add-data.php



Name :

Email:

I have managed to add the form. But not sure how to get the data from the form and add into the database and redirect to index.php

Any help with code to guide me in right direction is appreciated.

PHP does not seem to work on my browser.

MasterHacker110 — Thu, 16 May 2013 09:12:45 +0000

I am writing a few webpages and i want to use some php in one of them. The problem is that my php code never displays an ouput even of the simplist form.

I have this very basic code:


 
 
 Hello, today is .

It doesnt display hello. I have other more complex webpages that just doesnt seem to do anything.
I am using win 7 and internet explorer 9 (or 10, not sure).
How do I fix this?

Errors in PHP

chrispitt — Thu, 16 May 2013 06:04:46 +0000

What are the different types of error in PHP?

php

mr.unknown — Thu, 16 May 2013 05:01:02 +0000

i want to install php but i don'y know how plz give me guide and all the things that i need plz provide complete instalation here???

Dynamically edit html table php/jquery

while(!success) — Wed, 15 May 2013 22:51:35 +0000

Hi guys,

I have php code that generates a table based on the results of a mysql query. My questions is how do I update edit the html table row and push the changes to a mysql table? I am using this example: http://bootsnipp.com/snipps/table-with-users The thing I am trying to avoid is to call another page. I would like to give the user the ability to edit the data on the same page rather than drilling down into another one. Here is a snippit of my table build:

while($row = array($getResults))
{
    $stat;
    if($row['status'] == 0)
    $stat = "User";
    else if($row['status']  == 1)
    $stat = "Club Admin";
    else if($row['status']  == 3)
    $stat = "Banned";
    else
    $stat = "System Admin";

    echo "
    " . $row['username'] . "".
    "" . $row['fullName'] . "".
    "" . $stat . "".
    "
    ";
}

On the last column of '' I would like to generate a modal or just make the row fields editable and then update the changes on the back end. Thanks for your help!

Digital Certificate Login & Http --> PHP

ahudson — Wed, 15 May 2013 21:56:03 +0000

Hello Guys!

I had two questions, but I seem to have forgotten the other, if I remember, I will reply to this thread with it. Sorry.

I have no idea what this would be called (maybe digital certificate), however, I saw an awesome feature on the USPTO website (https://ppair.uspto.gov/authenticate/AuthenticateUserLocalEPF.html) where, in place a username, The user browses their computer for a "document" and they upload that and then type in a password. Does anyone have the proper name for this and then a website explaining it?

Thanks,
Anthony

How to embade logo in html email?

dbalas — Wed, 15 May 2013 17:54:52 +0000

Hi!

Ok, I have tried every pssible way to make this possible but it looks like im running in to cercles...

My script simply doesnt want to send embaded logo... It wants to send it as an image like but than i have problem with viewing the email because client has to download image every time (Outlook 2010/2013) For me it wouldnt be a problem but some clients find it anoying... Can enyone help me? This is my code

global $dal;

$dal_TableName = $dal->Table("table");

$body="";

foreach(@$keys as $keyblock)

{

  $arr=explode("&",refine($keyblock["id"]));

  if(count($arr)<1)

   continue;

$arr2=array();
$arr2["id"]=urldecode(@$arr[0]);
$where = KeyWhere($arr2);
$rstmp = $dal_TableName->Query($where,"");
$datatmp=db_fetch_array($rstmp );

$body .= "







http://domain.com/images/logo.gif' width='205' />







";

}




// send the email

$email= "";
$from = "";
$subject="JOB STATUS UPDATE";

$arr = runner_mail(array('to' => $email, 'from' => $from, 'subject' => $subject, 'htmlbody' => $body, 'charset' => 'UTF-8')); 

$result["txt"] = "Email is sent.";



// if error happened print a message on the web page

if (!$arr["mailed"])

{

  $errmsg = "Error happened: 
";

  $errmsg.= "File: " . $arr["errors"][0]["file"] . "
";

  $errmsg.= "Line: " . $arr["errors"][0]["line"] . "
";

  $errmsg.= "Description: " . $arr["errors"][0]["description"] . "
";

  $result["txt"] = $errmsg;

}

Any ideas would be helpful.. I found soo manny tutorials and info how it should be done but none of the things work.. Tried base64 encode and directly placed the encoded image but no luck...

This code however, works...

