Would I have to go about doing the math manually and make my own function? Is there some built in function I can use to be lazy? Is there some totally easier way that I am oblivious to?
I will assume you mean you would like to display the value of some integral type in decimal, binary, octal, and hexadecimal representations. Three out of four are available the lazy way, but you'll need to roll your own to display a binary representation.
#include <iostream>
template < typename T >
inline T highbit(T& t)
{
return t = (((T)(-1)) >> 1) + 1;
}
template < typename T >
std::ostream& bin(T& value, std::ostream &o)
{
for ( T bit = highbit(bit); bit; bit >>= 1 )
{
o << ( ( value & bit ) ? '1' : '0' );
}
return o;
}
int main()
{
unsigned long value = 0x12345678;
std::cout << "hex: " << std::hex << value << std::endl;
std::cout << "dec: " << std::dec << value << std::endl;
std::cout << "oct: " << std::oct << value << std::endl;
std::cout << "bin: ";
bin(value, std::cout);
std::cout << std::endl;
return 0;
}
/* my output
hex: 12345678
dec: 305419896
oct: 2215053170
bin: 00010010001101000101011001111000
*/
Reputation Points: 2780
Solved Threads: 312
long time no c
Offline 4,790 posts
since Apr 2004
Unsolved 
