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Jul 14th, 2009

If and while statement problem (Beginner)

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//This program will ask the user for k, m and n.
//k should not be equal to 1.
//Output all numbers multiple by k between m and n. (ex. k=2,m=5,n=20 output should be 6 8 10...18)

*problem*
How to exit this program when the user assigned k to 1 ?
And why is it that when i assign an even-number to k it will output until n. And n should not appear on the screen. Actually this was already answered by our teacher but i want to know how.

(Toggle Plain Text)

#include <stdio.h>

int main()
{
    
    int k, m, n;
    
   
    printf("Enter a value for k: ");
    scanf("%d",&k);
    printf("Enter a value for m: ");
    scanf("%d",&m);
    printf("Enter a value for n: ");
    scanf("%d",&n);
    
  
if  (k <= 1 )


printf("k should not be equal to one \n");
    
    if ( m < n)
    {       
            while ( m < n )
            {
            m=m+1;
              if ((m%k)==0)
              {
                   printf("\n %d",m);
                   
              }
            }
         
    }

    if (m>n)
    printf("\n m should not be greater to n");
    
    
    getchar();  
    getchar();  
    return 0;
}

Last edited by DoEds; Jul 14th, 2009 at 10:46 am.

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DoEds

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Jul 14th, 2009

Re: If and while statement problem (Beginner)

Oh i figured out the problem when k is assign to 1.

(Toggle Plain Text)

if ( k <= 1)
    printf("\n k should not be equal to 1");
    
    
    if (k > 1 && m < n)
    {       
            while (k > 1 && m < n )
            {
            m=m+1;

Last edited by DoEds; Jul 14th, 2009 at 10:42 am.

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Jul 14th, 2009

Re: If and while statement problem (Beginner)

Why would you want to wrap this if around the while:

(Toggle Plain Text)

if (k > 1 && m < n)
{
  while(k > 1 && m < n)
  {
  
  }
}

As you can see both conditions are the same, so you can leave out this if

Edit::
Like this:

C Syntax (Toggle Plain Text)
while(k > 1 && m < n)
{
 
}
while(k > 1 && m < n)
{

}

This is possible because the instructions in the while loop's body will only get executed when the condition is true (in this case the condition is: k > 1 && m < n, so if this condition isn't true at the beginning of the while loop, your program will just skip over all the instructions inside the loop's body, and proceed executing the first statement after the while loop (if there's one))

Last edited by tux4life; Jul 14th, 2009 at 11:01 am. Reason: fix broken code tag

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Jul 14th, 2009

Re: If and while statement problem (Beginner)

Click to Expand / Collapse Quote originally posted by DoEds ...

*problem*
How to exit this program when the user assigned k to 1 ?

Use exit() function

http://www.cprogramming.com/fod/exit.html

tuse

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Jul 14th, 2009

Re: If and while statement problem (Beginner)

Click to Expand / Collapse Quote originally posted by tuse ...

Use exit() function

http://www.cprogramming.com/fod/exit.html

Possible, but if your main function contains your whole program, then I would rather suggest you to use: return exit_code; instead of the exit() function

Last edited by tux4life; Jul 14th, 2009 at 11:18 am.

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Jul 19th, 2009

Re: If and while statement problem (Beginner)

Thanks a lot man...
I've figured out this problem already...
I put a another condition in the mudulo statement

(Toggle Plain Text)

 if ((m%k)==0 && n != m)
              {
                   printf("\n %d",m);
                   
              }

Last edited by DoEds; Jul 19th, 2009 at 12:56 am.

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