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Dec 11th, 2005

i can't figure out this code :( help please

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Hello im practicing C language
and i ran into this code and i can't figure out the outputs

can u help me please ?
I'm confused in operator precedence.
and What does short circuit evaluation means in c?

when i run this code the output is:
000 and 001
How come this way ? please share ur knowledge with me .

C Syntax (Toggle Plain Text)
 
#include<stdio.h>
 
void main()
{
	int a = 0, b = 0, x;
 
	x = 0 && (a = b = 777);
	printf("%d %d %d\n", a, b, x);
 
	x = 777 || (a = ++b);
	printf("%d %d %d\n", a, b, x);
}
#include<stdio.h>

void main()
{
	int a = 0, b = 0, x;

	x = 0 && (a = b = 777);
	printf("%d %d %d\n", a, b, x);

	x = 777 || (a = ++b);
	printf("%d %d %d\n", a, b, x);
}

Thanks much...

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free_eagle

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Dec 11th, 2005

Re: i can't figure out this code :( help please

Don't use void main().

Quote ...

and What does short circuit evaluation means in c?

C Syntax (Toggle Plain Text)
if(a() && b())
if(a() && b())

In this case, if a is false, b won't be evaluated, because no matter what b is, the expression is false.

dwks

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Dec 11th, 2005

Re: i can't figure out this code :( help please

hi DWKS
thanks for short clear explanation.

So u in this case when we use logical operations we don't assign numbers but we think it like true and false right and we can think of "if" statement to be considered?!

aah yes i understood that i didn't think about condition i thought may be we assign 777 to a and b

but look this operators;

"=" and "==" x = 0 && (a = b = 777)

i though as the operator is assignment it will give 0 to x and ... umm okay i'll try to find out...

THANK YOU!!!

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