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C++ Discussion Thread
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Apr 18th, 2008

Segmentation Fault (Tiny Program)

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Hi,

I'm getting seg fault in this

C++ Syntax (Toggle Plain Text)
#include <iostream>
 
int main()
{
	char *p;
	*p='w';
	std::cout<<p;
	return 0;
}
#include <iostream>

int main()
{
	char *p;
	*p='w';
	std::cout<<p;
	return 0;
}

I'm sure it is due to the line

C++ Syntax (Toggle Plain Text)

 *p='w';

I interpret this line as

Quote ...

Value at address p = 'w'

. I would like to hear an explanation on why I can't do this.

Thanks for your time

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Apr 18th, 2008

Re: Segmentation Fault (Tiny Program)

>I would like to hear an explanation on why I can't do this.
Because you never told p where to point. Thus, it could point anywhere, and "anywhere" is very likely outside of your address space.

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Apr 18th, 2008

Re: Segmentation Fault (Tiny Program)

Thanks

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