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C++ Discussion Thread
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Nov 18th, 2008

char arrays and strcpy trouble

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Hi,

the following code works fine, that is, strcpy effectively copies the whole string on temporal to word.

cpp Syntax (Toggle Plain Text)
char word[20];
char temp[ ] = "hola";
cout << temporal << endl;
strcpy(word, temporal);
cout << word << endl;
char word[20];
char temp[ ] = "hola";
cout << temporal << endl;
strcpy(word, temporal);
cout << word << endl;

However, if I try to use the heap to store the "word" array then I'm in trouble and I get copied only the first character.

cpp Syntax (Toggle Plain Text)
char * word = new char [20];
char temporal[ ] = "hola";
strcpy(word, temporal);
cout << word << endl; // it only prints h
char * word = new char [20];
char temporal[ ] = "hola";
strcpy(word, temporal);
cout << word << endl; // it only prints h

The question is what am I doing wrong? Is there a function to do that or do I have to write my own function? There is probably something I don't quite understand about strings but don't know what it is.
Please, any help is appreciated

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freelancelote

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Junior Poster in Training

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Nov 18th, 2008

Re: char arrays and strcpy trouble

strange,

C++ Syntax (Toggle Plain Text)
#include <iostream>
 
using std::cout;
using std::endl;
 
int main(void) {
	char * word = new char [20];
	char temporal[ ] = "hola";
	strcpy(word, temporal);
	cout << word << endl;
	return 0;
}
#include <iostream>

using std::cout;
using std::endl;

int main(void) {
	char * word = new char [20];
	char temporal[ ] = "hola";
	strcpy(word, temporal);
	cout << word << endl;
	return 0;
}

works perfectly for me

mrboolf

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Nov 18th, 2008

Re: char arrays and strcpy trouble

Mhhh!

yeah, very strange.
It turns out it works for me now too...

Thanks

freelancelote

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