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C Discussion Thread
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Mar 23rd, 2006

Dice program

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OK I wrote this dice program up and it works really well. Just curious though if there was a way to reduce the number of "if" statements.

C Syntax (Toggle Plain Text)
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
 
#define SIZE 11
#define TOTAL 36000
 
int main(void)
{
	int cnt = 0;
	int die1, die2, sum;
	int array[SIZE];
 
	srand(time(NULL));
 
	for (cnt = 0; cnt < SIZE; cnt++)
		array[cnt] = 0;
 
	for (cnt = 0; cnt < TOTAL; cnt++)
	{
		die1 = rand() % 6 + 1;
		die2 = rand() % 6 + 1;
		sum = die1 + die2;
 
		if (sum == 2)
			array[0] = array[0] + 1;
		if (sum == 3)
			array[1] = array[1] + 1;
		if (sum == 4)
			array[2] = array[2] + 1;
		if (sum == 5)
			array[3] = array[3] + 1;
		if (sum == 6)
			array[4] = array[4] + 1;
		if (sum == 7)
			array[5] = array[5] + 1;
		if (sum == 8)
			array[6] = array[6] + 1;
		if (sum == 9)
			array[7] = array[7] + 1;
		if (sum == 10)
			array[8] = array[8] + 1;
		if (sum == 11)
			array[9] = array[9] + 1;
		if (sum == 12)
			array[10] = array[10] + 1;
	 }
 
	for (cnt = 0; cnt < SIZE; cnt++)
		printf("Number of %d's: %d\n", cnt+2, array[cnt]);
 
	return 0;
}
#include <stdio.h>
#include <stdlib.h>
#include <time.h>

#define SIZE 11
#define TOTAL 36000

int main(void)
{
	int cnt = 0;
	int die1, die2, sum;
	int array[SIZE];

	srand(time(NULL));

	for (cnt = 0; cnt < SIZE; cnt++)
		array[cnt] = 0;

	for (cnt = 0; cnt < TOTAL; cnt++)
	{
		die1 = rand() % 6 + 1;
		die2 = rand() % 6 + 1;
		sum = die1 + die2;

		if (sum == 2)
			array[0] = array[0] + 1;
		if (sum == 3)
			array[1] = array[1] + 1;
		if (sum == 4)
			array[2] = array[2] + 1;
		if (sum == 5)
			array[3] = array[3] + 1;
		if (sum == 6)
			array[4] = array[4] + 1;
		if (sum == 7)
			array[5] = array[5] + 1;
		if (sum == 8)
			array[6] = array[6] + 1;
		if (sum == 9)
			array[7] = array[7] + 1;
		if (sum == 10)
			array[8] = array[8] + 1;
		if (sum == 11)
			array[9] = array[9] + 1;
		if (sum == 12)
			array[10] = array[10] + 1;
	 }

	for (cnt = 0; cnt < SIZE; cnt++)
		printf("Number of %d's: %d\n", cnt+2, array[cnt]);

	return 0;
}

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degamer106

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Mar 23rd, 2006

Re: Dice program

hmm.. try this:

(Toggle Plain Text)

for (cnt = 0; cnt < TOTAL; cnt++)
{	
   die1 = rand() % 6 + 1;
   die2 = rand() % 6 + 1;
     sum = die1 + die2;
     ++array[sum-2];
}

Clinton Portis

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Mar 23rd, 2006

Re: Dice program

Quote originally posted by Clinton Portis ...

hmm.. try this:
(Toggle Plain Text)
for (cnt = 0; cnt < TOTAL; cnt++)
{	
   die1 = rand() % 6 + 1;
   die2 = rand() % 6 + 1;
     sum = die1 + die2;
     ++array[sum-2];
}
for (cnt = 0; cnt < TOTAL; cnt++) { die1 = rand() % 6 + 1; die2 = rand() % 6 + 1; sum = die1 + die2; ++array[sum-2]; }

Erm what exactly does ++array[sum-2] do?

Outside of incrementing the array I don't see how it stores the sum :eek:

degamer106

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Mar 23rd, 2006

Re: Dice program

I'm not sure what ye' were trying to accomplish but I think

C Syntax (Toggle Plain Text)
 
++array[sum-2] ;
 
++array[sum-2] ;

basically does the same things as all these if statements

C Syntax (Toggle Plain Text)
if (sum == 2)
    array[0] = array[0] + 1;
if (sum == 2)
    array[0] = array[0] + 1;

which appear to just be adding 1 to whatever is stored in your array element.. which appears to always be 2 less than your sum value.

Clinton Portis

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Mar 23rd, 2006

Re: Dice program

Oh ok thanks.

degamer106

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