post decriment in while

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I hav one doubt regarding post decriment,the code in c is as follows.............

void main()
{
clrscr();
while(i--!=6)
i=i+2;
printf("%d\n",i);
getch();
}

I know the output is 5, but i read in a book dat the post incriment or decrement operators are evaluated after reaching semicolon(

.....but in while condition,the ondition fails so it wont execute the next line so, directly reaches printf.Till now there is no semicolon still the i value is decresed......wts da reason...can u sugest me..?

Thanks & Regards.

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pointers

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Light Poster

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Oct 31st, 2006

Re: post decriment in while

If you want help you must to fix your code. i is undefined and uninitialised. There are more problems with your code but first fix and beautify it.

andor

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Posting Whiz in Training

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Oct 31st, 2006

Re: post decriment in while

Wow.

C Syntax (Toggle Plain Text)
void main()  - don't use void main. main() returns an int.
{
  clrscr();
  while(i--!=6)      - where is i set to some intitial value?
      i=i+2;           - this is the end of the while loop 
                              I think you are missing {} to make a while block?
   printf("%d\n",i);
   getch();
}
 
void main()  - don't use void main. main() returns an int.
{
  clrscr();
  while(i--!=6)      - where is i set to some intitial value?
      i=i+2;           - this is the end of the while loop 
                              I think you are missing {} to make a while block?
   printf("%d\n",i);
   getch();
}

You do realize that your while loop subtracts then adds to the same variable, essentially in the same statement. Eeeek...

Back up.

What are you trying to do?

jim mcnamara

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