I found this link , which you could use to do the decimal to hex number.
But, I'd imagine somewhere there's bound to be some kind of library function that could do this for you... Have you searched Google for it yet?
alc6379
Cookie... That's it
2,820 posts since Dec 2003
Reputation Points: 186
Solved Threads: 147
Would I have to go about doing the math manually and make my own function? Is there some built in function I can use to be lazy? Is there some totally easier way that I am oblivious to?
I will assume you mean you would like to display the value of some integral type in decimal, binary, octal, and hexadecimal representations. Three out of four are available the lazy way, but you'll need to roll your own to display a binary representation.
#include <iostream>
template < typename T >
inline T highbit(T& t)
{
return t = (((T)(-1)) >> 1) + 1;
}
template < typename T >
std::ostream& bin(T& value, std::ostream &o)
{
for ( T bit = highbit(bit); bit; bit >>= 1 )
{
o << ( ( value & bit ) ? '1' : '0' );
}
return o;
}
int main()
{
unsigned long value = 0x12345678;
std::cout << "hex: " << std::hex << value << std::endl;
std::cout << "dec: " << std::dec << value << std::endl;
std::cout << "oct: " << std::oct << value << std::endl;
std::cout << "bin: ";
bin(value, std::cout);
std::cout << std::endl;
return 0;
}
/* my output
hex: 12345678
dec: 305419896
oct: 2215053170
bin: 00010010001101000101011001111000
*/
Dave Sinkula
long time no c
5,058 posts since Apr 2004
Reputation Points: 2,780
Solved Threads: 314