Problem with "\n"

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Hi All,
I am facing a problem with new line character (\n). When I am initializing a string variable with a string having a new line character, e.g.,

C++ Syntax (Toggle Plain Text)
char str[20] = “Programming is \nfun�?;
cout << str;
char str[20] = “Programming is \nfun�?;
cout << str;

It is printing:
Programming is
fun

But on the other hand when I am taking the same string as an input and trying to print it, i.e.,

C++ Syntax (Toggle Plain Text)
char str[20];
cin >> str;
cout << str;
char str[20];
cin >> str;
cout << str;

Input:
Programming is \nfun
It is printing:
Programming is \nfun

Can any one solve this problem?
Thanks,
Amit

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amt_muk

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Light Poster

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since May 2005

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Jun 7th, 2005

Re: Problem with "\n"

one of the way is cin.getline but you must specify the delimiter (maybe '.')

C++ Syntax (Toggle Plain Text)
#include <iostream.h>
void main()
{
	char str[20];
	cin.getline(str, 20, '.');
	cout << str << endl;
 
 
}
#include <iostream.h>
void main()
{
	char str[20];
	cin.getline(str, 20, '.');
	cout << str << endl;


}

andor

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Posting Whiz in Training

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Jun 7th, 2005

Re: Problem with "\n"

In source code, the sequence \n means a newline -- the compiler does the translation. In an interactive program, the sequence \n means the character \ followed by the character n. Hitting the enter key in an interactive program puts the newline character in the input stream. Some of the input functions are delimited by whitespace, and a newline is whitespace, so using them may ignore the newline.

Dave Sinkula

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long time no c

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