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C++ Discussion Thread
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Nov 22nd, 2008

Parsing error

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Hi all,
I used a function called GetRandomVariable to return a double data type and here's its code:

C++ Syntax (Toggle Plain Text)
double GetRandomNumber(void)
{
    // Zi = (AZi-1 + C)(mod m)
    // Zi = (5Zi-1 + 3)(mod 16)
    RandomVariableGenerator::Znode = (double)((5.0*RandomVariableGenerator::Znode + 3) % 16);
    return RandomVariableGenerator::Znode/16;
}
 static double Znode = 7.0;
double GetRandomNumber(void)
{
    // Zi = (AZi-1 + C)(mod m)
    // Zi = (5Zi-1 + 3)(mod 16)
    RandomVariableGenerator::Znode = (double)((5.0*RandomVariableGenerator::Znode + 3) % 16);
    return RandomVariableGenerator::Znode/16;
}
 static double Znode = 7.0;

but unfortunately i got the following error:

Error 1 error C2296: '%' : illegal, left operand has type 'double'

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Fouly

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Nov 22nd, 2008

Re: Parsing error

double doesn't support the Modulus operator, you will have to implement it yourself if you want to do this.

Last edited by William Hemsworth; Nov 22nd, 2008 at 8:20 am.

William Hemsworth

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Nov 22nd, 2008

Re: Parsing error

There is hope!

Use fmod to resolve the modulus between two doubles

c++ Syntax (Toggle Plain Text)
 
#include <iostream>
 
using std::cin;
using std::cout;
using std::endl;
 
int main(){
 
    double x = fmod(4.5, 3.22);
    cout << x << endl; // 1 R 1.28, so 1.28 should print out
    cin.get();
    return 0;
}
#include <iostream>

using std::cin;
using std::cout;
using std::endl;

int main(){

    double x = fmod(4.5, 3.22);
    cout << x << endl; // 1 R 1.28, so 1.28 should print out
    cin.get();
    return 0;
}

Alex Edwards

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Nov 22nd, 2008

Re: Parsing error

Yes it works...i used the fmod function instead of implementing it by my self. thanks a lot Alex & William

Fouly

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