Do you have any idea what this means?

[govinda.attal]

int main()
{
       int var;
       char string[50];
       
       (var, string);
       (0);
       (0, 1, 2);
 
       return 0;
}

Reply ASAP
Thanks in advance
Govinda Attal.

[Dave Sinkula]

Several no-ops? What is your question?

[mostafadotnet]

Hi govinda.attal ,
This means nothing.

[govinda.attal]

This code does compile and generates an exe file...When I went thru disassembly, I found nothing useful in it...There were no nops in it. First of all our basic coding principles say that it should give a compiler error... compilers like msvc, gcc simply pass without giving any error or warnings..

[Infarction]

This code does compile and generates an exe file...When I went thru disassembly, I found nothing useful in it...There were no nops in it. First of all our basic coding principles say that it should give a compiler error... compilers like msvc, gcc simply pass without giving any error or warnings..

I compiled to assembly and peeked at it too. The compiler just optimizes the NOPs out, so you pretty much get stack allocation and stack deallocation and that's it.

[Grunt]

Why would compiller give an error? That's a valid program.

[andor]

This code does compile and generates an exe file...When I went thru disassembly, I found nothing useful in it...There were no nops in it. First of all our basic coding principles say that it should give a compiler error... compilers like msvc, gcc simply pass without giving any error or warnings..

gcc var.c -o var -Wall
var.c: In function `main':
var.c:6: warning: left-hand operand of comma expression has no effect
var.c:8: warning: left-hand operand of comma expression has no effect
var.c:8: warning: left-hand operand of comma expression has no effect
var.c:6: warning: statement with no effect
var.c:7: warning: statement with no effect
var.c:8: warning: statement with no effect