linked list: Search, Remove

[MugANDGlass]

void search()
{
char id[12];
node *p = head;
system("cls");
{
	cout<<"Search ID: ";
	cin>>id;

}
	while ((p!=NULL) && (strcmp(id,p->id)!=0))

	{
		p = p->next;

	}
	
	if(p==NULL)

	{
		cout<<"No such ID in our list"<<endl;
		delete p;

	}
	
	else

		cout<<"We have this ID in our list"<<endl;
		
}


void remove()
{
char id[12];
node *newptr;
node *q = NULL;
node *p = head;

	cout<<" Delete ID: "; 
	cin>>id;
        cout<<"Title 	:"<<p->name_1<<endl;

	while ((p!=NULL) && (strcmp(id,p->id)!=0))
		{
			q = p;
			p = p->next;
		}
		
	if(q==NULL) 
		{
			head = head->next;
			delete p;
		}
		
	else if (p==NULL)
		{
			cout<<"No such ID in list"<<endl;
		}
		
	else 
		{
			q->next=p->next;
			delete p;
		}
}

*** I got problem when I try to search ID that doesnt exist in the list. The program will display this, 'No such ID in our list' but then it will debug after that.
*** When I try to enter ID that doesnt exist in the list, the delete function will display the input that had been entered and display, 'No such ID in list'.
eg; Title: alice in wonderland
No such ID in list
I want the delete function only display this, 'No such ID in list'.
Anyone can explain why this problem occur? Thanks.

[v3ga]

Its the remove() function, not delete.
Your question is not clear to me but I think this is what you want..
The problem is line 42. Check before printing.

if(p!=NULL)
cout<<"Title 	:"<<p->name_1<<endl;

[v3ga]

Why don't you Make search() function return a value and check using it in the remove() function.