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Dec 30th, 2007

Re: arrays proplem

c++ Syntax (Toggle Plain Text)
for(int i=0 ; i<50 ; i++)
{cout<<a[i]<<" ";
if(i%10 == 0)
cout<<endl;
}
for(int i=0 ; i<50 ; i++)
{cout<<a[i]<<" ";
if(i%10 == 0)
cout<<endl;
}

you had to use cout<<endl if i is divisble by 10 i.e. 10 elements has been printed..

Last edited by rajatC; Dec 30th, 2007 at 5:19 am.

rajatC

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Dec 30th, 2007

Re: arrays proplem

it will print 11 elements in first line and 10 in all others...
to be more accurate use...

c++ Syntax (Toggle Plain Text)
for(int i=1 ; i<51 ; i++)
    {
 
            cout<<setw(3)<<a[i-1]<<" ";
            if(i%10 == 0)
            cout<<endl;
    }
for(int i=1 ; i<51 ; i++)
    {
            
            cout<<setw(3)<<a[i-1]<<" ";
            if(i%10 == 0)
            cout<<endl;
    }

rajatC

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Dec 30th, 2007

Re: arrays proplem

Click to Expand / Collapse Quote originally posted by rajatC ...

c++ Syntax (Toggle Plain Text)
for(int i=0 ; i<50 ; i++)
{cout<<a[i]<<" ";
if(i%10 == 0)
cout<<endl;
}
for(int i=0 ; i<50 ; i++) {cout<<a[i]<<" "; if(i%10 == 0) cout<<endl; }
you had to use cout<<endl if i is divisble by 10 i.e. 10 elements has been printed..

It should be:

C++ Syntax (Toggle Plain Text)
if( (i+1)%10 == 0)
if( (i+1)%10 == 0)

Because i was started from 0

invisal

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Dec 30th, 2007

Re: arrays proplem

this is my answer ; is it right ?

C++ Syntax (Toggle Plain Text)
# include <iostream>
#include <iomanip >
using namespace std ;
int main ()
{
 
int alpha[50];
for (int i=0;i<25;i++)
{
alpha[i]=i*i;
cout<<alpha[i]<<" ";
}
for(int i=25;i<50;i++)
{
alpha[i]=3*i;
cout<<alpha[i]<<" ";
}
for(int i=1 ; i<51 ; i++)    {                           
    {
 
            cout<<setw(3)<<alpha[i-1]<<" ";
            if( (i+1)%10 == 0)
            cout<<endl;
    }
 
}
 
return 0;
}
# include <iostream>
#include <iomanip >
using namespace std ;
int main ()
{
	
int alpha[50];
for (int i=0;i<25;i++)
{
alpha[i]=i*i;
cout<<alpha[i]<<" ";
}
for(int i=25;i<50;i++)
{
alpha[i]=3*i;
cout<<alpha[i]<<" ";
}
for(int i=1 ; i<51 ; i++)    {                           
    {
            
            cout<<setw(3)<<alpha[i-1]<<" ";
            if( (i+1)%10 == 0)
            cout<<endl;
    }
    
}

return 0;
}

bis student

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Dec 30th, 2007

Re: arrays proplem

This works if you don't mind the newline right from the get go.

cpp Syntax (Toggle Plain Text)
if (i % 10 == 0)
   cout << endl;
cout << alpha[i] << "\t";
if (i % 10 == 0)
   cout << endl;
cout << alpha[i] << "\t";

superjacent

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Dec 30th, 2007

Re: arrays proplem

Click to Expand / Collapse Quote originally posted by bis student ...

this is my answer ; is it right ?

I'd guess that you should be able to determine if it's right or not and I'm suspecting you're guessing it's not.

I'd suggest removing the cout statements from the for loops of the assignment statements, they just print 25 across the line, which is not what you want.

I removed those cout statements and your code is nearly there. The first line only prints 9 numbers, the rest print 10.

superjacent

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Dec 30th, 2007

Re: arrays proplem

(Toggle Plain Text)

for(int i=1 ; i<51 ; i++)    {                           
    {
            
            cout<<setw(3)<<alpha[i-1]<<" ";
            if( (i+1)%10 == 0)
            cout<<endl;
    }
    
}

Double open brace and double close brace?

There are 2 ways to choose to print 10 numbers for each line.

C++ Syntax (Toggle Plain Text)
for (int i=0; i<50; i++) {
   cout << alpha[i] << "  ";
    if ((i+1) % 10 == 0)
        cout << endl;
}
for (int i=0; i<50; i++) {
   cout << alpha[i] << "  ";
    if ((i+1) % 10 == 0)
        cout << endl;
}

C++ Syntax (Toggle Plain Text)
for (int i=1; i<51; i++) {
   cout << alpha[i-1] << "  ";
    if (i % 10 == 0)
        cout << endl;
}
for (int i=1; i<51; i++) {
   cout << alpha[i-1] << "  ";
    if (i % 10 == 0)
        cout << endl;
}

This one also work too

C++ Syntax (Toggle Plain Text)
for (int i=0; i<50; ) {
   cout << alpha[i] << "  ";
    if (++i % 10 == 0)
        cout << endl;
}
for (int i=0; i<50; ) {
   cout << alpha[i] << "  ";
    if (++i % 10 == 0)
        cout << endl;
}

invisal

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