Hi, I have a simple code written in MIPS assembly that reads an integer from a user and displays it to the screen. The code is as follows:
main: la $a0, in_msg li $v0, 4 syscall li $v0, 5 syscall move $t0, $v0 la $a0, out_msg li $v0, 4 syscall move $a0, $t0 li $v0, 1 syscall li $v0, 10 syscall .data in_msg: .asciiz "Input: " out_msg: .asciiz "\nOutput:\n-------\n"
How can I convert this decimal value to a binary? Thank you in advance.
I am currently trying to work on this. If anyone can help...it would be greatly appreciated.
Post what you've got and what part of it is giving you trouble.
I figured it out:
# Brent Wagner
.data ask_str1: .asciiz "Enter a number PLEASE: " result_str: .asciiz "" .align 2
.text .globl __start
__start: # ask and store the first number li $v0, 4 la $a0, ask_str1 syscall li $v0, 5 syscall move $a0, $v0
jal print_bin # New Line li $v0, 11 li $a0, 10 syscall j __start
print_bin:
add $t0, $zero, $a0 # put our input ($a0) into $t0 add $t1, $zero, $zero # Zero out $t1 addi $t3, $zero, 1 # load 1 as a mask sll $t3, $t3, 31 # move the mask to appropriate position addi $t4, $zero, 32 # loop counter loop:
and $t1, $t0, $t3 # and the input with the mask beq $t1, $zero, print # Branch to print if its 0 add $t1, $zero, $zero # Zero out $t1 addi $t1, $zero, 1 # Put a 1 in $t1 j print print: li $v0, 1 move $a0, $t1 syscall srl $t3, $t3, 1 addi $t4, $t4, -1 bne $t4, $zero, loop
jr $ra
could someone briefly describe how this MIPS code works please?
i get the syscalls, and the registers and all.. but how does it actually convert the decimal into binary? I cant seem to understand the logic behind it..
