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May 15th, 2005

convert seconds to minutes, hours, days, months, years, etc.

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Is there a standard algorithm that can take the output of difftime (which is in seconds) and use it to print out the number of minutes, hours, days, weeks, etc.?

I was going to try and calculate this myself by using the modulo, etc. but thought that something might pre-exist..

winbatch

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May 15th, 2005

Re: convert seconds to minutes, hours, days, months, years, etc.

There's probably a function or set of functions that do what you want, but nothing in the standard library. It would be easier to just do it manually since the algorithm isn't that hard.

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May 15th, 2005

Re: convert seconds to minutes, hours, days, months, years, etc.

Got anything handy?

winbatch

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May 15th, 2005

Re: convert seconds to minutes, hours, days, months, years, etc.

It's as simple as this, more or less:

C Syntax (Toggle Plain Text)
#include <iostream>
 
int main()
{
  double seconds = 1234567;
  double minutes = seconds / 60;
  double hours = minutes / 60;
  double days = hours / 24;
  double weeks = days / 7;
  double months = weeks / 52;
  double years = months / 12;
 
  std::cout.setf(std::ios_base::fixed, std::ios_base::floatfield);
  std::cout.precision(3);
 
  std::cout << "Seconds: " << seconds << '\n'
    << "Minutes: " << minutes << '\n'
    << "Hours: " << hours << '\n'
    << "Days: " << days << '\n'
    << "Weeks: " << weeks << '\n'
    << "Months: " << months << '\n'
    << "Years: " << years << '\n';
}
#include <iostream>

int main()
{
  double seconds = 1234567;
  double minutes = seconds / 60;
  double hours = minutes / 60;
  double days = hours / 24;
  double weeks = days / 7;
  double months = weeks / 52;
  double years = months / 12;

  std::cout.setf(std::ios_base::fixed, std::ios_base::floatfield);
  std::cout.precision(3);

  std::cout << "Seconds: " << seconds << '\n'
    << "Minutes: " << minutes << '\n'
    << "Hours: " << hours << '\n'
    << "Days: " << days << '\n'
    << "Weeks: " << weeks << '\n'
    << "Months: " << months << '\n'
    << "Years: " << years << '\n';
}

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May 15th, 2005

Re: convert seconds to minutes, hours, days, months, years, etc.

Dogtree,

Thanks - I was planning however, to only show minutes if it was over 60 seconds, only show hours if it was over 60 minutes, etc.. That's where it got a little hairy..

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May 16th, 2005

Re: convert seconds to minutes, hours, days, months, years, etc.

Not hairy at all. If integral division results in 0, don't show it:

C Syntax (Toggle Plain Text)
#include <functional>
#include <iostream>
#include <string>
 
template <typename Pred>
void print_if(int part, Pred p, std::string msg = "")
{
  if (p(part))
    std::cout << msg << part << '\n';
}
 
int main()
{
  int seconds = 1234567;
  int minutes = seconds / 60;
  int hours = minutes / 60;
  int days = hours / 24;
  int weeks = days / 7;
  int months = weeks / 52;
  int years = months / 12;
 
  std::cout.setf(std::ios_base::fixed, std::ios_base::floatfield);
  std::cout.precision(3);
 
  print_if(seconds, std::bind2nd(std::greater<int>(), 0), "Seconds: ");
  print_if(minutes, std::bind2nd(std::greater<int>(), 0), "Minutes: ");
  print_if(hours, std::bind2nd(std::greater<int>(), 0), "Hours: ");
  print_if(days, std::bind2nd(std::greater<int>(), 0), "Days: ");
  print_if(months, std::bind2nd(std::greater<int>(), 0), "Months: ");
  print_if(years, std::bind2nd(std::greater<int>(), 0), "Years: ");
}
#include <functional>
#include <iostream>
#include <string>

template <typename Pred>
void print_if(int part, Pred p, std::string msg = "")
{
  if (p(part))
    std::cout << msg << part << '\n';
}

