Theta means a "tight" bound in the sense that you bound something above and below by a growth order.
Basically, if you can find a growth order such that t(n) is in big-Oh of the order, as well as in big-Omega of the order, then t(n) is by definition in Theta of that order.
Hint: Let n -> infinity, as though you were taking a limit. What does t(n) look like in the limit of large n?
Hint 2: If you want to go beyond that, take your answer from the first hint and prove it is correct by finding constants a, b, and m such that a*f(n) <= t(n) <= b*f(n) for all n >= m. You don't have to find tight a and b... just make them positive and you're good to go.