Quick Question

[Drew06]

I can't seem to figure out the syntax error on this one, it says the error is at the end of the input....

#include
#include

int determine(int);

void main(void)
{
int num1, even, odd;

printf("Enter a number: ");
scanf("%d", &num1);

printf("The number is: %d", determine(num1));
scanf("%d", &num1);
getchar();

int determine(int num1)
{
if(num1 %2 == 0)
num1 = even;
else
num1 = odd;
}

Any help would be appreciated,
Andrew

[Narue]

Your main doesn't have a closing brace. You also can't have nested functions, so the use of even and odd in determine has to be done differently.

[Drew06]

Heh, yeah I just noticed that... Im a newbie to C programming... :(

I changed that so it is running now, but after it displays if the number is even or odd it asks for another number and when you enter a number the console goes away..

[Narue]

>Im a newbie to C programming...
Then I'll adjust my next answer accordingly, because it's not exactly a trivial problem.

>when you enter a number the console goes away..
You're using getchar to pause the program it seems, but because there's still a newline left in the stream, getchar reads it immediately and doesn't block. You can add a second getchar:

int main(void)
{
  int num1, even, odd;

  printf("Enter a number: ");
  scanf("%d", &num1);

  printf("The number is: %d", determine(num1));
  scanf("%d", &num1);
  getchar();
  getchar();

  return 0;
}

And that will probably work, or you can loop until you find a newline, which is more likely to work most of the time:

int main(void)
{
  int num1, even, odd;

  printf("Enter a number: ");
  scanf("%d", &num1);

  printf("The number is: %d", determine(num1));
  scanf("%d", &num1);
  while ( getchar() != '\n' )
    ;
  getchar();

  return 0;
}

Notice that I changed your void main to int main and returned a value. void main is wrong, don't do it.

[Drew06]

Thanks alot!