Draw sin curve w/ user input, how to code sin()?

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I am trying to get a program to draw a sine curve (from 0 to 2pi). It takes 8 lines to draw the complete curve. However, the user can choose to use up to 100 lines to make the curve smoother. How do I get the program to calculate that? I thought of using a counter to count through until it gets to the number of user chosen lines (m_iSample), but then I don't know how to calculate it. I just finished trig too, darn it.

for (count = 0; count<=m_iSample; ++count) {
double iSinValue=sin(count * PI);//do the sin calculation
int iFinalSinValue=iSinValue * 200;//convert result so that it will display correctly
pDC->LineTo( ??? , iFinalSinValue);//draw the line
}
Thanks Again!
Reagan

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Reagan

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Dec 6th, 2004

Re: Draw sin curve w/ user input, how to code sin()?

Ok, bit by bit :

y=f(x) is the curve.

In our case, f is sin(), y is iSinValue, which makes x = count*PI.

What's not clear?

nvanevski

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