int main()
{
  int seconds = 1234567;
  int minutes = seconds / 60;
  int hours = minutes / 60;
  int days = hours / 24;
  int weeks = days / 7;
  int months = weeks / 52;
  int years = months / 12;

  std::cout.setf(std::ios_base::fixed, std::ios_base::floatfield);
  std::cout.precision(3);

  print_if(seconds, std::bind2nd(std::greater<int>(), 0), "Seconds: ");
  print_if(minutes, std::bind2nd(std::greater<int>(), 0), "Minutes: ");
  print_if(hours, std::bind2nd(std::greater<int>(), 0), "Hours: ");
  print_if(days, std::bind2nd(std::greater<int>(), 0), "Days: ");
  print_if(months, std::bind2nd(std::greater<int>(), 0), "Months: ");
  print_if(years, std::bind2nd(std::greater<int>(), 0), "Years: ");
}

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May 16th, 2005

Re: convert seconds to minutes, hours, days, months, years, etc.

This isn't the output I'm seeking - what you've provided is the conversion between seconds and each parameter (hours, minutes, etc.)

basically, if the minutes is above 60 I don't want to 61, etc.

This is how I ended up doing it:

C Syntax (Toggle Plain Text)
string Date::operator - ( const Date& b )
{
double diff = difftime( rawtime, b.rawtime );
if ( diff < 0 )
diff*=-1;
ostringstream o;
 
 
if ( diff < 60 )
{
o<<diff<<" SECOND(S)"; 
return o.str();
}
 
if ( diff < 3600 )
{
	int min = (int)diff/60;
	int sec= (int)diff%60;
	o<<min<<" MINUTE(S), "<<sec<< " SECOND(S)"; 
}
else if ( diff < 86400 ) /* DAY */
{
	 int hours = (int) diff/3600;
	 int hourRemainder = (int)diff%3600;
	 int min = (int)hourRemainder/60;
	 int sec= (int)diff%60;
	 o<<hours<< " HOUR(S), "<< min<< " MINUTE(S), "<<sec<< " SECOND(S)"; 
}
else if ( diff < 31536000 ) /* YEAR */ 
{
	 int days = (int) diff/86400;
	 int daysRemainder = (int)diff%86400;
	 int hours = (int) daysRemainder/3600;
	 int hourRemainder = (int)(diff - 86400)%3600;
	 int min = (int)hourRemainder/60;
		int sec= (int)diff%60;
		o<<days<<" DAY(S), "<<hours<< " HOUR(S), "<< min<< " MINUTE(S), "<<sec<< " SECOND(S)"; 
}
else
{
	int years = (int) diff/31536000;
	int yearsRemainder = (int) diff%31536000;
	int days = (int) yearsRemainder/86400;
	int daysRemainder = (int)diff%86400;
	int hours = (int) daysRemainder/3600;
	int hourRemainder = (int)(diff - 86400)%3600;
	int min = (int)hourRemainder/60;
	 int sec= (int)diff%60;
	 o<<years<<" YEAR(S), "<<days<<" DAY(S), "<<hours<< " HOUR(S), "<< min<< " MINUTE(S), "<<sec<< " SECOND(S)"; 
}
 
 
 
return o.str();
}
string Date::operator - ( const Date& b )
{
double diff = difftime( rawtime, b.rawtime );
if ( diff < 0 )
diff*=-1;
ostringstream o;
 
