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Dec 2nd, 2006

Pointers to class members - it just won't work.

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Short example of problem I have:

C Syntax (Toggle Plain Text)
class A{
public:
    int x[10];
};
 
int main(){
    int A::*pointer = &A::x;
 
    A a;
    a.*pointer = 3;
    return 0;
}
class A{
public:
    int x[10];
};

int main(){
    int A::*pointer = &A::x;
    
    A a;
    a.*pointer = 3;
    return 0;
}

I got an error: cannot convert from 'int (A:

)[10]' to 'int A:

' in second line of 'main()'

I tried to remove '&' from this line because x is an array so the name of array (without square brackets) like A::x should return it's adress (in this case shift in A class), but now I got an error like this:

illegal reference to non-static member 'A::x'

Why compiler thinks I want to convert something? I just want to create a pointer to int array x[10], member of A class.
Could you help?

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edek

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Dec 2nd, 2006

Re: Pointers to class members - it just won't work.

You're not doing it correctly -- you might want to try something like:

C Syntax (Toggle Plain Text)

A a;
int *pointer;
pointer=a.x;

I haven't actually tried this code out, so it may not compile.

Last edited by John A; Dec 2nd, 2006 at 7:36 pm.

John A

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Dec 2nd, 2006

Re: Pointers to class members - it just won't work.

OK, but it is not what I'm trying to do.
I do not need a pointer to an member of object 'a' of type 'A'

I need a pointer to class member which can be created even before the object of such class is created and then used with this object, like this:

C Syntax (Toggle Plain Text)
 int A::*pointer = A::x;   //main problem: how to get adress (shift in class A) of member x
                                             //A::x doesn't return adress (shift) that I need
A a;
a.*pointer = 5
 
A b;
b.*pointer = 33;
etc.
 int A::*pointer = A::x;   //main problem: how to get adress (shift in class A) of member x
                                             //A::x doesn't return adress (shift) that I need
A a;
a.*pointer = 5

A b;
b.*pointer = 33;
etc.

But it doesnt work with this syntax, any other idea?

Last edited by edek; Dec 2nd, 2006 at 7:31 pm.

edek

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Dec 2nd, 2006

Re: Pointers to class members - it just won't work.

>>a.*pointer
that is incorrect syntax -- remove the star and add class member named pointer.

(Toggle Plain Text)

class A{
public:
    int x[10];
    int* pointer;
};

A a;
a.pointer = &a.x[0];

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Dec 3rd, 2006

Re: Pointers to class members - it just won't work.

not just that, but you DO get an object instance when you do "A a;".
It's just created in a different memory space as compared to "A a = new A();".

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Dec 3rd, 2006

Re: Pointers to class members - it just won't work.

I feel I was not understood again, propably my fault. If you would like to see what I ment see:
http://www.informit.com/guides/conte...eqNum=142&rl=1

Last edited by edek; Dec 3rd, 2006 at 10:57 am.

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Re: Pointers to class members - it just won't work.

>I feel I was not understood again, propably my fault.
Don't worry about it. Pointers to members aren't exactly a commonly used feature. The problem in your initial code is a type mismatch. x is an array, but to get a pointer to it, you need a pointer to an array member and you were only using a pointer to an int member:

C Syntax (Toggle Plain Text)
class A{
public:
  int x[10];
};
 
int main(){
  int (A::*pointer)[10] = &A::x;
 
  A a;
  (a.*pointer)[0] = 3;
  return 0;
}
class A{
public:
  int x[10];
};

int main(){
  int (A::*pointer)[10] = &A::x;

  A a;
  (a.*pointer)[0] = 3;
  return 0;
}

Unfortunately, this isn't a case where you can rely on the implicit conversion of an array name to a pointer to the first element of the array. To do that you would need to add another level of abstraction:

C Syntax (Toggle Plain Text)
class A{
public:
  int x[10];
};
 
int main(){
  int (A::*pointer)[10] = &A::x;
  int *p;
  A a;
 
  p = a.*pointer;
  *p = 3;
 
  return 0;
}
class A{
public:
  int x[10];
};

int main(){
  int (A::*pointer)[10] = &A::x;
  int *p;
  A a;

  p = a.*pointer;
  *p = 3;

  return 0;
}

Narue

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Dec 3rd, 2006

Re: Pointers to class members - it just won't work.

Thank you very much for understanding me! Bye.

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