how to reverse a numbers input by user

[Kerry]

Hello, my name is kerry and i just sign up .Well, my question is how do reverse a number input by user using recersive function.Thanks for the help.

[saadkhulsai]

U Means how to make a factorial program then mail me at [email][e-mail][/email]

[FireNet]

Hello, my name is kerry and i just sign up .Well, my question is how do reverse a number input by user using recersive function.Thanks for the help.

You mean recursive funtion.The concept is quite simple.You take a number (to be reversed) and divide it by 10 and add the remainder to another number.As every loop goes by you multiply 10 to the other number and keep adding the remainders till you get 0.

Check this out

int n=12345,m=0;
cout<<"Orginal No:"<<n;
while(n>0)
{
    m *= 10;
    m += n%10;
    n /= 10;
}

cout<<"\nRevesed No:"<<m;

[rishiraj_bayerd]

Hi,
Your problem can be solved in various way.This program is simplest(but layman process).Here i assumed that input number is in between integer range
(i.e.-32768 to 32767)

#include
#incliude

void reverse(int num)
{
int i,div;

for(i=0;i<5;i++)
{
if(num>9)
{
printf("%d",div);
break;
}

div=num%10;
num*=/10;
printf("%d",div);
}

}

void main()
{

int num;
clrscr();

printf("\nEnter the number:");
scanf("%d",&num);

reverse(num);

getch();
}


N.B.
If you have any problem in C.Please send it to me with your id.I try my best to solve it.my id is [email][e-mail][/email]

thanking you......
Rishiraj bayerd.

[let us c]

reverse(int n)
{
long sum=0;int rem;
while(n>0)
{rem=n%10;
sum=sum*10+rem;
n=n/10;}
return sum;

main()
................................ hope u can do it from here.good luck.

[stg110]

the recursive code (function call itself ) will be as follow
#include
#include
int reverse_num (int n,int m) ;
using namespace std;
int main()
{
int n;
int m=0;
cout<<"enter number to reverse :";
cin>>n;
cout<

[c0ld sn1ff3r]

#include<stdio.h>
#include<conio.h>
main()
{
int num, rem=0;
printf("\n Enter the number ");
scanf("%d", &num);
while(num>0)
{
rem = (rem * 10) + (num % 10);
num = num / 10;
}
printf("\n Reverse of the number is %d", rem);
getch();
}