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Jan 24th, 2009

Open variable named files

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hello,,

i need help on how to open files by using variable names..

here's my function:

Quote ...

(Toggle Plain Text)
void stringSearcher(string filename, string search)
{
	ifstream file;
	file.open(filename);
	if(!file.is_open())
	{
		cerr<<"File can't be open..."<<endl;
		exit(1);
	}
	string line;

	while(!file.eof())
	{
		getline(file, line);
		if(line.find(search)==0)
		{
			displayTitle(line);
			exit(1);
		}
	}
}
void stringSearcher(string filename, string search) { ifstream file; file.open(filename); if(!file.is_open()) { cerr<<"File can't be open..."<<endl; exit(1); } string line; while(!file.eof()) { getline(file, line); if(line.find(search)==0) { displayTitle(line); exit(1); } } }

my problem is that there's always an error on the file.open line...
"no matching function to call...etc"

this is where i call the function in my main:

Quote ...

(Toggle Plain Text)
while (pent=readdir(pdir))
    {
        if (checkXML(pent->d_name))
        {
             list.push_back(pent->d_name);
	     string title("<TITLE>");
	     stringSearcher(pent->d_name, title);
        }
    }
while (pent=readdir(pdir)) { if (checkXML(pent->d_name)) { list.push_back(pent->d_name); string title("<TITLE>"); stringSearcher(pent->d_name, title); } }

sorry if you don't understand it,,

thx for helps... i need this asap btw,,

Last edited by azwraith69; Jan 24th, 2009 at 10:47 pm.

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azwraith69

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Jan 24th, 2009

Re: Open variable named files

When you see it say that there's "no matching function", that means there's no function with the given name that expects the types you've provided. If you double-check the documentation for ifstream's open function, you'll see that it takes a char*, not a string.

So use the .c_str() member function to get a char*.

Rashakil Fol

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Jan 24th, 2009

Re: Open variable named files

Click to Expand / Collapse Quote originally posted by Rashakil Fol ...

When you see it say that there's "no matching function", that means there's no function with the given name that expects the types you've provided. If you double-check the documentation for ifstream's open function, you'll see that it takes a char*, not a string.

So use the .c_str() member function to get a char*.

thx,, for quick reply,,

i have just did that..

now,, there's no more errors,,

but the problem is,, File can't be open...

Quote ...

(Toggle Plain Text)
void stringSearcher(string filename, string search)
{
	ifstream file;
	ifstream openfile(filename.c_str());
	if(!file.is_open())
	{
		cerr<<"File can't be open..."<<endl;
		exit(1);
	}

	string line;
	while(!file.eof())
	{
		getline(file, line);
		if(line.find(search)==0)
		{
			displayTitle(line);
			exit(1);
		}
	}
}
void stringSearcher(string filename, string search) { ifstream file; ifstream openfile(filename.c_str()); if(!file.is_open()) { cerr<<"File can't be open..."<<endl; exit(1); } string line; while(!file.eof()) { getline(file, line); if(line.find(search)==0) { displayTitle(line); exit(1); } } }

when i cout the filename,, it is right,, for example -> "file.xml"
and it is in the same directory with my source codes..
but it can't be open using .c_str()..

if i use file.open("file.xml"),, it opens properly....

what's the problem??

thx again,,

azwraith69

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since Jul 2008

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Jan 25th, 2009

Re: Open variable named files

sorry for double post...

i have already fixed my problem... just overlooked something..

thx for the help again..

azwraith69

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