You should try Code::Blocks, Dev-C++ has become very out-of-date, but the debugger on both works the same.

http://wiki.codeblocks.org/index.php?title=Debugging_with_Code::Blocks

You can setup break-points to step through, and a watch on those variables.

uhh.... No. Debugging is the act of resolving those issues and no one's going to do it for you(unless you like spending money).

Try this code..

# include <stdio.h>
# define MAX 100
int main(void)
{
    int oddcount, evencount;
    int array[MAX],i,n;

    printf("\n Enter Array Size (Between 1 to %d ): ",MAX);

    scanf("%d", &n); // User enters Array Size

    for(i = 0; i < n; i++)
    {
       printf("\n Enter %d value: ",i+1);
       scanf("%d", &array[i]); // Allows user to enter values into the Array
       }

    putchar('\n');
    printf("\nArray Values: ");
    for(i = 0; i < n; i++)
    {
       printf("\n [%d] value is %3d ", i+1, array[i]); //Prints out the array -- this is where program stops it should carry on down
    }
     //**************************************//
    oddcount = 0;
    evencount = 0;

     for (i = 0; i < n; i++) // Code determines wheter odd or even.

     {
          if (array[i] % 2 != 0)
          {
            //printf("\nThe number %d Is Odd.\n", i);
            oddcount ++;
          }

          else
          {
            //printf("\nThe number %d Is Even.\n",i);
            evencount ++;
          }
     }
     printf("\n Odd Num: %d \n Even Num: %d", oddcount , evencount );

     return 0;
}

If you are still getting some problem then post your problem here..

# include <stdio.h>
# define MAX 100
int main(void)
{
    int oddcount, evencount;
    int array[MAX],i,n;

    printf("\n Enter Array Size: ",MAX);
 
    scanf("%d", &n); // User enters Array Size
 
    for(i = 0; i < n; i++)
    {
       printf("\n Enter %d value: ",i+1); 
       scanf("%d", &array[i]); // Allows user to enter values into the Array
       }
    
    putchar('\n');
    printf("\nArray Values: ");
    for(i = 0; i < n; i++)
    {
       printf("%3d ",array[i]); //Prints out the array -- this is where program stops it should carry on down 
    }
    oddcount = 0;
    evencount = 0;

    for (i = 0; i < n; i++) // Code determines wheter odd or even.
    {
      if (array[i]%2 != 0)
      {
        printf("\nThe number %d Is Odd.\n", i);
        oddcount++;     
      }
      else {
        printf("\nThe number %d Is Even.\n",i);
        evencount++;
      }
    }
    return 0;
}

Your code isn't stopping. It just finishes - you never added the print statement for how many even and odd numbers you had in the array.

Add that, and it should be fine - if not, post back. Don't you know how to single step through your program yet?

That's a MUST to learn, and right away. You have some real work to do to get yourself up to speed on this. Get cracking, dude! ;)

Edit: With n, you aren't setting up the size of the array - it has MAX number of elements. You are setting up how many elements your data will have, in the array. You don't want to go working with data that isn't yours, so that's important to have in there.

HOPE IT CAN HELP TO US :D

#include<stdio.h>
#include<conio.h>
int main()
{
int list[5];
int i;
clrscr();
for(i=0;i<=4;i++)
{
printf("Enter no. %d:",i+1);
scanf("%d",&list);
}
printf("The even nos.:");
for(i=0;i<=4;i++)
{
if(list%2==0)
{
printf("%d\t",list);
}
}
printf("\n The odd nos.:");
for(i=0;i<=4;i++)
{
if(list%2==1)
{
printf("%d\t",list);
}
}
getch();
return 0
}