 
if ( diff < 60 )
{
o<<diff<<" SECOND(S)"; 
return o.str();
}
 
if ( diff < 3600 )
{
	int min = (int)diff/60;
	int sec= (int)diff%60;
	o<<min<<" MINUTE(S), "<<sec<< " SECOND(S)"; 
}
else if ( diff < 86400 ) /* DAY */
{
	 int hours = (int) diff/3600;
	 int hourRemainder = (int)diff%3600;
	 int min = (int)hourRemainder/60;
	 int sec= (int)diff%60;
	 o<<hours<< " HOUR(S), "<< min<< " MINUTE(S), "<<sec<< " SECOND(S)"; 
}
else if ( diff < 31536000 ) /* YEAR */ 
{
	 int days = (int) diff/86400;
	 int daysRemainder = (int)diff%86400;
	 int hours = (int) daysRemainder/3600;
	 int hourRemainder = (int)(diff - 86400)%3600;
	 int min = (int)hourRemainder/60;
		int sec= (int)diff%60;
		o<<days<<" DAY(S), "<<hours<< " HOUR(S), "<< min<< " MINUTE(S), "<<sec<< " SECOND(S)"; 
}
else
{
	int years = (int) diff/31536000;
	int yearsRemainder = (int) diff%31536000;
	int days = (int) yearsRemainder/86400;
	int daysRemainder = (int)diff%86400;
	int hours = (int) daysRemainder/3600;
	int hourRemainder = (int)(diff - 86400)%3600;
	int min = (int)hourRemainder/60;
	 int sec= (int)diff%60;
	 o<<years<<" YEAR(S), "<<days<<" DAY(S), "<<hours<< " HOUR(S), "<< min<< " MINUTE(S), "<<sec<< " SECOND(S)"; 
}
 
 
 
return o.str();
}

Here's an example in action:
NOW:05/16/05 20:39:18
LATER:05/17/07 21:58:21
Difference:2 YEAR(S), 1 DAY(S), 1 HOUR(S), 19 MINUTE(S), 3 SECOND(S)

winbatch

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May 16th, 2005

Re: convert seconds to minutes, hours, days, months, years, etc.

I wasn't trying to solve your problem for you, sorry if I gave you that impression. I'm glad you figured it out without my help anyway.

Dogtree

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May 17th, 2005

Re: convert seconds to minutes, hours, days, months, years, etc.

Well have you guys ever heard of the MOD (%) function.

Well let's say the count was 153 seconds.

C Syntax (Toggle Plain Text)
char *print_time( int time )
{
  static char buf[20];
  char tmp[200];
 
  buf[0] = '\0';
 
  sprintf( tmp, "%d ", time );
  strcat( buf, tmp );
 
  return buf;
}
 
int main( void )
{
  int time[1];
 
  int seconds = 153;
 
  time[0] = seconds % 60;          // time[0] will equal 153 - 60 - 60, this will go on
                                   // until there isn't 60 left to subtract, then return
                                   // what is left
  seconds = seconds - time[0];     // we have the seconds so remove it
  time[1] = ( seconds / 60 ) % 60; // we divide by 60 cause there is 60 secs in a min.
                                   // the same will happen here as above but seeing
                                   // the seconds was 120 (153 - 33) it will return 2
 
  printf( "%s%s%s%s%s\n",
    time[1] > 0 ? print_time( time[1] ) : "", time[1] > 0 ? "minutes" : "",
    time[1] > 0 ? " and " : "", 
    time[0], " seconds" );
 
  return 0;
}
char *print_time( int time )
{
  static char buf[20];
  char tmp[200];

  buf[0] = '\0';

  sprintf( tmp, "%d ", time );
  strcat( buf, tmp );

  return buf;
}

int main( void )
{
  int time[1];

  int seconds = 153;

  time[0] = seconds % 60;          // time[0] will equal 153 - 60 - 60, this will go on
                                   // until there isn't 60 left to subtract, then return
                                   // what is left
  seconds = seconds - time[0];     // we have the seconds so remove it
  time[1] = ( seconds / 60 ) % 60; // we divide by 60 cause there is 60 secs in a min.
                                   // the same will happen here as above but seeing
                                   // the seconds was 120 (153 - 33) it will return 2

  printf( "%s%s%s%s%s\n",
    time[1] > 0 ? print_time( time[1] ) : "", time[1] > 0 ? "minutes" : "",
    time[1] > 0 ? " and " : "", 
    time[0], " seconds" );

  return 0;
}

Basically this will return x minutes and x seconds if both are bigger than 0 or just the seconds, it is very adaptable, now using 153 seconds it would return 2 minutes and 33 seconds.

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May 17th, 2005

Re: convert seconds to minutes, hours, days, months, years, etc.

(Yes, I know - see my post #7)

winbatch

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