I want to store only some of the input

[swissknife007]

I am implementing a program where I want to store only certain part of the input string.
for eg if the input string is
0123456789
I want to discard 4 AND 7
and store
01235689
Please my program requires an input string of 10000 characters so running time is very crucial for me.
Also while inputting the string I really don't know how many characters will be there.
Does anybody have any suggestions?
Any help will be greatly appreciated

[gerard4143]

Depends, what is the criteria for discarding characters.

[swissknife007]

Depends, what is the criteria for discarding characters.

I already told you the criteria.
I dont want 4s and 7s in my answer

[swissknife007]

I already told you the criteria. I dont want 4s and 7s in my answer

I mean I don't want to store 4s and 7s present in the input.

[gerard4143]

I would investigate a function like

void *memchr(const void *s, int c, size_t n);

The memchr() function scans the first n bytes of the memory area
pointed to by s for the character c. The first byte to match c
(interpreted as an unsigned character) stops the operation.

The memchr() and memrchr() functions return a pointer to the match‐
ing byte or NULL if the character does not occur in the given mem‐
ory area.

Copied from the manpages on GNU/Linux.

With this function you can leap through valid areas of data to store.

[swissknife007]

I would investigate a function like

void *memchr(const void *s, int c, size_t n);

The memchr() function scans the first n bytes of the memory area pointed to by s for the character c. The first byte to match c (interpreted as an unsigned character) stops the operation.

The memchr() and memrchr() functions return a pointer to the match‐ ing byte or NULL if the character does not occur in the given mem‐ ory area.

Copied from the manpages on GNU/Linux.

With this function you can leap through valid areas of data to store.

Sorry but you didnt understand my question.i dont want to stop reading once i encounter 4 or 7.I want to continue reading the rest of the string

[gerard4143]

Sorry but you didnt understand my question.i dont want to stop reading once i encounter 4 or 7.I want to continue reading the rest of the string

Yes I understood your question. You use the function memchr to find the occurrence of characters(or pointers to the occurrences) to find ranges(pointer ranges) of valid data.

[L7Sqr]

How are you handling the input/output? Given that you can read from stdin and write to stdout why not just filter the input?

int main () {
   int c = 0;
   while (EOF != (c = fgetc (stdin))) {
      switch (c) {
         case '4': case '7': break;
         default: fputc (c, stdout);
      }
   }
   return 0;
}

[mhd_arif123]

I am implementing a program where I want to store only certain part of the input string. for eg if the input string is 0123456789 I want to discard 4 AND 7 and store 01235689 Please my program requires an input string of 10000 characters so running time is very crucial for me. Also while inputting the string I really don't know how many characters will be there. Does anybody have any suggestions? Any help will be greatly appreciated

Step 1 : you have to store those characters (that you want to discard) in a data structure
Step 2 : extract a single character from the input string and match it with the list of discardable characters.
Step 3 : if match is not found , copy the extracted character to a new place(datastructure). else leave it.
continue above steps , till the end of input string.