Passing a filename to a function

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Hi, I have been trying for several hours without success to write a function that takes a filename, opens the corresponding file, populates a std::vector<double> with values from the file, and returns the std::vector<double>. I can't get past the passing the filename stage unfortunately, despite reading about this here there and everywhere online.

Could anybody give me a clue how to do this please?

Thanks!

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adarrell

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Jan 30th, 2009

Re: Passing a filename to a function

You can do this by passing a pointer to char or a string.

C++ Syntax (Toggle Plain Text)
#include <string>
void yourFunction(const char * filename); //we don't want to modify so it's const
void yourFunction(string filename);
#include <string>
void yourFunction(const char * filename); //we don't want to modify so it's const
void yourFunction(string filename);

venomxxl

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Jan 30th, 2009

Re: Passing a filename to a function

Also, if you're using std::strings for a filename you'll have to convert them to const char* for ifstream. The c_str() function will do that for you:

C++ Syntax (Toggle Plain Text)
    std::string filename = "my_file.txt";
    std::ifstream infile(filename.c_str());
    std::string filename = "my_file.txt";
    std::ifstream infile(filename.c_str());

Nick Evan

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