please help me. my program is working but not displaying the table but i followed the syntax for the two-dimensional array. how come the program does not display the table? here is the code. :D
#include<stdio.h>
#include<conio.h>
main()
{
int x[5][5],a,j;
for (a=0;a<=5;a++)
for (j=0;j<5;j++)
x[a][j]=(a*4)+j+1;
for (a=0;a<=5;a++)
for (j=0;j<5;j++)
printf("%d\n",x[a][j]);
getch();
}Jump to PostWhen a=5, you are trying to read and write x[5][0]. This is not your memory and your code segfaults.
Change for (a=0;a<=5;a++) to for (a=0;a<5;a++)in both sets of loops.
When you ran your code, it should have crashed and you should have seen an error …
Jump to PostChange
printf("%d\n",x[a][j]);
to
printf("%d ",x[a][j]);
and only printf the newline when the value of a changes.
When a=5, you are trying to read and write x[5][0]. This is not your memory and your code segfaults.
Change for (a=0;a<=5;a++) to for (a=0;a<5;a++)
in both sets of loops.
When you ran your code, it should have crashed and you should have seen an error message indicating that there was a segFault.
i have a question sir/ma'am. My professor wants that the output should be in a table and in a sequence. how can i do that? or that it is not possible?
Change
printf("%d\n",x[a][j]);
to
printf("%d ",x[a][j]);
and only printf the newline when the value of a changes.
i have a question sir/ma'am. My professor wants that the output should be in a table and in a sequence. how can i do that? or that it is not possible?
You mean like this :
for (a=0;a<5;a++){
for (j=0;j<5;j++)
printf("%d\t",x[a][j]);
printf("\n");
}YES! just like that. thanks a lot! :D thanks to the both of you. :D
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