two dimensional matrix array problem

[shamila08]

hello, dear all. below is my program code. the problem is an half of my output is zero for entries of matrix for n greater than 4.

#include    <stdio.h>
#include    <stdlib.h>
#include <iostream>
#define     MAX 100
int       num[MAX][MAX];
int         n; 
int nrows = 0;
using namespace std;

void print(int i )
{ 
  if (i > 0) {
	
  for (int j = 1; j <=n; j++) 
	    //cout << num[i][j];
	cout << "num["<<i<<"]["<<j<<"]=" <<num[i][j] << endl; 
  cout <<"\n";
  }
}
void rightRotate ( int n)
{int  tmp; 
for(int k = 1; k<n; ++k)
for(int l = 1; l<=n; ++l)
{
	//cout << "l:"<< l << "\n"; 
tmp = num[l][k];
	num[l][k]= num[l][k+1];
	num[l][k+1] = tmp;}
}

void matrixPermute (int n)
{
    int     i, temp;
   if  (n ==3 ) 
      {nrows ++;
	   print(nrows);
       return;
     }
    temp = n-1 ;
	cout << "temp:"<< temp<<"\n";
    for (i = 1; i <=temp ; ++i) 
        {
//cout << "i:" << i << "\n";
		matrixPermute (temp);
rightRotate (temp);
        } 
}
void initiate(int n)
{
  for (int i = 1; i <= n; ++i) 
 for (int j = 1; j <= n; ++j) 
  {  
    num[i][j] = j;
  }
} 

int main ()
{
        cout << "number must be between 3 and 10 \n";
        cin >> n;
		cout  << endl;
	initiate(n);
    matrixPermute (n);
cout << "nrows=" <<nrows << "\n";
}

its cant read the following code that i set it up

void matrixPermute (int n)
{
    int     i, temp;
   if  (n ==3 ) 
      {nrows ++;
	   print(nrows);
       return;
     }

[arghasen]

can u be a bit more specific

[siddhant3s]

What are you trying to accomplish?
Can you be more descriptive?

[shamila08]

let me show the output
number must be between 3 and 10:
5
....
......
num[5][1]=1
num[5][2]=2
num[5][3]=3
num[5][4]=4
num[5][5]=5

num[6][1]=0
num[6][2]=0
num[6][3]=0
num[6][4]=0
num[6][5]=0

temp:3
num[7][1]=0
num[7][2]=0
num[7][3]=0
num[7][4]=0
num[7][5]=0

num[8][1]=0
num[8][2]=0
num[8][3]=0
num[8][4]=0
num[8][5]=0

num[9][1]=0
num[9][2]=0
num[9][3]=0
num[9][4]=0
num[9][5]=0

temp:3
num[10][1]=0
num[10][2]=0
num[10][3]=0
num[10][4]=0
num[10][5]=0

num[11][1]=0
num[11][2]=0
num[11][3]=0
num[11][4]=0
num[11][5]=0

num[12][1]=0
num[12][2]=0
num[12][3]=0
num[12][4]=0
num[12][5]=0

nrows=12
Press any key to continue . . .

the problem is when nrows = 6 until 12, the related elements is zero. something is not corresponds to the nrows.

[shamila08]

when i remove try did not use nrows such as follows:

void print()
{ 
  if (num != 0) {
	 int i=1;
  for (int j = 1; j <=n; j++) 
	    cout << num[i][j];
//	cout << "num["<<i<<"]["<<j<<"]=" <<num[i][j] << endl; 
  cout <<"\n";
  }
}

and

void matrixPermute (int n)
{
    int     i, temp;
   if  (n ==3 ) 
      { nrows++;
	   print();
       return;
     }

this is the output

number must be between 3 and 10
5

temp:4
temp:3
12345
23145
31245
temp:3
23415
34215
42315
temp:3
34125
41325
13425
temp:3
41235
12435
24135
nrows=12
Press any key to continue . . .

however i need to represent the output in matrix form. i couldnt make it. i need the index 'i' will follows nrows index.

[Ancient Dragon]

line 50 and 51: array numbers always begin with 0, not 1.

for(int i = 0; i < n; i++)
{
    for(int j = 0; j < n; j++)
    {
          num[i][j] = j+1;
   }
}

line 44: >>matrixPermute (temp);
This is a recursive function call, yet you always are passing the same value of temp which never changes in that loop. It looks like that function will be an infinite recursion, which will eventually crash and burn the program.

[shamila08]

thanks....
yup that's recursive function. the index 'temp', we can change it where i use code as follows:

if  (n ==2 ) 
      { nrows++;
	   print();
       return;
     }

or we can set up

if  (n ==1 ) 
      { nrows++;
	   print();
       return;
     }

regarding to my last previous post is i have to represent the output in matrix form correspond to nrows index.
when n = 4, there is no problem. however problem arises when n>4..
is it possible or i have to rewrite the program without 'temp'?

[shamila08]

ok. i start index with '0' not '1'.

#include    <stdio.h>
#include    <stdlib.h>
#include <iostream>
#define     MAX 100
int       num[MAX][MAX];
int         n; 
int nrows = 0;
using namespace std;

void print(int i)
{ 
  if (num != 0) {
	  for (int j = 0; j <n; j++) 
	 //  cout << num[0][j];
	cout << "num["<<i<<"]["<<j<<"]=" <<num[i][j] << endl; 
  cout <<"\n";
  }
}
void rightRotate ( int n)
{int  tmp; 
for(int k = 0; k<n-1; ++k)
for(int l = 0; l<n; ++l)
{
	//cout << "l:"<< l << "\n"; 
tmp = num[l][k];
	num[l][k]= num[l][k+1];
	num[l][k+1] = tmp;}
}

void matrixPermute (int n)
{
    int     i, temp;
   if  (n ==3 ) 
      { nrows++;
	   print(nrows);
       return;
     }
    temp = n-1 ;
	cout << "temp:"<< temp<<"\n";
    for (i = 0; i <temp ; ++i) 
        {
//cout << "i:" << i << "\n";
		matrixPermute (temp);
rightRotate (temp);
        } 
}
void initiate(int n)
{
  for (int i = 0; i < n; ++i) 
 for (int j = 0; j < n; ++j) 
  {  
    num[i][j] = j+1;
  }
} 

int main ()
{
        cout << "number must be between 3 and 10 \n";
        cin >> n;
		cout  << endl;
	initiate(n);
    matrixPermute (n);
cout << "nrows=" <<nrows << "\n";
}

its also obtained the same output. i understand because it related to 'temp'.

the meaning of the temp is follows:
n = 4
when temp =3,
it will right rotate the first three element such as follows:
1234
2314
3124..........

for n = 5:
when temp 4, it will rotate the first 4 element:
12345 ( the list is not appear).
23415
34125
41235
the continue temp = 3: ( that's the last output)
12345
23145
31245
12345