attaced is the question

Try something like:


This should keep on asking the user the choice until he enters a correct number.

One mild problem from past experience, if the users enters a floating point number, this loop spins out of control. Give it a try, it's good exercise.

OH sorry Mr. Vegaseat my bad, thanks for pointing out the flaw to me. The OP required the user to input floating point values so i actually shouldnt have taken a decimal input in the first place.

Well here is a near foolproof Implementation of the input accepting phase for your program which accpets only valid floats.

Now that is sweet, except I wouldn't use exit (1), but would rather stay in the input loop.

Thanks for the appreciation.
Hmm i guess you are right, no use being too harsh
But that just involves adjusting the "if" stmt a bit and voila one would get what he wants.

Hi Guys,

Thanks so much. But is there amuch easily way of writing that part as it's seem pretty tough for me to understand.Please advise. Thanks.

Hi,

Can this be done?
#include<stdio.h>
float x[4] = {1.2,2.4,3.6,4.8};
float f[4] = {0.1,0.2,0.3,0.4};
float xave = 0.0;
float ftotal = 0.0;
main()
{
int i;
float weights[4] = {0};
char buf[80];
for(i = 0; i < 4; ++i)
{
printf("Enter weight #%d", i+1);
fgets(buf,sizeof(buf),stdin);
weights[i] = atof(buf);
}
{
int i;
for (i=0; 1<4;i++) ftotal + = f[i];
if(ftotal!=1.0)
{
printf("error\n");
exit();
}
for(i=0;1<4;i++) xave+=f *x;
printf("\nThe weights are %f"&f);
printf("\nThe average is %f\n",xave);
}

But seem to hv compilng errors...can anyone please help me out where should i amend correctly yo make it works?

0001 #include<stdio.h>0002 float x[4] = {1.2,2.4,3.6,4.8};0003 float f[4] = {0.1,0.2,0.3,0.4};0004 float xave = 0.0;0005 float ftotal = 0.0;0006 main()0007 {0008 int i;0009 float weights[4] = {0};0010 char buf[80];0011 for(i = 0; i < 4; ++i)0012 {0013 printf("Enter weight #%d", i+1);0014 fgets(buf,sizeof(buf),stdin);0015 weights[i] = atof(buf);0016 }0017 {0018 int i;0019 for (i=0; 1<4;i++) ftotal + = f[i]; parse error before `=' 0020 if(ftotal!=1.0)0021 {0022 printf("error\n");0023 exit(); at this point in file0024 }0025 for(i=0;1<4;i++) xave+=f *x; invalid operands `float[4]' and `float[4]' to binary `operator *'0026 printf("\nThe weights are %f"&f); invalid operands `const char[20]' and `float[4]' to binary `operator &'0027 printf("\nThe average is %f\n",xave);0028 }0029 0030 0031 parse error at end of input confused by earlier errors, bailing out

Syntax Errors found in /usr/include/stdlib.h:

0001 #include<stdio.h>0002 float x[4] = {1.2,2.4,3.6,4.8};0003 float f[4] = {0.1,0.2,0.3,0.4};0004 float xave = 0.0;0005 float ftotal = 0.0;0006 main()0007 {0008 int i;0009 float weights[4] = {0};0010 char buf[80];0011 for(i = 0; i < 4; ++i)0012 {0013 printf("Enter weight #%d", i+1);0014 fgets(buf,sizeof(buf),stdin);0015 weights[i] = atof(buf);0016 }0017 {0018 int i;0019 for (i=0; 1<4;i++) ftotal + = f[i]; parse error before `=' 0020 if(ftotal!=1.0)0021 {0022 printf("error\n");0023 exit(); at this point in file0024 }0025 for(i=0;1<4;i++) xave+=f *x; invalid operands `float[4]' and `float[4]' to binary `operator *'0026 printf("\nThe weights are %f"&f); invalid operands `const char[20]' and `float[4]' to binary `operator &'0027 printf("\nThe average is %f\n",xave);0028 }0029 0030 0031 parse error at end of input confused by earlier errors, bailing out

Syntax Errors found in /usr/include/stdlib.h: