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C++ Discussion Thread
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Jan 20th, 2005

redundant variables

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take a look at this code:

---
void redundant_var()
{
char user_name[]="";
cout<<"insert name: "; cin>>user_name;
swap_name(user_name); //another function not seen
}
---

now, the following code works fine, but i am SURE there is a away to pass in user_name without the need of storing it in a temporary variable.

cannt you pass the CONSOLE_INPUT straight into the function?

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3246251196

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Newbie Poster

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Jan 20th, 2005

Re: redundant variables

>cannt you pass the CONSOLE_INPUT straight into the function?
Not the way you want to do it, no.

Narue

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Jan 20th, 2005

Re: redundant variables

cin returns itself, not the thing(s) it reads from the input.

jwenting

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duckman

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Jan 20th, 2005

Re: redundant variables

Quote ...

cannt you pass the CONSOLE_INPUT straight into the function?

Why do you WANT to do that.....?

If anything what is wrong with...

C++ Syntax (Toggle Plain Text)
function(cin.getline(...));
function(cin.getline(...));

...will grab the input and pass it to the function.

1o0oBhP

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Posting Pro in Training

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Jan 20th, 2005

Re: redundant variables

>...will grab the input and pass it to the function.
Be more specific or I'll have to describe in detail why you're wrong. Since you've proven yourself to know C++ fairly well, I'll give you the benefit of the doubt and assume that you just worded your post poorly.

Narue

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Jan 21st, 2005

Re: redundant variables

Quote originally posted by 1o0oBhP ...

Why do you WANT to do that.....?

If anything what is wrong with...
C++ Syntax (Toggle Plain Text)
function(cin.getline(...));
function(cin.getline(...));
...will grab the input and pass it to the function.

ok thats excellent:

"swap_name(cin.getline());"

or does something have to go int the parenthesis (which i am confident does)

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