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C Discussion Thread
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Jan 17th, 2006

(C) have 2 parse errors (help)

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here is my problem
main.c:17: error: parse error before '{' token
main.c:27: error: parse error before string constant

C Syntax (Toggle Plain Text)
#include <stdio.h>
#include <c.h>
#include <math.h>
#include <ctype.h>
#include <time.h>
#include <stdlib.h>
#include <string.h>
 
#define kmll 200
#define Kzll 0
 
int myint,any,go;
int main (int argc, const char * argv[]) {
 
(myint, any, go) = 0 ;
 
// here parse error
do printf(" helo guys plese incert a number") {
 
if any = 0 {  
 
scanf("%c %c",myint,any);   
 
else 
 
printf(" next code"); } 
 
// here parse error
printf(" %d + %d = %d ", myint, any,(any + myint));
 
else printf(" uno");
 
return 0; }
#include <stdio.h>
#include <c.h>
#include <math.h>
#include <ctype.h>
#include <time.h>
#include <stdlib.h>
#include <string.h>

#define kmll 200
#define Kzll 0

int myint,any,go;
int main (int argc, const char * argv[]) {

(myint, any, go) = 0 ;

// here parse error
do printf(" helo guys plese incert a number") {

if any = 0 {  

scanf("%c %c",myint,any);   

else 

printf(" next code"); } 

// here parse error
printf(" %d + %d = %d ", myint, any,(any + myint));

else printf(" uno");

return 0; }

a quick reply to the problem would be helpfull

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zenoen

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Jan 17th, 2006

Re: (C) have 2 parse errors (help)

need () around if:
if ( any == 0 )

also, you want == not =

winbatch

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Posting Pro in Training

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Jan 17th, 2006

Re: (C) have 2 parse errors (help)

try concentrating on { } brackets and matching if-else statements

SpS

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since Aug 2005

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Jan 18th, 2006

Re: (C) have 2 parse errors (help)

still doesent work please help

C Syntax (Toggle Plain Text)
#include <stdio.h>
#include <c.h>
#include <math.h>
#include <ctype.h>
#include <time.h>
#include <stdlib.h>
#include <string.h>
 
#define kmll 200
#define Kzll 0
 
int myint,any,go;
int main (int argc, const char * argv[]) {
 
(myint, any, go) == 0 ;
 
 
 
// stupid error is some where under here ( parse error befor '{' token ) 
//help it should work but doesent
/*dang it */ do printf(" helo guys plese incert a number "); {
 
 
while any = 0 {  
 
scanf("%c %c",myint,any);   
 
else 
 
printf(" next code"); } 
 
 
// here 2 im in need of help (parse error befor string constant) 
// i don't see the problem help me
printf(" %d + %d == %d ", myint, any,(any + myint)); 
 
 
else printf(" uno"); }
 
return 0; }
#include <stdio.h>
#include <c.h>
#include <math.h>
#include <ctype.h>
#include <time.h>
#include <stdlib.h>
#include <string.h>

#define kmll 200
#define Kzll 0

int myint,any,go;
int main (int argc, const char * argv[]) {

(myint, any, go) == 0 ;



// stupid error is some where under here ( parse error befor '{' token ) 
//help it should work but doesent
/*dang it */ do printf(" helo guys plese incert a number "); {


while any = 0 {  

scanf("%c %c",myint,any);   

else 

printf(" next code"); } 


// here 2 im in need of help (parse error befor string constant) 
// i don't see the problem help me
printf(" %d + %d == %d ", myint, any,(any + myint)); 


else printf(" uno"); }

return 0; }

zenoen

Reputation Points: 10

Solved Threads: 1

Newbie Poster

Offline

16 posts
since Dec 2005

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No one has posted to this discussion for at least three months. Please let old threads die and do not reply to them unless you feel you have something new and valuable to contribute that absolutely must be added to make the discussion complete. Otherwise, please start a new thread in this forum instead.

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