Hello DaniWeb members,
I need some help with a program I made that I couldn't figure out the logic to complete
the program should make 5 random numbers between "1 and 55" and those five numbers should:
*Have two or three even numbers (%66 even or %66 odd)
*Have two or three numbers higher than 28.
*the sum of all five numbers should be between 106 and 179
*Choose one two numbers from the same level "and not choose two levels "total of level chosen 4"
Level 1 1 : 9
Level 2 10: 19
Level 3 20: 29
Level 4 30: 39
Level 5 40: 49
Level 6 50: 55
I did make the program work where it should all the results, but couldn't figure how I could force the program to do the outputs I'm looking for.
here is a sample of the output I'm looking for
http://img511.imageshack.us/img511/7...eenshotoo6.png
any ideas?
thanks
Hassan
// PROJECT1.cpp : Defines the entry point for the console application.
//
#include "stdafx.h"
int q,r,s,t,u,v, w, x, y, z, pb;
int evens (int),highs (int);
int sum_evens=0, sum_highs=0,sumintegers=0, sum_level1=0,sum_level2=0,sum_level3=0,sum_level4=0,sum_level5=0,sum_level6=0;
int level1 (int), level2 (int), level3 (int), level4 (int), level5 (int), level6 (int);
int main()
{
// 1- Making Five Random Numbers
int random_integer[5];
srand((unsigned)time(NULL));
for (int i = 0; i <5; i++)
{
random_integer[i] = 1+ rand() % 55;
}
//2- Organizing the numbers from small to large
for (int i = 1; i < 5; i++)
{
int currentElement = random_integer[i];
int k;
for (k= i-1; k >=0 && random_integer[k] > currentElement; k--)
{
random_integer[k+1] = random_integer[k];
}
random_integer[k+1]=currentElement;
}
//3- Having three or two even numbers
for (int i = 0; i < 5; i++)
{
z= evens (random_integer[i]);
sum_evens=sum_evens + z;
}
cout << "sum_evens : " << sum_evens << "\n"; // need to be forced to be two or three
//4- Having two or three high/low numbers
for (int i = 0; i < 5; i++)
{
w= highs (random_integer[i]);
sum_highs=sum_highs + w;
}
cout << "sum_highs : " << sum_highs << "\n"; // need to be forced to be two or three
//5- Having two numbers from the same level .. and skip two levels
//level1
for (int i = 0; i < 5; i++)
{
v= level1 (random_integer[i]);
sum_level1=sum_level1 + v;
u= level2 (random_integer[i]);
sum_level2=sum_level2 + u;
t= level3 (random_integer[i]);
sum_level3=sum_level3 + t;
s= level4 (random_integer[i]);
sum_level4=sum_level4 + s;
r= level5 (random_integer[i]);
sum_level5=sum_level5 + r;
q= level6 (random_integer[i]);
sum_level6=sum_level6 + q;
}
cout << "sum_level1 : " << sum_level1 << "\n"; // need to be forced to be two or three
cout << "sum_level2 : " << sum_level2 << "\n";
cout << "sum_level3 : " << sum_level3 << "\n";
cout << "sum_level4 : " << sum_level4 << "\n";
cout << "sum_level5 : " << sum_level5 << "\n";
cout << "sum_level6 : " << sum_level6 << "\n";
//6- Having the Sum of all integers
for (int i = 0; i < 5; i++)
{
sumintegers= random_integer[i] + sumintegers;
}
cout << "sumintegers : " << sumintegers << "\n";
//7-powerball number
pb = 1+ rand() % 44;
//8-Output the results
for (int i = 0; i <5; i++)
{
cout << random_integer[i] << " - ";
}
cout << "pb " << pb << "\n" ;
} 
Unsolved 
