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Oct 5th, 2004

Array with names

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As this is my first post on this forum I want to say "Hello!" to everybody and I hope that we'll help each other as much as we can and we'll be very good friends.

So, this is my problem ( a rather simple one but I don't know how to resolve it ) : I found a exercise that wants me to have a array with some student's names and another array with their grades ( numerical grades ) at informatics. :eek:

Example: X=('John','Michelle','Jack','Robert'); Y=(10,5,6,7);

My question is: how do I put those names in the array so that a name ( let's say John ) should occupy a single position? For example: X[1]= 'John'; X[2]='Michelle' , etc. I have to read them from the keyboard , of course.

Thank you very much for your time and eventual help!

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djextazy

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Oct 5th, 2004

Re: Array with names

Hi djextazy,
Well come to DaniWeb ,
if u want to have full name at one location of the array
u have to declare array as a two dimensional array,
i-e its declaration would be like this
char [][];
or u can also use array of pointers , but if u r new to C++ u should use
two dimension array
I hope it resolved ur issue but still if their is some problem feel free to ask again.
Fahad

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Oct 5th, 2004

Re: Array with names

Hi,
The declaration should be like this
char X[][];

Fahad

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Oct 5th, 2004

Re: Array with names

Quote originally posted by fahad ...

Hi,
The declaration should be like this
char X[][];

Fahad

Do you mean something like
a[1][1] = "Victor";
a[2][2] = "Jose"; ???

I mean:
char a[30][30],i,n;
cout<<"n= "; cin>>n;
for(i=1;i<=n;i++) { cout<<"Give "<<i<<"-st name: "; cin>>a[i]; }

Correct me please if I am mistakening. Thank you for your help!

djextazy

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Re: Array with names

Hi,
Yes u r right ,
try this............and if still getting some problems discuss it again
Fahad

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Oct 5th, 2004

Re: Array with names

An array of size N will be indexed from 0 to N-1. The standard idiomatic for loop is then like this:

(Toggle Plain Text)

for ( int i = 0; i < N; ++i )

Dave Sinkula

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Oct 5th, 2004

Re: Array with names

It works , altought the exercise says that I should use two arrays , one for the names and one for the grades. Oh well , it's important that it works ...

Thank you very much!

djextazy

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Re: Array with names

Quote originally posted by Dave Sinkula ...

An array of size N will be indexed from 0 to N-1. The standard idiomatic for loop is then like this:
(Toggle Plain Text)
for ( int i = 0; i < N; ++i )
for ( int i = 0; i < N; ++i )

It works fine as for(i=1;i<=n;i++) . Trust me. :lol:

djextazy

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Re: Array with names

>It works fine as for(i=1;i<=n;i++) .
Yes it does. But then again, so does this:

C Syntax (Toggle Plain Text)
i = 9;
loopie:
  // Do stuff
  if ( --i > 9 - n )
    goto loopie;
i = 9;
loopie:
  // Do stuff
  if ( --i > 9 - n )
    goto loopie;

Most programmers prefer to use the idiomatic approach because it's easier to use, easier to get used to, and common enough that you don't have to get used to something else everytime you read a different person's program.

Narue

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Re: Array with names

Quote originally posted by djextazy ...

It works fine as for(i=1;i<=n;i++) . Trust me. :lol:

Do you see the bug here?

C Syntax (Toggle Plain Text)
#include <stdio.h>
 
 #define N 10
 
 int main()
 {
    int i, array[N] = {1,2,3,4,5,6,7,8,9,10};
    for ( i = 1; i <= N; ++i )
    {
 	  printf("array[%d] = %d\n", i, array[i]);
    }
    return 0;
 }
#include <stdio.h>
 
 #define N 10
 
 int main()
 {
    int i, array[N] = {1,2,3,4,5,6,7,8,9,10};
    for ( i = 1; i <= N; ++i )
    {
 	  printf("array[%d] = %d\n", i, array[i]);
    }
    return 0;
 }

Dave Sinkula

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