Split string into char array

[vtskillz]

Hi, I was wonder if someone could give me some help with my program

I have a variable:

char *insert = "abcdefgh"

and i want to split that into chars like so, 'a', 'b', 'c', 'd', etc.

I've tried ToCharArray(), but that doesnt seem to work

[Narue]

>I have a variable:
>char *insert = "abcdefgh"
>and i want to split that into chars like so, 'a', 'b', 'c', 'd', etc.
Uh, you're done. A string literal is an array of const char and except for modification, sizeof, and address-of you can use the pointer as if it were an array. If you need an actual array, you can do this:

char insert[] = "abcdefgh";

C doesn't have a special string type like Java, so when you're using a string in C, you're really using an array.

[gerard4143]

Hi, I was wonder if someone could give me some help with my program

I have a variable:

char *insert = "abcdefgh"

and i want to split that into chars like so, 'a', 'b', 'c', 'd', etc.

I've tried ToCharArray(), but that doesnt seem to work

a string in c/c++ is a array of characters so extract then like so

#include

int main(int argc, char**argv)
{
char *insert = "abcdefg";

for (int i = 0; i < 7; ++i)
std::cout<

[Aia]

This is C forum. Not C/C++ ;)
Take the time to read how properly tag your code so instead of looking like this:
#include

int main(int argc, char**argv)
{
char *insert = "abcdefg";

for (int i = 0; i < 7; ++i)
std::cout<#include <iostream>

int main(int argc, char**argv)
{
char *insert = "abcdefg";


for (int i = 0; i < 7; ++i)
std::cout<<insert[i]<<"\n";

}

For how to do that read here and here
I don't promise that it'll fix your code, but it'll make it more readable.

[naej]

hmm try this
but i'm not sure i'm just a first yr student

char a
char b
.
.
.
char g

hee hee

we're not finished discussing array yet

hmm

[Narue]

>but i'm not sure i'm just a first yr student
If you're not sure, don't answer because you're more likely to lead people astray with bad advice than do any good.

>hee hee
Oh, I get it. You're joking. Because anybody who would jump into a thread over a year after it unofficially ended and offer something as inane as your "help" is either trying to get a laugh or is a complete retard. I don't think you're a complete retard (yet), so it must be a pitiful attempt at humor. :icon_rolleyes:

[Arcaiz]

If you really want to make an array of char without '\0' at the end of it. You could make something like this

#include<stdio.h>

int main()
{
char *insert = "abcdefgh";
char outsert[8]; //I use 8 because abcdefgh contains 8 char
int i;

for (i=0;i<8;i++)
{
outsert[i] = insert[i];
}

return 0;
}

But i can't imagine what you only can do with array of char. Please answer me.

[harishug]

char *insert = "abcdefgh";

char outsert[8]; //I use 8 because abcdefgh contains 8 char
int i;
for (i=0;i<8;i++)
{
outsert[i] = insert[i];
}
in array outsert you will found array of character .......

[gerard4143]

you can do like this: char[] values = {'a','b','c','d','e','f','g'}; then address to each value using the vector(array) like this:

values[0],values[1],etc. (a,b,etc.) you might want to see this tutorial that has also some detailes about char array: http://goldwin-advertising.ro/index.php?option=com_content&view=article&id=10:splitstring&catid=3:howto&Itemid=5

Yeah they probably figured that out 3 years ago when the question was posted.

[arunsolo1984]

char str[] = "now # is the time for all # good men to come to the # aid of their country";
char delims[] = "#";
char *result = NULL;
result = strtok( str, delims );
while( result != NULL ) {
printf( "result is \"%s\"\n", result );
result = strtok( NULL, delims );
}

OUTPUT:
result is "now "
result is " is the time for all "
result is " good men to come to the "
result is " aid of their country"