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Sep 30th, 2008

Re: Vector Dimensions

Correct me if I'm wrong, but doesn't the cavet ^ symbol in C++.NET mean that the type is actually a pointer?

c++ Syntax (Toggle Plain Text)
List1.Add(Vec1());
List1.Add(Vec1());

looks fishy... Vec1 is a pointer-type, so doesn't that mean you need to call gcnew to properly instantiate that Vec? O_O

c++ Syntax (Toggle Plain Text)
List1.Add(gcnew Vec1());
List1.Add(gcnew Vec1());

I'd assume.

Last edited by Alex Edwards; Sep 30th, 2008 at 12:07 am.

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Sep 30th, 2008

Re: Vector Dimensions

When using pointers in .NET, you do use * and & to address pointers so the cavet ^ symbol should only meen a type as int and double I beleive like string for the std:: and then String^ for managed.
If I put gcnew before Vec1 in the code below the compiler says this message:

'Vec1' : cannot use this type as argument of 'gcnew'

(Toggle Plain Text)

typedef List<String^>^ Vec1;
typedef List<Vec1> Vec2;

Vec2 List1;

for( int j = 0; j < 1000; j++ )
{	

	List1.Add(gcnew Vec1());

	for( int i = 0; i < 1000; i++ )
	{
		List1[j]->Add("0");
	}

}

Jennifer84

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Sep 30th, 2008

Re: Vector Dimensions

I think you are after ...

C++ Syntax (Toggle Plain Text)
typedef List<String^> Vec1;
typedef List<Vec1^> Vec2;
 
Vec2 List1;
 
for( int j = 0; j < 1000; j++ )
{	
	List1.Add(gcnew Vec1());
 
	for( int i = 0; i < 1000; i++ )
	{
		List1[j]->Add("0");
	}
}
typedef List<String^> Vec1;
typedef List<Vec1^> Vec2;

Vec2 List1;

for( int j = 0; j < 1000; j++ )
{	
	List1.Add(gcnew Vec1());

	for( int i = 0; i < 1000; i++ )
	{
		List1[j]->Add("0");
	}
}

mitrmkar

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Sep 30th, 2008

Re: Vector Dimensions

Mitrmkar,

Thank you! Now it works...

Jennifer84

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Oct 2nd, 2008

Re: Vector Dimensions

When compiling the below code I will have a compileerror that says:
String3D : illegal use of this type as an expression
String2D : illegal use of this type as an expression
String1D : illegal use of this type as an expression

I wonder if I doing this correct when trying to iterate through all 3 Dimension with .Count ?

(Toggle Plain Text)

typedef List<String^> String1D;
typedef List<String1D^> String2D;
typedef List<String2D^> String3D;



	String3D Dimensions;	
	int count1 = 0;
	int count2 = -1;


for( int i = 0; i < 5; i++ )
{

	if( i == 0 )
	{
	          Dimensions.Add(gcnew String2D()); 
	}
	if( i >= 0 && i <= 4 )
	{
		count2 = count2 + 1;
		Dimensions[count1]->Add(gcnew String1D()); 
	}
	Dimensions[count1][count2]->Add("TextString");
} 


		
for(int h = 0; h < String3D.Count; ++h)
{
for(int j = 0; j < String2D.Count; ++j)
{
for(int k = 0; k < String1D.Count; ++k)
{
}}}

Last edited by Jennifer84; Oct 2nd, 2008 at 4:01 pm.

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Oct 2nd, 2008

Re: Vector Dimensions

I found out that "()" was needed. When iterating through the dimensions to show the "TextString" that was put into the List(Dimensions), only 1 MessageBox will appear.
As I have put "TextString" to 5 elements it should be 5 Times.

I am putting the string to these elements:
Dimensions[0][0][0];
Dimensions[0][1][0];
Dimensions[0][2][0];
Dimensions[0][3][0];
Dimensions[0][4][0];

(Toggle Plain Text)

typedef List<String^> String1D;
typedef List<String1D^> String2D;
typedef List<String2D^> String3D;



	String3D Dimensions;	
	int count1 = 0;
	int count2 = -1;


for( int i = 0; i < 5; i++ )
{

	if( i == 0 )
	{
	          Dimensions.Add(gcnew String2D()); 
	}
	if( i >= 0 && i <= 4 )
	{
		count2 = count2 + 1;
		Dimensions[count1]->Add(gcnew String1D()); 
	}
	Dimensions[count1][count2]->Add("TextString");
} 


		
for(int h = 0; h < String3D().Count + 1; ++h)
{
for(int j = 0; j < String2D().Count + 1; ++j)
{
for(int k = 0; k < String1D().Count + 1; ++k)
{

MessageBox::Show(Dimensions[h][j][k]);

}


}}

Last edited by Jennifer84; Oct 2nd, 2008 at 4:31 pm.

