Simple Calculator

[mikedd]

Write a calculator program that lets users enter a simple mathematic operation and display the results as in the sample output shown below (bold text indicates user input).

Calculate: 92+1
Result = Ninety Three

Calculate: 92, 000 + 1
Result = Ninety Two Thousand

Calculate: 92, 000.01 + 1
Result = Ninety Two Thousand and One Point Zero One

Calculate: 92, 000.01 * 1 + 1 / 1
Result = Ninety Two Thousand and One Point Zero One

Your program MUST at least be able to interpret the following operators:
• +
• -
• /
• *
• %
• >
• <
• >=
• <=

p/s:pls can someone help me solve this problem and i am currently using knoppix software to solve this problem..pls help me..thx..

[Salem]

You also forgot to read these as well
http://www.daniweb.com/forums/announcement118-2.html
http://www.daniweb.com/forums/thread78060.html

Now, which bit are you really stuck on?

[jephthah]

sure, sure. i've got nothing better to do than do your homework.

shall i also write your report, bind it, and mail it first class to your instructor?

[mikedd]

i do not know how to change the result into character..Can teach me?

[Salem]

Consider this
23 = Twenty three
123 = One hundred and twenty three
123,000 = One hundred and twenty three thousand

So you need to think about (eventually)
- splitting into groups of 1000
- splitting hundreds from tens and units

But start simple, try to code up converting 1 to 99.

[mike_g]

If I was doing this I think I would use sprintf to convert the numeric result to a string then parse the characters building the words from it:
http://www.cplusplus.com/reference/clibrary/cstdio/sprintf.html

[mikedd]

#include <stdio.h>

int main()
{
   int   invalid_operator = 0;
   char  operator1;
   float number1, number2, result;

   printf( "Enter two numbers and an operator in the format\n" );
   printf( "number1 operator number2\n" );
   scanf( "%f %c %f", &number1, &operator1, &number2 );

   switch ( operator1 ) {
      case '*' :
         result = number1 * number2;
         break;
      case '/' : 
         result = number1 / number2; 
         break;
      case '+' :
         result = number1 + number2; 
         break;
      case '-' :
         result = number1 - number2; 
         break;
      default :
         invalid_operator = 1;
   }
      
   switch ( invalid_operator ) {
      case 1 :
         printf( "Invalid operator.\n" ); 
         break;
      default :
         printf( "%f %c %f is %f\n",
            number1, operator1, number2, result );
   }
       
   return 0;
}

p/s:said i hav done this programe..But i do not know how to make the calculated output into character.Can someone pls show me how to make it?

[mike_g]

If I was doing this I think I would use sprintf to convert the numeric result to a string then parse the characters building the words from it: http://www.cplusplus.com/reference/c...o/sprintf.html

Have you tried converting the result to a string yet? that should make a good first step.

[mikedd]

but the problem now is i do not even know how to convert a single integer into a character.can u pls at least show me how to convert an integer into a character?

[Nick Evan]

The following example-code will 'convert' an int into a char

int number = 97; //97 is the ascii value of 'a' 
char character = (char)number; // "convert" it
printf("%c", character);

A char and an int are both numbers, they just differ in the way us humans read them :) ascii-table

[mikedd]

but the output above will printout an 'a' output.How do i make it to printout the word ninety seven?

[Salem]

char *ones[ ] = { "zero", "one", "two", "three" };
char *tens[ ] = { "none", "ten", "twenty" };
int n = 23;
printf( "%s %s", ones[n%10], tens[n/10] );

It's too big a clue to explain, you'll just have to figure it out.

[mike_g]

Since the result is a float I still reckon the easiest way to go about it would be to use sprintf and parse the string, but the op dosent seem to be interested in that idea :/

[mikedd]

but the output above is an 'a'.how do i program it to make the output ninety seven?pls ignore this msg..i post wrongly oredi

[Salem]

So that's all you've got to show for another day's help, and maybe you thinking about the problem some more (or maybe - shock horror - actually trying something for yourself).

Just post the same question again.

[mikedd]

yay finally i did it but i still facing problem on the decimal number.Gt any good idea to solve it?

[mike_g]

Yes, but first you are going to have to learn how to read. You could practice with this . Then learn how to converse with other people coherently. Hopefully the reading material should help you with that too.

[mikedd]

...Cmon la tel me how to make the decimal putput tat read the output point zero one?

[Aia]

...Cmon la tel me how to make the decimal putput tat read the output point zero one?

I knew I should have keep my copy of the Rosetta Stone.

[Salem]

> .Gt any good idea to solve it?
Yeah, exactly the same way that you solved the part before the decimal point.
It's all the same technique.