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C Discussion Thread
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Nov 4th, 2009

left operand must be l-value

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what's wrong here?

c Syntax (Toggle Plain Text)
typedef struct person
{
	int age;
	char name[50];
};
 
int main()
{
	struct person test;
 
	test.age = 20;
	test.name = "Test";
 
	return 0;
}
typedef struct person
{
	int age;
	char name[50];
};

int main()
{
	struct person test;

	test.age = 20;
	test.name = "Test";
	
	return 0;
}

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fatihpiristine

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Nov 4th, 2009

Re: left operand must be l-value

anyways i fixed it myself

here is the solution

c Syntax (Toggle Plain Text)
 
typedef struct
{
	int age;
	char *name[50];
} Person;
 
Person newperson(char *name, int age)
{
	Person temp;
	*temp.name = name;
	temp.age = age;
	return temp;
}
 
int main()
{
	Person list[50], ttt;
 
	list[0] = newperson("Test", 20);
 
 
 
	*ttt.name = "ASDF";
 
 
 
	return 0;
}
typedef struct
{
	int age;
	char *name[50];
} Person;

Person newperson(char *name, int age)
{
	Person temp;
	*temp.name = name;
	temp.age = age;
	return temp;
}

int main()
{
	Person list[50], ttt;

	list[0] = newperson("Test", 20);

	

	*ttt.name = "ASDF";

	
	
	return 0;
}

fatihpiristine

Reputation Points: 6

Solved Threads: 19

Posting Whiz in Training

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Nov 4th, 2009

Re: left operand must be l-value

Use strcpy to copy a string. You've got more going wrong in that code, though. I think you're after something that might look a bit like this:

C Syntax (Toggle Plain Text)
#include <string.h>
 
typedef struct
{
	int age;
	char name[50];
} Person;
 
Person newperson(char *name, int age)
{
	Person temp;
	strcpy(temp.name, name);
	temp.age = age;
	return temp;
}
#include <string.h>

typedef struct
{
	int age;
	char name[50];
} Person;

Person newperson(char *name, int age)
{
	Person temp;
	strcpy(temp.name, name);
	temp.age = age;
	return temp;
}

Dave Sinkula

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long time no c

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since Apr 2004

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Nov 4th, 2009

Re: left operand must be l-value

thanks for the remark. that was the thing i was trying to remember.

fatihpiristine

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Posting Whiz in Training

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since Sep 2007

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