Hello--
I've been writing some code in C++ to test the
tffs-lib library, which is written in C. The library provides functions for directly accessing a FAT file system from within a program. Although most modern operating systems have drivers for accessing the FAT filesystem on SD cards, I am working with an embedded Linux system, and I would like to directly access the FAT filesystem using a device node (/dev/mmcblk1p1) to speed up write I/O access.
I am able to build the
tffs-lib and statically link it with my test program. My cross-compiler build is based on gcc 4.2.2.
However, I receive the following error when compiling the code. This error mentions an "anonymous struct," which I believe is not legal in C++.
request for member 'fatsz' in 'htffs', which is of non-class type '<anonymous struct>*' test.cpp test-tffs-lib
Is it possible to use an anonymous struct in C++, even when the anonymous struct is being used within a C library? I tried passing the command-line switch "-features=extensions" to gcc, but (strangely enough) this results in no executable being created. However, after passing this switch, there is no warning generated, and the code compiles cleanly (without the output executable being created.)
Here is the code of my very simple test program in C++. The error occurs on line 32 below.
#include <iostream>
#include <string>
// TFFS library include (for C code)
extern "C" {
#include <tffs.h>
}
void doTest();
int main()
{
doTest();
return 0;
}
void doTest()
{
int32_t ret;
std::string sd_dev = "/dev/mmcblk1p1";
tffs_handle_t htffs;
// mount the filesystem directory
ret = TFFS_mount((byte*)sd_dev.c_str(), &htffs);
if(ret != TFFS_OK)
exit(1);
// check the space available on the medium
// This is the line of code where the error occurs
uint32_t fatsz = htffs.fatsz;
std::cout << "fatsz = " << fatsz << std::endl;
// unmount the filesystem directory
ret = TFFS_umount(htffs);
if(ret != TFFS_OK)
exit(1);
}
Marked 
