If I add default arguments to the end of my copy constructor, is it still considered a copy constructor? E.g. will it still be used in the places where a copy constructor would normally be used (or automatically generated).
I can verify that it works on one compiler (g++). That is, this does output the "copy ctor" message 3 times:
#include <iostream>
class Context
{
// real thing actually has some methods
};
class A
{
private:
Context & m_context;
public:
A ( Context * context )
:m_context ( MATT_DEREF ( context ) )
{
// probably do something with context here..
}
A ( const A & a, Context * new_context = 0 )
:m_context ( new_context ? *new_context : a.m_context )
{
std::cout << "copy ctor\n";
// probably do something with context here..
}
};
void test ( A a )
{ return; }
int main ( void )
{
Context c1, c2;
A a1 ( &c1 );
// implictly copying by passing as value
test ( a1 );
// explicitly copying in the same context
A a2 ( a1 );
// copying to a new context
A a3 ( a1, &c2 );
return EXIT_SUCCESS;
}
But, will this always work O.K.? are there any caveats/pitfalls etc?
Other alternatives considered:
- I can't have the generated copy ctor used, for various reasons (e.g. other pointers/reference members shouldn't be shallow copied ).
- I don't want to pass the pointer to "context" in later, because that makes other areas unpleasant. E.g. I need to use "context" in the constructor, and it's not meant to be trivially reseatable.
- I do want the rest of the copy constructors features (i.e. being able to initialize the object & its bases in order).
- I'd rather not have to write 3 constructors for every class like this.
Marked 
