modify the function to

C Syntax (Toggle Plain Text)

int countchar( const char list[], char what )
{
  int i=0, count=0 ;
  for( ; list[i] != 0 ; ++i )
        if( list[i] == what ) ++count ;
  return count ;
}

int countchar( const char list[], char what ) { int i=0, count=0 ; for( ; list[i] != 0 ; ++i ) if( list[i] == what ) ++count ; return count ; }

modify the function prototype to

C Syntax (Toggle Plain Text)

int countchar(const char[], char);

int countchar(const char[], char);

I have this program that counts characters in a string is there a way to modify this code so that for example it counts specific characters entered. Exmaple.. user entered Hello, and I wanted the program to say there are 2 "L"''s entered in that word. THanks for your help!

c Syntax (Toggle Plain Text)

#include <stdio.h>
#define MAXNUM 15
 
int countchar (char []);
int main()
 
{
        char message [MAXNUM];
        int numchar;
 
        printf("\nType in a word: ");
        gets(message);
        numchar = countchar (message);
        printf ("The number of characters entered is %d\n", numchar);
        return 0;
 
} // END OF MAIN
 
//FUNCTION IMPLEMENTATION
 
int countchar (char list[])
{
        int i, count = 0;
 
        for (i = 0; list[i] != '\0'; i++)
        count++;
 
        return (count);
}

#include <stdio.h> #define MAXNUM 15 int countchar (char []); int main() { char message [MAXNUM]; int numchar; printf("\nType in a word: "); gets(message); numchar = countchar (message); printf ("The number of characters entered is %d\n", numchar); return 0; } // END OF MAIN //FUNCTION IMPLEMENTATION int countchar (char list[]) { int i, count = 0; for (i = 0; list[i] != '\0'; i++) count++; return (count); }