I'm afraid that none of us can help you out - the image you posted is 404 (not found).

If you fix up the image location, I'm sure one of us can make a suggestion! :-)

here it is it should work jst let me know what you think and if it works or not.

I've tried to open this file and can't do! Are you looking for athe formula to find the area of something? The formula to find the area of a circle is PI * radius squared.

You can't open the attached file? I can ... is there something possibly wrong w/ my database?

Works fine for me.

yeah all i want is a formula is if it is possible. the shape is not quite a circle. I dont know how i would explain it either. but any help would be great. thanks.

If it is meant to be solved as an area, what I would do is set it up as a grid and take it from there (combining shapes to become regular shape and then measuring the are of those), because plain old getting it from the picture is very improbable, unless you have a program to measure the lines, to get the perimeter and multiplying that by itself. Other than that, I have no idea. To have an equation for a shape 'without a name', is different. I would help you, but I'm still in high school, and haven't taken calculus, which I hear is need to take on to these 'without a name' shapes.
If you wanted to find the area of a three dimension Icosahedron, I can help you.

Number of vertices: v
Number of edges: e
Number of faces: f
Edge: a
Radius of circumscribed sphere: R
Radius of inscribed sphere: r
Surface area: S
Volume: V
Dihedral angle between faces: delta (in degrees)
v = 12, e = 30, f = 20
a = (sqrt[50-10 sqrt(5)]/5)R
r = (sqrt[75+30 sqrt(5)]/15)R
R = (sqrt[10+2 sqrt(5)]/4)a
r = (sqrt[42+18 sqrt(5)]/12)a
S = 5 sqrt(3)a2
V = (5[3+sqrt(5)]/12)a3
delta = arccos(-sqrt[5]/3) = 138o 11'
http://mathforum.org/dr.math/faq/for...ages/icosa.gif

so you think i will learn how to do this in calculus. well thats good cause im taking calc this fall. but that also sucks cause then i have to put the project off for a while well i will ask some of my buddies that have taken calc thank for the hlep

edit: i guess i should tell everyone why im trying to figure this out. i need to know cause i have been given a project at work to see if i can do with visual basic and the project invovles finding out the area of spaces like this so that they can do other info with the info. there is a program out there that can do this so i figure some how some way i must beable to do it. but the program they have found to do this will cost the company $50,000.00 :eek: and they dont want to pay that. but hopefully i will figure it out

Do you happen to have an aprox answer as well as the dimensions of the entire pic? Need an aprox to know if i am getting close or not. Thanks