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Feb 23rd, 2005

GetKeyState syntax

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At the beginning of an "IF" statement, I have:

C Syntax (Toggle Plain Text)
if (SHORT GetKeyState(int 48)==1){
if (SHORT GetKeyState(int 48)==1){

When compiling I get a syntax error just before the constant, and I've played around with it a bit, but haven't found what to do.

Could someone fix this or explain to me why it's not working?

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Feb 23rd, 2005

Re: GetKeyState syntax

Here is the MSDN entry for the function:
GetKeyState()

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Feb 23rd, 2005

Re: GetKeyState syntax

Prototypes tell you the expected types, but when you call a function you don't include the type -- the type is inherently part of the variable or literal being used in the call. That is,

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if (GetKeyState(48)==1){
if (GetKeyState(48)==1){

Dave Sinkula

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Feb 23rd, 2005

Re: GetKeyState syntax

I had realized that a bit after I posted, but I seem to be getting the low bit instead of the high bit, which is the one I need.

Isn't there a HIGH() operator or something?

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Feb 24th, 2005

Re: GetKeyState syntax

How can I take only the high order bit from that command?

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Feb 24th, 2005

Re: GetKeyState syntax

>How can I take only the high order bit from that command?
Here's a slight push in the direction of a solution:

C Syntax (Toggle Plain Text)

#define bit(i) (1UL << (i))

You can use it to test a certain bit by ANDing the result of bit(n) with the value:

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if ((GetKeyState(48) & bit(7)) != 0)
if ((GetKeyState(48) & bit(7)) != 0)

Narue

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