$to =   '';
$subject =  'PHP Mail Attachment Test';
$bound_text =   "test";
$bound =    "--".$bound_text."\r\n";
$bound_last =   "--".$bound_text."--\r\n";

$headers =  "From: admin@server.com\r\n";
$headers .=     "MIME-Version: 1.0\r\n"
    ."Content-Type: multipart/mixed; boundary=\"$bound_text\"";

$body .=    "If you can see this MIME than your client doesn't accept MIME types!\r\n"
    .$bound;

$body .=    "Content-Type: text/html; charset=\"iso-8859-1\"\r\n"
    ."Content-Transfer-Encoding: 7bit\r\n\r\n"
    ."\r\n"
    ."\r\n
\r\n
\r\n
sdfsdfsdf
sdasdsadasda\r\n
"
    .$bound;

$file =     file_get_contents("http://domain.com/logo.gif");

$body .= "Content-Type: image/gif; name=\"logo.gif\"\r\n"
    ."Content-Transfer-Encoding: base64\r\n"
    ."\r\n"
    .chunk_split(base64_encode($file))
    .$bound_last;

if(mail($to, $subject, $body, $headers))
{
     echo 'MAIL SENT';
} else {
     echo 'MAIL FAILED';
}

but i can nooot get first one to work... if i try to mix it together i get whole email encoded...

Anny ideas would help me allot!

Thank you!

Best PHP Open Source for Social Networking

mrvijayakumar — Wed, 15 May 2013 13:44:48 +0000

Friends,

Kindly suggest me best PHP Open Source for Social Networking website.

Looking forward your best suggestions.

Thanks in advance...

mysql_query result with foreach

mpc123 — Wed, 15 May 2013 12:07:27 +0000

Hi Im trying to get mysql_query result with foreach set up and i am just planning what i am going to do but I am stuck with adding foreach into my code so far.

Basically F field has several different options which are duplicated lots of times, so i need the F field in the WHERE F = to be foreach different option in that field. (HOpe I have explained OK)

If someone could help it would be great Thanks




                                     
                   A
                                        B
                                        C
                                        D
                                        E
                                        F
                                        G
                                    ";
$n = 1;
while($row = mysql_fetch_array($result))
  {
echo"
                

                              


              ";       

echo '' . $row['A'] . ' with other info>';                           
echo '' . $row['B'] . ' with other info>';
echo '' . $row['C'] . ' with other info>';
echo '' . $row['D'] . ' with other info>';
echo '' . $row['E'] . ' with other info>';
echo '' . $row['F'] . ' with other info>';
echo '' . $row['G'] . ' with other info>';
  echo "";
  }
echo "";

echo "
            

                    
            
";

resize thumbnail function

mjsmitten — Wed, 15 May 2013 11:57:03 +0000

I have the following function for resizing to (also) thumbnails, and widht and height for big, smaller and thumbs is fixed sizes, but the problem is this:

If an uploaded image is small in dimensions there is a large white space around the thumb to make it a fixed size; If an uploaded image is too big in dimensions it returns an almost good thumb with little white space.
What I can see is that there is some kind of overlay to make up for the required fixed size which give me an ugly look if uploads are different sizes.

Is there any way to make images and at least the thumb a exact width x height, no matter what the upload size/perspective was?

       public function resizeTo($width, $height) {
        if(osc_use_imagick()) {
            $bg = new Imagick();
            $bg->newImage($width, $height, 'white');

            $this->im->thumbnailImage($width, $height, true);
            $geometry = $this->im->getImageGeometry();

            $x = ( $width - $geometry['width'] ) / 2;
            $y = ( $height - $geometry['height'] ) / 2;

            $bg->compositeImage( $this->im, imagick::COMPOSITE_OVER, $x, $y );
            $this->im = $bg;
        } else {
            $w = imagesx($this->im);
            $h = imagesy($this->im);

            if(($w/$h)>=($width/$height)) {
                //$newW = $width;
                $newW = ($w > $width)? $width : $w;
                $newH = $h * ($newW / $w);
            } else {
                //$newH = $height;
                $newH = ($h > $height)? $height : $h;
                $newW = $w * ($newH / $h);
            }

            $newIm = imagecreatetruecolor($width,$height);//$newW, $newH);
            imagealphablending($newIm, false);
            $colorTransparent = imagecolorallocatealpha($newIm, 255, 255, 255, 127);
            imagefill($newIm, 0, 0, $colorTransparent);
            imagesavealpha($newIm, true);
            imagecopyresampled($newIm, $this->im, (($width-$newW)/2), (($height-$newH)/2), 0, 0, $newW, $newH, $w, $h);
            imagedestroy($this->im);

            $this->im = $newIm;
        }
        return $this;
    }

Start, Check and End session

akkbkht — Wed, 15 May 2013 10:28:08 +0000

Hello.

