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Mar 20th, 2006

Class with dynamic array how?

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I am new in programming and my problem is probably notorious but still is a problem.
I want build class which can produce object which contain two dimensional dynamic array and member function which fill that array.
Question is where I should to create the array, in function or in constructor.
Cod of array is:

int sizeP, stupaca;

char **polje; //dinamicka alokacija polja s pozivacem na pokazivac

polje = new char*[sizeP];

for (int i = 0; i < sizeP; i++) 

{

polje[i] = new char[stupaca + 1];

polje[i][0] = stupaca;

for (int j = 1; j <= stupaca; j++)

polje[i][j] = i + 1 + j / 100.; 

}

2. question: do I need copy constructor? Probably yes, but I don’t know create it.
3.Can I delete the array in destructor with following cod:



for (int i = 0; i < sizeP; i++)

delete [] polje[i];

delete [] polje;

Thenx

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marioxp

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Mar 21st, 2006

Re: Class with dynamic array how?

Well, when someone says dynamic array my knee jerk reaction would be use <vector> from the STL. However, I'm not too sure about 2d vectors although I guess its inherent structure would probably be the same.

If you're intent is to build this from scratch for fun then go for it, although you probably haven't found my reply useful.

hmmm

iamthwee

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Mar 21st, 2006

Re: Class with dynamic array how?

i hope this can help u a little....

C++ Syntax (Toggle Plain Text)
#include<iostream>
using namespace std ;
 
class DynamecArray2D ;
class DynamecArray2D {
	char **pArray ;
public:
	DynamecArray2D() ;
	DynamecArray2D(int iRow, int iColumn) ;
	DynamecArray2D(DynamecArray2D &) ;  //copy constructor
	~DynamecArray2D() ;
};
DynamecArray2D::DynamecArray2D() {
	pArray = NULL;
}
DynamecArray2D::DynamecArray2D(int iRow, int iColumn)  {
	pArray = new char*[iRow] ;
	for(int i=0; i<iRow; ++i) {
		pArray[i] = new char[iColumn] ;
		pArray[i][iColumn-1] = NULL ;
	}
}
DynamecArray2D::DynamecArray2D(DynamecArray2D &objDynamecArray2D) {  //copy constructor
	char **p=NULL;
	int i=0,j=0,iColumn;
	p=objDynamecArray2D.pArray ;
	while(*(p+i)) {
		++i;
	}
	pArray = new char*[i] ;
	iColumn = strlen(objDynamecArray2D.pArray[0]) ;
	for(j=0; j<i; ++j) {
		pArray[j] = new char[iColumn+1] ;
		pArray[j][iColumn-1] = NULL ;
	}
	i=0;
	p=objDynamecArray2D.pArray ;
	while(*(p+i)) {
		strcpy(*(pArray+i),*(p+i));
		++i;
	}
}
DynamecArray2D::~DynamecArray2D() {
	int i=0;
	while(pArray[i]) {
		if(pArray[i]) {
			delete pArray[i] ;
		}
		++i;
	}
	if(pArray){
		delete []pArray ;
	}
}
#include<iostream>
using namespace std ;

class DynamecArray2D ;
class DynamecArray2D {
	char **pArray ;
public:
	DynamecArray2D() ;
	DynamecArray2D(int iRow, int iColumn) ;
	DynamecArray2D(DynamecArray2D &) ;  //copy constructor
	~DynamecArray2D() ;
};
DynamecArray2D::DynamecArray2D() {
	pArray = NULL;
}
DynamecArray2D::DynamecArray2D(int iRow, int iColumn)  {
	pArray = new char*[iRow] ;
	for(int i=0; i<iRow; ++i) {
		pArray[i] = new char[iColumn] ;
		pArray[i][iColumn-1] = NULL ;
	}
}
DynamecArray2D::DynamecArray2D(DynamecArray2D &objDynamecArray2D) {  //copy constructor
	char **p=NULL;
	int i=0,j=0,iColumn;
	p=objDynamecArray2D.pArray ;
	while(*(p+i)) {
		++i;
	}
	pArray = new char*[i] ;
	iColumn = strlen(objDynamecArray2D.pArray[0]) ;
	for(j=0; j<i; ++j) {
		pArray[j] = new char[iColumn+1] ;
		pArray[j][iColumn-1] = NULL ;
	}
	i=0;
	p=objDynamecArray2D.pArray ;
	while(*(p+i)) {
		strcpy(*(pArray+i),*(p+i));
		++i;
	}
}
DynamecArray2D::~DynamecArray2D() {
	int i=0;
	while(pArray[i]) {
		if(pArray[i]) {
			delete pArray[i] ;
		}
		++i;
	}
	if(pArray){
		delete []pArray ;
	}
}

dubeyprateek

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Mar 21st, 2006

Re: Class with dynamic array how?

>I'm not too sure about 2d vectors although I guess its inherent structure would probably be the same.

C++ Syntax (Toggle Plain Text)

std::vector<std::vector<T> > matrix;

std::vector is designed to work the way people expect even in multiple dimensions.

Narue

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Mar 21st, 2006

Re: Class with dynamic array how?

Thank you I’ll try with that. I think this is it!

I don't use this for vectors I’m trying create from one big string many small strings, and place it in array.

marioxp

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Mar 21st, 2006

Re: Class with dynamic array how?

>std::vector<std::vector<T> > matrix;

Thanx _jsw, I was wondering that but I didn't know 4 sure. Do you have an example...

>I don't use this for vectors I’m trying create from one big string many small strings, and place it in array.

Well unless, you just missed the above, you can use a 2D vector to do exactly that. Unless, like I said before ,you're just doing that for fun, practise or just to complicate matters?

iamthwee

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Mar 22nd, 2006

Re: Class with dynamic array how?

>Do you have an example...

C++ Syntax (Toggle Plain Text)
#include <iostream>
#include <vector>
 
int main()
{
  typedef std::vector<std::vector<int> > mat_t;
 
  mat_t mat ( 10, std::vector<int> ( 10, 0 ) );
 
  for ( mat_t::size_type i = 0; i < mat.size(); i++ ) {
    for ( mat_t::size_type j = 0; j < mat[i].size(); j++ ) {
      if ( j % 2 != 0 )
        mat[i][j] = j;
    }
  }
 
  for ( mat_t::size_type i = 0; i < mat.size(); i++ ) {
    for ( mat_t::size_type j = 0; j < mat[i].size(); j++ )
      std::cout<< mat[i][j] <<' ';
    std::cout<<'\n';
  }
}
#include <iostream>
#include <vector>

int main()
{
  typedef std::vector<std::vector<int> > mat_t;

  mat_t mat ( 10, std::vector<int> ( 10, 0 ) );

  for ( mat_t::size_type i = 0; i < mat.size(); i++ ) {
    for ( mat_t::size_type j = 0; j < mat[i].size(); j++ ) {
      if ( j % 2 != 0 )
        mat[i][j] = j;
    }
  }

  for ( mat_t::size_type i = 0; i < mat.size(); i++ ) {
    for ( mat_t::size_type j = 0; j < mat[i].size(); j++ )
      std::cout<< mat[i][j] <<' ';
    std::cout<<'\n';
  }
}

Narue

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