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Oct 2nd, 2008

Re: Vector Dimensions

What I try to find, is the equavilent to the vector ::iterator for the first code.
The first code iterates each Dimension from .begin() to the .end() and then continues
to next dimension for the 3 Dimensions.

C++ Syntax (Toggle Plain Text)
typedef std::vector<string> String1D;
typedef std::vector<String1D> String2D;
typedef std::vector<String2D> String3D;
 
String3D Dimensions;	
 
for (String3D::iterator i = Dimensions.begin(); i != Dimensions.end(); ++i) 
{
for (String2D::iterator j = i->begin(); j != i->end(); ++j)			
{
for (String1D::iterator k = j->begin(); k != j->end(); ++k)			
{}}}
typedef std::vector<string> String1D;
typedef std::vector<String1D> String2D;
typedef std::vector<String2D> String3D;

String3D Dimensions;	

for (String3D::iterator i = Dimensions.begin(); i != Dimensions.end(); ++i) 
{
for (String2D::iterator j = i->begin(); j != i->end(); ++j)			
{
for (String1D::iterator k = j->begin(); k != j->end(); ++k)			
{}}}

As all these Dimensions below for "List" have been ->Add and therefore have different many elements for each Dimension, I am looking for the same(equavilent) method to Iterate each Dimension to the end as the above approach for the std::vector.
Something might be missing in the below code.

C++ Syntax (Toggle Plain Text)
typedef List<String^> String1D;
typedef List<String1D^> String2D;
typedef List<String2D^> String3D;
 
String3D Dimensions;	
 
for(int i = 0; i < String3D().Count + 1; ++i)
{
for(int j = 0; j < String2D().Count + 1; ++j)
{
for(int k = 0; k < String1D().Count + 1; ++k)
{}}}
typedef List<String^> String1D;
typedef List<String1D^> String2D;
typedef List<String2D^> String3D;

String3D Dimensions;	

for(int i = 0; i < String3D().Count + 1; ++i)
{
for(int j = 0; j < String2D().Count + 1; ++j)
{
for(int k = 0; k < String1D().Count + 1; ++k)
{}}}

Last edited by Jennifer84; Oct 2nd, 2008 at 7:03 pm.

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Oct 3rd, 2008

Re: Vector Dimensions

In some way it is needed to refer to the previous vectordimension.
The problem is that I dont know how you refer to the previous dimension beginning and end and set this to some sort of an iterator as this is put ?

String2D::iterator j = i->begin(); j != i->end(); ++j

For the List, I cant find either a begin or end member or iterator.
The below code could be a step closer perheps.
Any idéas or tips would be of help. I am quite stuck.

C++ Syntax (Toggle Plain Text)
for(int i = 0; i < Dimensions.Count; ++i)
{
for(int j = 0; j < String3D().Count; ++j)
{
for(int k = 0; k < String2D().Count; ++k)
{	
}}}
for(int i = 0; i < Dimensions.Count; ++i)
{
for(int j = 0; j < String3D().Count; ++j)
{
for(int k = 0; k < String2D().Count; ++k)
{	
}}}

Last edited by Jennifer84; Oct 3rd, 2008 at 9:40 am.

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Oct 3rd, 2008

Re: Vector Dimensions

About this thread starting question: look at my posts in solved threads (two month ago):
http://www.daniweb.com/forums/thread136351.html
http://www.daniweb.com/forums/thread137814.html

Last edited by ArkM; Oct 3rd, 2008 at 12:44 pm.

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Oct 3rd, 2008

Re: Vector Dimensions

Yes, this was the thread I was reading on but I missed it and as I saw it was as simple as this. I was imagining me something different.
It helped alot. Great !

C++ Syntax (Toggle Plain Text)
for(int i = 0; i < Dimensions.Count; ++i)
{
for(int j = 0; j < Dimensions[i]->Count; ++j)
{
for(int k = 0; k < Dimensions[i][j]->Count; ++k)
{
 
	MessageBox::Show(Dimensions[i][j][k]);
 
}
 
 
}
}
for(int i = 0; i < Dimensions.Count; ++i)
{
for(int j = 0; j < Dimensions[i]->Count; ++j)
{
for(int k = 0; k < Dimensions[i][j]->Count; ++k)
{
	
	MessageBox::Show(Dimensions[i][j][k]);

}


}
}

Click to Expand / Collapse Quote originally posted by ArkM ...

About this thread starting question: look at my posts in solved threads (two month ago):
http://www.daniweb.com/forums/thread136351.html
http://www.daniweb.com/forums/thread137814.html

Last edited by Jennifer84; Oct 3rd, 2008 at 1:44 pm.

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