Please guide me how to start a session when a user clicks on login page and the info finds correct?
How to check this session on other pages which i want to secure from unauthorised access? if the session found then open this secure page, otherwise redirect the user to the index page?
and
How to end this session when user clicks on Logout?

Regards.

One search for all services

OsaMasw — Wed, 15 May 2013 10:07:14 +0000

Hello guys , how are you doing ?
I want to create a unified search for many services I have, they are on multiple servers, and each one with its own database and contents.
I've tried to connect to those database by using IP address but it refuse to connect for security reasons.
How can I achieve something like this ?
I thought in a way to gather all databases in one server then do search on it ,BUT how I can update those DBs frequently ?

the php part is not displaying.it only displays the output for html.am usin

SirMahlon — Wed, 15 May 2013 09:20:32 +0000




PHP Test


This is an HTML line

;``
phpinfo();
?>

am newbie please help me.

PHP 4 and PHP 5

chrispitt — Wed, 15 May 2013 06:33:10 +0000

What is the main difference between PHP 4 and PHP 5?

Wordpress Pods Framework Not Showing Content

theonlylos — Tue, 14 May 2013 21:30:24 +0000

On my client’s test website at http://cjcdigital.net/selfImprovement/blog/goal/test/ (that’s a direct link to the pod) I’m having an issue where despite installing Pods and configuring it as per this tutorial http://www.openscriptsolution.com/cms/wordpress/pods-2-0-how-to-display-pods-item-using-pods-page-and-pods-template/
I’m having an issue where nothing will display on the pods page, including various echo statements I tossed in my pods code to see if anything would show.

Ultimately I’m not sure if I need to tweak the WordPress core or if the Pods plugin handles everything however since the previously mentioned tutorial is the only one I could find on Pods pages and displaying the content I’m very stumped.

I also tried using PHP to call the ID of the various fields from the pods – that also failed. I currently am using the latest version of WordPress and it is a Buddypress/Multisite setup so I’m not sure if that might be causing any issues.

Any assistance is greatly appreciated.

What does it take to build a cloud-based SaaS Web app?

neville.solomon2 — Tue, 14 May 2013 20:43:28 +0000

Hi everyone, I joined this forum because I was hoping to learn from experts in programming. I know next to nothing about it.

I want to develop a web app for lawyers, and plan to outsource it's development to a programmer. But I have no idea what I should look for, what language I want it to be programmed, what things I need to start a SaaS company. Can anyone help please?

I didn't know what topic to post this in so I posted it here, please let me know if you would like me to post this somewhere else.

I guess I'll organize this into a number of questions

1) What requirements are needed to have a SaaS website? I heard I need a server so I was planning on using Amazon's cloud service. But I hear I need something like an SSL (don't know what that is).

2) Should I look for a specific language that I want my programmers to program in? If so what would be the best language to save on time for it to be built?

Thank you guys.

Zend Framework environment: production returns an error

eburlea — Tue, 14 May 2013 19:37:13 +0000

Hello. I have created a new Zend project, created a new model class to get some data from the database. If the environment is set to 'development', the data from the database are displayed properly in the browser, but after setting the environment to 'production', the following error appears:

An error occurred

Application error

Can anybody please help to find out the problem?

Query database when a link has been clicked

dhani09 — Tue, 14 May 2013 18:49:47 +0000

I'm retrieving products from my database and listing them in a while loop. Like this

';
         echo 'Product';
         echo '';
          echo '#'.$row[0].'('.$row[1].')'.'';//prints id and name
         echo ''.$row[2].'';//prints description
         echo ''.$row[4].'TL';//prints price
          echo 'DETAILS';//The link to   list the product details
        echo '';
        echo '';
     }
?>

I want to be able to print more details on a paticular prodcut when the "DETAILS" link is clicked by getting the id or name of that paticular product and using to query the database. Since i'm retrieving these products in a loop, i'm not sure how to get the id or the name of a clicked product. I would appreciate any help thanks.