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Mar 10th, 2008
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How???

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How to count> Is true I do this programming?

C++ Syntax (Toggle Plain Text)
  1.  
  2. {
  3. int count;
  4. count=0;
  5. count++;
  6.  for ( int i = 0 ; i < students.size (); i++ )
  7. {
  8. for ( int k = 0;k<students.at(i).examcode.size(); k++ )
  9. {
  10. if (students.at (i).examcode.at(0)=0)
  11. {
  12. cout<<count++<< " ";
  13. }
  14. }
  15. }
  16. }
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nurulshidanoni is offline Offline
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Mar 10th, 2008
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Re: How???

What are you trying to count? Number of examcodes for each student?

line 10: you want to use the == operator there, not the assignment = operator.
Last edited by Ancient Dragon; Mar 10th, 2008 at 11:31 pm.
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Ancient Dragon is offline Offline
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Mar 11th, 2008
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Re: How???

I want to count how many (3,13) appear..is it like this?

c++ Syntax (Toggle Plain Text)
  1. {
  2. int count;
  3. count=0;
  4. count++;
  5. for ( int i = 0 ; i < students.size (); i++ )
  6. {
  7. {
  8. for ( int k = 1;k<students.at(i).examcode.size(); k++ )
  9. if (students.at (i).examcode.at(0)==3)	
  10. {
  11. cout<<"  "<< count++;
  12. }
  13. if (students.at (i).examcode.at(k)==13)	
  14. {
  15. cout<< " " <<count++;
  16. }
  17. }
  18. }
  19. cout <<"\n";
  20. }
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nurulshidanoni is offline Offline
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Mar 11th, 2008
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Re: How???

You should increment count only inside the second if statement.
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ithelp is offline Offline
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Mar 11th, 2008
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Re: How???

Is it true to make a condition statement? &&

C++ Syntax (Toggle Plain Text)
  1. int count;
  2. count++;
  3. for ( int i = 0 ; i < students.size (); i++ )
  4. {
  5. for ( int k = 1;k<students.at(i).examcode.size(); k++ )
  6. {
  7. if (students.at (i).examcode.at(0)==1 && students.at (i).examcode.at(k)==1)	
  8. {
  9. count++;
  10. }
  11. }
  12. }
  13. cout<<"(1,1)="<<count;
  14. cout <<"\n";
  15. cout <<"\n";
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nurulshidanoni is offline Offline
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Mar 12th, 2008
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Re: How???

yes that would work, thought you don't need to bracket a single statement under an if() ie
C++ Syntax (Toggle Plain Text)
  1. if(1 == 1)
  2. {
  3.      return true;
  4. }
is the same as
C++ Syntax (Toggle Plain Text)
  1. if(1 == 1)
  2.    return true;
you only need curly brackets if more than one piece needs execution
C++ Syntax (Toggle Plain Text)
  1. if(1 == 1)
  2. {
  3.     cout << "One does equal one";
  4.     return true;
  5. }

also you can use
C++ Syntax (Toggle Plain Text)
  1. cout << "\n\n";
instead of
C++ Syntax (Toggle Plain Text)
  1. cout << "\n";
  2. cout << "\n";
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Necrolis is offline Offline
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Mar 12th, 2008
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Re: How???

Click to Expand / Collapse  Quote originally posted by nurulshidanoni ...
Is it true to make a condition statement? &&

C++ Syntax (Toggle Plain Text)
  1. int count;
  2. count++;
  3. for ( int i = 0 ; i < students.size (); i++ )
  4. {
  5. for ( int k = 1;k<students.at(i).examcode.size(); k++ )
  6. {
  7. if (students.at (i).examcode.at(0)==1 && students.at (i).examcode.at(k)==1)	
  8. {
  9. count++;
  10. }
  11. }
  12. }
  13. cout<<"(1,1)="<<count;
  14. cout <<"\n";
  15. cout <<"\n";
That will not work. You have to increment count only inside the second if like ithelp said. Also initialize count to 0 in line 2.
Last edited by hammerhead; Mar 12th, 2008 at 9:46 am.
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hammerhead is offline Offline
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Mar 12th, 2008
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Re: How???

Click to Expand / Collapse  Quote originally posted by hammerhead ...
That will not work. You have to increment count only inside the second if like ithelp said. Also initialize count to 0 in line 2.
there is no second if statement in the second lot of code, if he uses the current double conditional it should work fine(if count is properly init'ed to 0 as you said).
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Necrolis is offline Offline
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Mar 12th, 2008
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Re: How???

^ Sorry my fault.
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hammerhead is offline Offline
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This thread is more than three months old

No one has posted to this discussion for at least three months. Please let old threads die and do not reply to them unless you feel you have something new and valuable to contribute that absolutely must be added to make the discussion complete. Otherwise, please start a new thread in this forum instead.
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